:: YELLOW_3 semantic presentation  Show TPTP formulae Show IDV graph for whole article:: Showing IDV graph ... (Click the Palm Trees again to close it)

scheme :: YELLOW_3:sch 1
FraenkelA2{ F1() -> non empty set , F2( set , set ) -> set , P1[ set , set ], P2[ set , set ] } :
{ F2(s,t) where s, t is Element of F1() : P1[s,t] } is Subset of F1()
provided
A1: for s, t being Element of F1() holds F2(s,t) in F1()
proof end;

scheme :: YELLOW_3:sch 2
ExtensionalityR{ F1() -> Relation, F2() -> Relation, P1[ set , set ] } :
F1() = F2()
provided
A1: for a, b being set holds
( [a,b] in F1() iff P1[a,b] ) and
A2: for a, b being set holds
( [a,b] in F2() iff P1[a,b] )
proof end;

registration
let X be empty set ;
cluster proj1 X -> empty ;
coherence
proj1 X is empty
by FUNCT_5:10;
cluster proj2 X -> empty ;
coherence
proj2 X is empty
by FUNCT_5:10;
end;

registration
let X, Y be non empty set ;
let D be non empty Subset of [:X,Y:];
cluster proj1 D -> non empty ;
coherence
not proj1 D is empty
proof end;
cluster proj2 D -> non empty ;
coherence
not proj2 D is empty
proof end;
end;

registration
let L be RelStr ;
let X be empty Subset of L;
cluster downarrow X -> empty ;
coherence
downarrow X is empty
proof end;
cluster uparrow X -> empty ;
coherence
uparrow X is empty
proof end;
end;

theorem Th1: :: YELLOW_3:1  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being set
for D being Subset of [:X,Y:] holds D c= [:(proj1 D),(proj2 D):]
proof end;

Lm1: for x, a1, a2, b1, b2 being set st x = [[a1,a2],[b1,b2]] holds
( (x `1 ) `1 = a1 & (x `1 ) `2 = a2 & (x `2 ) `1 = b1 & (x `2 ) `2 = b2 )
proof end;

theorem :: YELLOW_3:2  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for L being transitive antisymmetric with_infima RelStr
for a, b, c, d being Element of L st a <= c & b <= d holds
a "/\" b <= c "/\" d
proof end;

theorem :: YELLOW_3:3  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for L being transitive antisymmetric with_suprema RelStr
for a, b, c, d being Element of L st a <= c & b <= d holds
a "\/" b <= c "\/" d
proof end;

theorem :: YELLOW_3:4  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for L being non empty reflexive antisymmetric complete RelStr
for D being Subset of L
for x being Element of L st x in D holds
(sup D) "/\" x = x
proof end;

theorem :: YELLOW_3:5  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for L being non empty reflexive antisymmetric complete RelStr
for D being Subset of L
for x being Element of L st x in D holds
(inf D) "\/" x = x
proof end;

theorem :: YELLOW_3:6  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for L being RelStr
for X, Y being Subset of L st X c= Y holds
downarrow X c= downarrow Y
proof end;

theorem :: YELLOW_3:7  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for L being RelStr
for X, Y being Subset of L st X c= Y holds
uparrow X c= uparrow Y
proof end;

theorem :: YELLOW_3:8  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S, T being with_infima Poset
for f being Function of S,T
for x, y being Element of S holds
( f preserves_inf_of {x,y} iff f . (x "/\" y) = (f . x) "/\" (f . y) )
proof end;

theorem :: YELLOW_3:9  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S, T being with_suprema Poset
for f being Function of S,T
for x, y being Element of S holds
( f preserves_sup_of {x,y} iff f . (x "\/" y) = (f . x) "\/" (f . y) )
proof end;

scheme :: YELLOW_3:sch 3
InfUnion{ F1() -> non empty antisymmetric complete RelStr , P1[ set ] } :
"/\" { ("/\" X,F1()) where X is Subset of F1() : P1[X] } ,F1() >= "/\" (union { X where X is Subset of F1() : P1[X] } ),F1()
proof end;

scheme :: YELLOW_3:sch 4
InfofInfs{ F1() -> complete LATTICE, P1[ set ] } :
"/\" { ("/\" X,F1()) where X is Subset of F1() : P1[X] } ,F1() = "/\" (union { X where X is Subset of F1() : P1[X] } ),F1()
proof end;

scheme :: YELLOW_3:sch 5
SupUnion{ F1() -> non empty antisymmetric complete RelStr , P1[ set ] } :
"\/" { ("\/" X,F1()) where X is Subset of F1() : P1[X] } ,F1() <= "\/" (union { X where X is Subset of F1() : P1[X] } ),F1()
proof end;

