:: FUNCT_3 semantic presentation  Show TPTP formulae Show IDV graph for whole article:: Showing IDV graph ... (Click the Palm Trees again to close it)

theorem Th1: :: FUNCT_3:1  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A, Y being set st A c= Y holds
id A = (id Y) | A
proof end;

theorem Th2: :: FUNCT_3:2  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set
for f, g being Function st X c= dom (g * f) holds
f .: X c= dom g
proof end;

theorem Th3: :: FUNCT_3:3  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set
for f, g being Function st X c= dom f & f .: X c= dom g holds
X c= dom (g * f)
proof end;

theorem Th4: :: FUNCT_3:4  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for Y being set
for f, g being Function st Y c= rng (g * f) & g is one-to-one holds
g " Y c= rng f
proof end;

theorem Th5: :: FUNCT_3:5  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for Y being set
for f, g being Function st Y c= rng g & g " Y c= rng f holds
Y c= rng (g * f)
proof end;

scheme :: FUNCT_3:sch 1
FuncEx3{ F1() -> set , F2() -> set , P1[ set , set , set ] } :
ex f being Function st
( dom f = [:F1(),F2():] & ( for x, y being set st x in F1() & y in F2() holds
P1[x,y,f . [x,y]] ) )
provided
A1: for x, y, z1, z2 being set st x in F1() & y in F2() & P1[x,y,z1] & P1[x,y,z2] holds
z1 = z2 and
A2: for x, y being set st x in F1() & y in F2() holds
ex z being set st P1[x,y,z]
proof end;

scheme :: FUNCT_3:sch 2
Lambda3{ F1() -> set , F2() -> set , F3( set , set ) -> set } :
ex f being Function st
( dom f = [:F1(),F2():] & ( for x, y being set st x in F1() & y in F2() holds
f . [x,y] = F3(x,y) ) )
proof end;

theorem Th6: :: FUNCT_3:6  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being set
for f, g being Function st dom f = [:X,Y:] & dom g = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
f . [x,y] = g . [x,y] ) holds
f = g
proof end;

definition
let f be Function;
func .: f -> Function means :Def1: :: FUNCT_3:def 1
( dom it = bool (dom f) & ( for X being set st X c= dom f holds
it . X = f .: X ) );
existence
ex b1 being Function st
( dom b1 = bool (dom f) & ( for X being set st X c= dom f holds
b1 . X = f .: X ) )
proof end;
uniqueness
for b1, b2 being Function st dom b1 = bool (dom f) & ( for X being set st X c= dom f holds
b1 . X = f .: X ) & dom b2 = bool (dom f) & ( for X being set st X c= dom f holds
b2 . X = f .: X ) holds
b1 = b2
proof end;
end;

:: deftheorem Def1 defines .: FUNCT_3:def 1 :
for f, b2 being Function holds
( b2 = .: f iff ( dom b2 = bool (dom f) & ( for X being set st X c= dom f holds
b2 . X = f .: X ) ) );

theorem :: FUNCT_3:7  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem Th8: :: FUNCT_3:8  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set
for f being Function st X in dom (.: f) holds
(.: f) . X = f .: X
proof end;

theorem :: FUNCT_3:9  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function holds (.: f) . {} = {}
proof end;

theorem Th10: :: FUNCT_3:10  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function holds rng (.: f) c= bool (rng f)
proof end;

theorem :: FUNCT_3:11  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:12  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A being set
for f being Function holds (.: f) .: A c= bool (rng f)
proof end;

theorem Th13: :: FUNCT_3:13  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for f being Function holds (.: f) " B c= bool (dom f)
proof end;

theorem :: FUNCT_3:14  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, B being set
for D being non empty set
for f being Function of X,D holds (.: f) " B c= bool X
proof end;

theorem Th15: :: FUNCT_3:15  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A being set
for f being Function holds union ((.: f) .: A) c= f .: (union A)
proof end;

theorem Th16: :: FUNCT_3:16  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A being set
for f being Function st A c= bool (dom f) holds
f .: (union A) = union ((.: f) .: A)
proof end;

theorem :: FUNCT_3:17  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, A being set
for D being non empty set
for f being Function of X,D st A c= bool X holds
f .: (union A) = union ((.: f) .: A)
proof end;

theorem Th18: :: FUNCT_3:18  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for f being Function holds union ((.: f) " B) c= f " (union B)
proof end;