scheme :: YELLOW_3:sch 6
SupofSups{ F1() -> complete LATTICE, P1[ set ] } :
"\/" { ("\/" X,F1()) where X is Subset of F1() : P1[X] } ,F1() = "\/" (union { X where X is Subset of F1() : P1[X] } ),F1()
proof end;

definition
let P, R be Relation;
func ["P,R"] -> Relation means :Def1: :: YELLOW_3:def 1
for x, y being set holds
( [x,y] in it iff ex p, q, s, t being set st
( x = [p,q] & y = [s,t] & [p,s] in P & [q,t] in R ) );
existence
ex b1 being Relation st
for x, y being set holds
( [x,y] in b1 iff ex p, q, s, t being set st
( x = [p,q] & y = [s,t] & [p,s] in P & [q,t] in R ) )
proof end;
uniqueness
for b1, b2 being Relation st ( for x, y being set holds
( [x,y] in b1 iff ex p, q, s, t being set st
( x = [p,q] & y = [s,t] & [p,s] in P & [q,t] in R ) ) ) & ( for x, y being set holds
( [x,y] in b2 iff ex p, q, s, t being set st
( x = [p,q] & y = [s,t] & [p,s] in P & [q,t] in R ) ) ) holds
b1 = b2
proof end;
end;

:: deftheorem Def1 defines [" YELLOW_3:def 1 :
for P, R, b3 being Relation holds
( b3 = ["P,R"] iff for x, y being set holds
( [x,y] in b3 iff ex p, q, s, t being set st
( x = [p,q] & y = [s,t] & [p,s] in P & [q,t] in R ) ) );

theorem Th10: :: YELLOW_3:10  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for P, R being Relation
for x being set holds
( x in ["P,R"] iff ( [((x `1 ) `1 ),((x `2 ) `1 )] in P & [((x `1 ) `2 ),((x `2 ) `2 )] in R & ex a, b being set st x = [a,b] & ex c, d being set st x `1 = [c,d] & ex e, f being set st x `2 = [e,f] ) )
proof end;

definition
let A, B, X, Y be set ;
let P be Relation of A,B;
let R be Relation of X,Y;
:: original: ["
redefine func ["P,R"] -> Relation of [:A,X:],[:B,Y:];
coherence
["P,R"] is Relation of [:A,X:],[:B,Y:]
proof end;
end;

definition
let X, Y be RelStr ;
func [:X,Y:] -> strict RelStr means :Def2: :: YELLOW_3:def 2
( the carrier of it = [:the carrier of X,the carrier of Y:] & the InternalRel of it = ["the InternalRel of X,the InternalRel of Y"] );
existence
ex b1 being strict RelStr st
( the carrier of b1 = [:the carrier of X,the carrier of Y:] & the InternalRel of b1 = ["the InternalRel of X,the InternalRel of Y"] )
proof end;
uniqueness
for b1, b2 being strict RelStr st the carrier of b1 = [:the carrier of X,the carrier of Y:] & the InternalRel of b1 = ["the InternalRel of X,the InternalRel of Y"] & the carrier of b2 = [:the carrier of X,the carrier of Y:] & the InternalRel of b2 = ["the InternalRel of X,the InternalRel of Y"] holds
b1 = b2
;
end;

:: deftheorem Def2 defines [: YELLOW_3:def 2 :
for X, Y being RelStr
for b3 being strict RelStr holds
( b3 = [:X,Y:] iff ( the carrier of b3 = [:the carrier of X,the carrier of Y:] & the InternalRel of b3 = ["the InternalRel of X,the InternalRel of Y"] ) );

definition
let L1, L2 be RelStr ;
let D be Subset of [:L1,L2:];
:: original: proj1
redefine func proj1 D -> Subset of L1;
coherence
proj1 D is Subset of L1
proof end;
:: original: proj2
redefine func proj2 D -> Subset of L2;
coherence
proj2 D is Subset of L2
proof end;
end;

definition
let S1, S2 be RelStr ;
let D1 be Subset of S1;
let D2 be Subset of S2;
:: original: [:
redefine func [:D1,D2:] -> Subset of [:S1,S2:];
coherence
[:D1,D2:] is Subset of [:S1,S2:]
proof end;
end;

definition
let S1, S2 be non empty RelStr ;
let x be Element of S1;
let y be Element of S2;
:: original: [
redefine func [x,y] -> Element of [:S1,S2:];
coherence
[x,y] is Element of [:S1,S2:]
proof end;
end;

definition
let L1, L2 be non empty RelStr ;
let x be Element of [:L1,L2:];
:: original: `1
redefine func x `1 -> Element of L1;
coherence
x `1 is Element of L1
proof end;
:: original: `2
redefine func x `2 -> Element of L2;
coherence
x `2 is Element of L2
proof end;
end;

theorem Th11: :: YELLOW_3:11  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for a, c being Element of S1
for b, d being Element of S2 holds
( ( a <= c & b <= d ) iff [a,b] <= [c,d] )
proof end;

theorem Th12: :: YELLOW_3:12  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for x, y being Element of [:S1,S2:] holds
( x <= y iff ( x `1 <= y `1 & x `2 <= y `2 ) )
proof end;

theorem :: YELLOW_3:13  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A, B being RelStr
for C being non empty RelStr
for f, g being Function of [:A,B:],C st ( for x being Element of A
for y being Element of B holds f . [x,y] = g . [x,y] ) holds
f = g
proof end;

registration
let X, Y be non empty RelStr ;
cluster [:X,Y:] -> non empty strict ;
coherence
not [:X,Y:] is empty
proof end;
end;

registration
let X, Y be reflexive RelStr ;
cluster [:X,Y:] -> strict reflexive ;
coherence
[:X,Y:] is reflexive
proof end;
end;

registration
let X, Y be antisymmetric RelStr ;
cluster [:X,Y:] -> strict antisymmetric ;
coherence
[:X,Y:] is antisymmetric
proof end;
end;

registration
let X, Y be transitive RelStr ;
cluster [:X,Y:] -> strict transitive ;
coherence
[:X,Y:] is transitive
proof end;
end;

registration
let X, Y be with_suprema RelStr ;
cluster [:X,Y:] -> non empty strict with_suprema ;
coherence
[:X,Y:] is with_suprema
proof end;
end;

registration
let X, Y be with_infima RelStr ;
cluster [:X,Y:] -> non empty strict with_infima ;
coherence
[:X,Y:] is with_infima
proof end;
end;

theorem :: YELLOW_3:14  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being RelStr st not [:X,Y:] is empty holds
( not X is empty & not Y is empty )
proof end;

theorem :: YELLOW_3:15  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being non empty RelStr st [:X,Y:] is reflexive holds
( X is reflexive & Y is reflexive )
proof end;

theorem :: YELLOW_3:16  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being non empty reflexive RelStr st [:X,Y:] is antisymmetric holds
( X is antisymmetric & Y is antisymmetric )
proof end;

theorem :: YELLOW_3:17  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being non empty reflexive RelStr st [:X,Y:] is transitive holds
( X is transitive & Y is transitive )
proof end;

theorem :: YELLOW_3:18  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being non empty reflexive RelStr st [:X,Y:] is with_suprema holds
( X is with_suprema & Y is with_suprema )
proof end;

theorem :: YELLOW_3:19  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being non empty reflexive RelStr st [:X,Y:] is with_infima holds
( X is with_infima & Y is with_infima )
proof end;

definition
let S1, S2 be RelStr ;
let D1 be directed Subset of S1;
let D2 be directed Subset of S2;
:: original: [:
redefine func [:D1,D2:] -> directed Subset of [:S1,S2:];
coherence
[:D1,D2:] is directed Subset of [:S1,S2:]
proof end;
end;

theorem :: YELLOW_3:20  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2 st [:D1,D2:] is directed holds
( D1 is directed & D2 is directed )
proof end;

theorem Th21: :: YELLOW_3:21  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D being non empty Subset of [:S1,S2:] holds
( not proj1 D is empty & not proj2 D is empty )
proof end;

theorem :: YELLOW_3:22  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty reflexive RelStr
for D being non empty directed Subset of [:S1,S2:] holds
( proj1 D is directed & proj2 D is directed )
proof end;

definition
let S1, S2 be RelStr ;
let D1 be filtered Subset of S1;
let D2 be filtered Subset of S2;
:: original: [:
redefine func [:D1,D2:] -> filtered Subset of [:S1,S2:];
coherence
[:D1,D2:] is filtered Subset of [:S1,S2:]
proof end;
end;

theorem :: YELLOW_3:23  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2 st [:D1,D2:] is filtered holds
( D1 is filtered & D2 is filtered )
proof end;

theorem :: YELLOW_3:24  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty reflexive RelStr
for D being non empty filtered Subset of [:S1,S2:] holds
( proj1 D is filtered & proj2 D is filtered )
proof end;