theorem :: FUNCT_3:19  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for f being Function st B c= bool (rng f) holds
f " (union B) = union ((.: f) " B)
proof end;

theorem :: FUNCT_3:20  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g being Function holds .: (g * f) = (.: g) * (.: f)
proof end;

theorem Th21: :: FUNCT_3:21  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function holds .: f is Function of bool (dom f), bool (rng f)
proof end;

theorem Th22: :: FUNCT_3:22  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being set
for f being Function of X,Y st ( Y = {} implies X = {} ) holds
.: f is Function of bool X, bool Y
proof end;

definition
let X be set ;
let D be non empty set ;
let f be Function of X,D;
:: original: .:
redefine func .: f -> Function of bool X, bool D;
coherence
.: f is Function of bool X, bool D
by Th22;
end;

definition
let f be Function;
func " f -> Function means :Def2: :: FUNCT_3:def 2
( dom it = bool (rng f) & ( for Y being set st Y c= rng f holds
it . Y = f " Y ) );
existence
ex b1 being Function st
( dom b1 = bool (rng f) & ( for Y being set st Y c= rng f holds
b1 . Y = f " Y ) )
proof end;
uniqueness
for b1, b2 being Function st dom b1 = bool (rng f) & ( for Y being set st Y c= rng f holds
b1 . Y = f " Y ) & dom b2 = bool (rng f) & ( for Y being set st Y c= rng f holds
b2 . Y = f " Y ) holds
b1 = b2
proof end;
end;

:: deftheorem Def2 defines " FUNCT_3:def 2 :
for f, b2 being Function holds
( b2 = " f iff ( dom b2 = bool (rng f) & ( for Y being set st Y c= rng f holds
b2 . Y = f " Y ) ) );

theorem :: FUNCT_3:23  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem Th24: :: FUNCT_3:24  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for Y being set
for f being Function st Y in dom (" f) holds
(" f) . Y = f " Y
proof end;

theorem Th25: :: FUNCT_3:25  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function holds rng (" f) c= bool (dom f)
proof end;

theorem :: FUNCT_3:26  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:27  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for f being Function holds (" f) .: B c= bool (dom f)
proof end;

theorem :: FUNCT_3:28  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A being set
for f being Function holds (" f) " A c= bool (rng f)
proof end;

theorem Th29: :: FUNCT_3:29  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for f being Function holds union ((" f) .: B) c= f " (union B)
proof end;

theorem :: FUNCT_3:30  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for f being Function st B c= bool (rng f) holds
union ((" f) .: B) = f " (union B)
proof end;

theorem Th31: :: FUNCT_3:31  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A being set
for f being Function holds union ((" f) " A) c= f .: (union A)
proof end;

theorem :: FUNCT_3:32  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A being set
for f being Function st A c= bool (dom f) & f is one-to-one holds
union ((" f) " A) = f .: (union A)
proof end;

theorem Th33: :: FUNCT_3:33  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for f being Function holds (" f) .: B c= (.: f) " B
proof end;

theorem :: FUNCT_3:34  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for f being Function st f is one-to-one holds
(" f) .: B = (.: f) " B
proof end;

theorem Th35: :: FUNCT_3:35  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function
for A being set st A c= bool (dom f) holds
(" f) " A c= (.: f) .: A
proof end;

theorem Th36: :: FUNCT_3:36  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function
for A being set st f is one-to-one holds
(.: f) .: A c= (" f) " A
proof end;

theorem :: FUNCT_3:37  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function
for A being set st f is one-to-one & A c= bool (dom f) holds
(" f) " A = (.: f) .: A
proof end;

theorem :: FUNCT_3:38  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g being Function st g is one-to-one holds
" (g * f) = (" f) * (" g)
proof end;

theorem :: FUNCT_3:39  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function holds " f is Function of bool (rng f), bool (dom f)
proof end;

definition
let A, X be set ;
func chi A,X -> Function means :Def3: :: FUNCT_3:def 3
( dom it = X & ( for x being set st x in X holds
( ( x in A implies it . x = 1 ) & ( not x in A implies it . x = 0 ) ) ) );
existence
ex b1 being Function st
( dom b1 = X & ( for x being set st x in X holds
( ( x in A implies b1 . x = 1 ) & ( not x in A implies b1 . x = 0 ) ) ) )
proof end;
uniqueness
for b1, b2 being Function st dom b1 = X & ( for x being set st x in X holds
( ( x in A implies b1 . x = 1 ) & ( not x in A implies b1 . x = 0 ) ) ) & dom b2 = X & ( for x being set st x in X holds
( ( x in A implies b2 . x = 1 ) & ( not x in A implies b2 . x = 0 ) ) ) holds
b1 = b2
proof end;
end;

:: deftheorem Def3 defines chi FUNCT_3:def 3 :
for A, X being set
for b3 being Function holds
( b3 = chi A,X iff ( dom b3 = X & ( for x being set st x in X holds
( ( x in A implies b3 . x = 1 ) & ( not x in A implies b3 . x = 0 ) ) ) ) );

theorem :: FUNCT_3:40  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:41  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem Th42: :: FUNCT_3:42  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for x, A, X being set st (chi A,X) . x = 1 holds
x in A
proof end;

theorem :: FUNCT_3:43  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for x, X, A being set st x in X \ A holds
(chi A,X) . x = 0
proof end;

theorem :: FUNCT_3:44  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:45  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:46  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:47  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A, X, B being set st A c= X & B c= X & chi A,X = chi B,X holds
A = B
proof end;

theorem Th48: :: FUNCT_3:48  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A, X being set holds rng (chi A,X) c= {0,1}
proof end;

theorem :: FUNCT_3:49  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set
for f being Function of X,{0,1} holds f = chi (f " {1}),X
proof end;

definition
let A, X be set ;
:: original: chi
redefine func chi A,X -> Function of X,{0,1};
coherence
chi A,X is Function of X,{0,1}
proof end;
end;

notation
let Y be set ;
let A be Subset of Y;
synonym incl A for id Y;
end;

definition
let Y be set ;
let A be Subset of Y;
:: original: incl
redefine func incl A -> Function of A,Y;
coherence
incl is Function of A,Y
proof end;
end;

theorem :: FUNCT_3:50  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:51  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:52  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:53  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for Y being set
for A being Subset of Y holds incl A = (id Y) | A by Th1;

theorem :: FUNCT_3:54  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:55  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:56  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for x, Y being set
for A being Subset of Y st x in A holds
(incl A) . x in Y
proof end;

definition
let X, Y be set ;
canceled;
func pr1 X,Y -> Function means :Def5: :: FUNCT_3:def 5
( dom it = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
it . [x,y] = x ) );
existence
ex b1 being Function st
( dom b1 = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
b1 . [x,y] = x ) )
proof end;
uniqueness
for b1, b2 being Function st dom b1 = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
b1 . [x,y] = x ) & dom b2 = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
b2 . [x,y] = x ) holds
b1 = b2
proof end;
func pr2 X,Y -> Function means :Def6: :: FUNCT_3:def 6
( dom it = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
it . [x,y] = y ) );
existence
ex b1 being Function st
( dom b1 = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
b1 . [x,y] = y ) )
proof end;
uniqueness
for b1, b2 being Function st dom b1 = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
b1 . [x,y] = y ) & dom b2 = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
b2 . [x,y] = y ) holds
b1 = b2
proof end;
end;

:: deftheorem FUNCT_3:def 4 :
canceled;

:: deftheorem Def5 defines pr1 FUNCT_3:def 5 :
for X, Y being set
for b3 being Function holds
( b3 = pr1 X,Y iff ( dom b3 = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
b3 . [x,y] = x ) ) );

:: deftheorem Def6 defines pr2 FUNCT_3:def 6 :
for X, Y being set
for b3 being Function holds
( b3 = pr2 X,Y iff ( dom b3 = [:X,Y:] & ( for x, y being set st x in X & y in Y holds
b3 . [x,y] = y ) ) );

theorem :: FUNCT_3:57  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:58  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem Th59: :: FUNCT_3:59  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being set holds rng (pr1 X,Y) c= X
proof end;

theorem :: FUNCT_3:60  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for Y, X being set st Y <> {} holds
rng (pr1 X,Y) = X
proof end;

theorem Th61: :: FUNCT_3:61  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being set holds rng (pr2 X,Y) c= Y
proof end;

theorem :: FUNCT_3:62  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being set st X <> {} holds
rng (pr2 X,Y) = Y
proof end;

definition
let X, Y be set ;
:: original: pr1
redefine func pr1 X,Y -> Function of [:X,Y:],X;
coherence
pr1 X,Y is Function of [:X,Y:],X
proof end;
:: original: pr2
redefine func pr2 X,Y -> Function of [:X,Y:],Y;
coherence
pr2 X,Y is Function of [:X,Y:],Y
proof end;
end;