definition
let S1, S2 be RelStr ;
let D1 be upper Subset of S1;
let D2 be upper Subset of S2;
:: original: [:
redefine func [:D1,D2:] -> upper Subset of [:S1,S2:];
coherence
[:D1,D2:] is upper Subset of [:S1,S2:]
proof end;
end;

theorem :: YELLOW_3:25  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty reflexive RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2 st [:D1,D2:] is upper holds
( D1 is upper & D2 is upper )
proof end;

theorem :: YELLOW_3:26  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty reflexive RelStr
for D being non empty upper Subset of [:S1,S2:] holds
( proj1 D is upper & proj2 D is upper )
proof end;

definition
let S1, S2 be RelStr ;
let D1 be lower Subset of S1;
let D2 be lower Subset of S2;
:: original: [:
redefine func [:D1,D2:] -> lower Subset of [:S1,S2:];
coherence
[:D1,D2:] is lower Subset of [:S1,S2:]
proof end;
end;

theorem :: YELLOW_3:27  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty reflexive RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2 st [:D1,D2:] is lower holds
( D1 is lower & D2 is lower )
proof end;

theorem :: YELLOW_3:28  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty reflexive RelStr
for D being non empty lower Subset of [:S1,S2:] holds
( proj1 D is lower & proj2 D is lower )
proof end;

definition
let R be RelStr ;
attr R is void means :Def3: :: YELLOW_3:def 3
the InternalRel of R is empty;
end;

:: deftheorem Def3 defines void YELLOW_3:def 3 :
for R being RelStr holds
( R is void iff the InternalRel of R is empty );

registration
cluster empty -> void RelStr ;
coherence
for b1 being RelStr st b1 is empty holds
b1 is void
proof end;
end;

registration
cluster non empty strict non void RelStr ;
existence
ex b1 being Poset st
( not b1 is void & not b1 is empty & b1 is strict )
proof end;
end;

registration
cluster non void -> non empty RelStr ;
coherence
for b1 being RelStr st not b1 is void holds
not b1 is empty
proof end;
end;

registration
cluster non empty reflexive -> non empty non void RelStr ;
coherence
for b1 being RelStr st not b1 is empty & b1 is reflexive holds
not b1 is void
proof end;
end;

registration
let R be non void RelStr ;
cluster the InternalRel of R -> non empty ;
coherence
not the InternalRel of R is empty
by Def3;
end;

theorem Th29: :: YELLOW_3:29  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2
for x being Element of S1
for y being Element of S2 st [x,y] is_>=_than [:D1,D2:] holds
( x is_>=_than D1 & y is_>=_than D2 )
proof end;

theorem Th30: :: YELLOW_3:30  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D1 being Subset of S1
for D2 being Subset of S2
for x being Element of S1
for y being Element of S2 st x is_>=_than D1 & y is_>=_than D2 holds
[x,y] is_>=_than [:D1,D2:]
proof end;

theorem Th31: :: YELLOW_3:31  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D being Subset of [:S1,S2:]
for x being Element of S1
for y being Element of S2 holds
( [x,y] is_>=_than D iff ( x is_>=_than proj1 D & y is_>=_than proj2 D ) )
proof end;

theorem Th32: :: YELLOW_3:32  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2
for x being Element of S1
for y being Element of S2 st [x,y] is_<=_than [:D1,D2:] holds
( x is_<=_than D1 & y is_<=_than D2 )
proof end;

theorem Th33: :: YELLOW_3:33  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D1 being Subset of S1
for D2 being Subset of S2
for x being Element of S1
for y being Element of S2 st x is_<=_than D1 & y is_<=_than D2 holds
[x,y] is_<=_than [:D1,D2:]
proof end;

theorem Th34: :: YELLOW_3:34  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty RelStr
for D being Subset of [:S1,S2:]
for x being Element of S1
for y being Element of S2 holds
( [x,y] is_<=_than D iff ( x is_<=_than proj1 D & y is_<=_than proj2 D ) )
proof end;

theorem Th35: :: YELLOW_3:35  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D1 being Subset of S1
for D2 being Subset of S2
for x being Element of S1
for y being Element of S2 st ex_sup_of D1,S1 & ex_sup_of D2,S2 & ( for b being Element of [:S1,S2:] st b is_>=_than [:D1,D2:] holds
[x,y] <= b ) holds
( ( for c being Element of S1 st c is_>=_than D1 holds
x <= c ) & ( for d being Element of S2 st d is_>=_than D2 holds
y <= d ) )
proof end;

theorem Th36: :: YELLOW_3:36  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D1 being Subset of S1
for D2 being Subset of S2
for x being Element of S1
for y being Element of S2 st ex_inf_of D1,S1 & ex_inf_of D2,S2 & ( for b being Element of [:S1,S2:] st b is_<=_than [:D1,D2:] holds
[x,y] >= b ) holds
( ( for c being Element of S1 st c is_<=_than D1 holds
x >= c ) & ( for d being Element of S2 st d is_<=_than D2 holds
y >= d ) )
proof end;

theorem :: YELLOW_3:37  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2
for x being Element of S1
for y being Element of S2 st ( for c being Element of S1 st c is_>=_than D1 holds
x <= c ) & ( for d being Element of S2 st d is_>=_than D2 holds
y <= d ) holds
for b being Element of [:S1,S2:] st b is_>=_than [:D1,D2:] holds
[x,y] <= b
proof end;

theorem :: YELLOW_3:38  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2
for x being Element of S1
for y being Element of S2 st ( for c being Element of S1 st c is_>=_than D1 holds
x >= c ) & ( for d being Element of S2 st d is_>=_than D2 holds
y >= d ) holds
for b being Element of [:S1,S2:] st b is_>=_than [:D1,D2:] holds
[x,y] >= b
proof end;

theorem Th39: :: YELLOW_3:39  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2 holds
( ( ex_sup_of D1,S1 & ex_sup_of D2,S2 ) iff ex_sup_of [:D1,D2:],[:S1,S2:] )
proof end;

theorem Th40: :: YELLOW_3:40  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2 holds
( ( ex_inf_of D1,S1 & ex_inf_of D2,S2 ) iff ex_inf_of [:D1,D2:],[:S1,S2:] )
proof end;

theorem Th41: :: YELLOW_3:41  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D being Subset of [:S1,S2:] holds
( ( ex_sup_of proj1 D,S1 & ex_sup_of proj2 D,S2 ) iff ex_sup_of D,[:S1,S2:] )
proof end;

theorem Th42: :: YELLOW_3:42  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D being Subset of [:S1,S2:] holds
( ( ex_inf_of proj1 D,S1 & ex_inf_of proj2 D,S2 ) iff ex_inf_of D,[:S1,S2:] )
proof end;

theorem Th43: :: YELLOW_3:43  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2 st ex_sup_of D1,S1 & ex_sup_of D2,S2 holds
sup [:D1,D2:] = [(sup D1),(sup D2)]
proof end;

theorem Th44: :: YELLOW_3:44  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty antisymmetric RelStr
for D1 being non empty Subset of S1
for D2 being non empty Subset of S2 st ex_inf_of D1,S1 & ex_inf_of D2,S2 holds
inf [:D1,D2:] = [(inf D1),(inf D2)]
proof end;

registration
let X, Y be non empty antisymmetric complete RelStr ;
cluster [:X,Y:] -> non empty strict antisymmetric with_suprema with_infima complete ;
coherence
[:X,Y:] is complete
proof end;
end;

theorem :: YELLOW_3:45  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being non empty antisymmetric lower-bounded RelStr st [:X,Y:] is complete holds
( X is complete & Y is complete )
proof end;

theorem :: YELLOW_3:46  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for L1, L2 being non empty antisymmetric RelStr
for D being non empty Subset of [:L1,L2:] st ( [:L1,L2:] is complete or ex_sup_of D,[:L1,L2:] ) holds
sup D = [(sup (proj1 D)),(sup (proj2 D))]
proof end;

theorem :: YELLOW_3:47  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for L1, L2 being non empty antisymmetric RelStr
for D being non empty Subset of [:L1,L2:] st ( [:L1,L2:] is complete or ex_inf_of D,[:L1,L2:] ) holds
inf D = [(inf (proj1 D)),(inf (proj2 D))]
proof end;

theorem :: YELLOW_3:48  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty reflexive RelStr
for D being non empty directed Subset of [:S1,S2:] holds [:(proj1 D),(proj2 D):] c= downarrow D
proof end;

theorem :: YELLOW_3:49  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for S1, S2 being non empty reflexive RelStr
for D being non empty filtered Subset of [:S1,S2:] holds [:(proj1 D),(proj2 D):] c= uparrow D
proof end;

scheme :: YELLOW_3:sch 7
Kappa2DS{ F1() -> non empty RelStr , F2() -> non empty RelStr , F3() -> non empty RelStr , F4( set , set ) -> set } :
ex f being Function of [:F1(),F2():],F3() st
for x being Element of F1()
for y being Element of F2() holds f . [x,y] = F4(x,y)
provided
A1: for x being Element of F1()
for y being Element of F2() holds F4(x,y) is Element of F3()
proof end;