definition
let X be set ;
func delta X -> Function means :Def7: :: FUNCT_3:def 7
( dom it = X & ( for x being set st x in X holds
it . x = [x,x] ) );
existence
ex b1 being Function st
( dom b1 = X & ( for x being set st x in X holds
b1 . x = [x,x] ) )
proof end;
uniqueness
for b1, b2 being Function st dom b1 = X & ( for x being set st x in X holds
b1 . x = [x,x] ) & dom b2 = X & ( for x being set st x in X holds
b2 . x = [x,x] ) holds
b1 = b2
proof end;
end;

:: deftheorem Def7 defines delta FUNCT_3:def 7 :
for X being set
for b2 being Function holds
( b2 = delta X iff ( dom b2 = X & ( for x being set st x in X holds
b2 . x = [x,x] ) ) );

theorem :: FUNCT_3:63  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:64  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem :: FUNCT_3:65  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem Th66: :: FUNCT_3:66  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set holds rng (delta X) c= [:X,X:]
proof end;

definition
let X be set ;
:: original: delta
redefine func delta X -> Function of X,[:X,X:];
coherence
delta X is Function of X,[:X,X:]
proof end;
end;

definition
let f, g be Function;
func <:f,g:> -> Function means :Def8: :: FUNCT_3:def 8
( dom it = (dom f) /\ (dom g) & ( for x being set st x in dom it holds
it . x = [(f . x),(g . x)] ) );
existence
ex b1 being Function st
( dom b1 = (dom f) /\ (dom g) & ( for x being set st x in dom b1 holds
b1 . x = [(f . x),(g . x)] ) )
proof end;
uniqueness
for b1, b2 being Function st dom b1 = (dom f) /\ (dom g) & ( for x being set st x in dom b1 holds
b1 . x = [(f . x),(g . x)] ) & dom b2 = (dom f) /\ (dom g) & ( for x being set st x in dom b2 holds
b2 . x = [(f . x),(g . x)] ) holds
b1 = b2
proof end;
end;

:: deftheorem Def8 defines <: FUNCT_3:def 8 :
for f, g, b3 being Function holds
( b3 = <:f,g:> iff ( dom b3 = (dom f) /\ (dom g) & ( for x being set st x in dom b3 holds
b3 . x = [(f . x),(g . x)] ) ) );

theorem :: FUNCT_3:67  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem Th68: :: FUNCT_3:68  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for x being set
for f, g being Function st x in (dom f) /\ (dom g) holds
<:f,g:> . x = [(f . x),(g . x)]
proof end;

theorem Th69: :: FUNCT_3:69  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for x, X being set
for f, g being Function st dom f = X & dom g = X & x in X holds
<:f,g:> . x = [(f . x),(g . x)]
proof end;

theorem Th70: :: FUNCT_3:70  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set
for f, g being Function st dom f = X & dom g = X holds
dom <:f,g:> = X
proof end;

theorem Th71: :: FUNCT_3:71  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g being Function holds rng <:f,g:> c= [:(rng f),(rng g):]
proof end;

theorem Th72: :: FUNCT_3:72  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for Y, Z being set
for f, g being Function st dom f = dom g & rng f c= Y & rng g c= Z holds
( (pr1 Y,Z) * <:f,g:> = f & (pr2 Y,Z) * <:f,g:> = g )
proof end;

theorem Th73: :: FUNCT_3:73  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being set holds <:(pr1 X,Y),(pr2 X,Y):> = id [:X,Y:]
proof end;

theorem Th74: :: FUNCT_3:74  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g, h, k being Function st dom f = dom g & dom k = dom h & <:f,g:> = <:k,h:> holds
( f = k & g = h )
proof end;

theorem :: FUNCT_3:75  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g, h being Function holds <:(f * h),(g * h):> = <:f,g:> * h
proof end;

theorem :: FUNCT_3:76  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for A being set
for f, g being Function holds <:f,g:> .: A c= [:(f .: A),(g .: A):]
proof end;

theorem :: FUNCT_3:77  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B being set
for C being non empty set
for f, g being Function holds <:f,g:> " [:B,C:] = (f " B) /\ (g " C)
proof end;

theorem Th78: :: FUNCT_3:78  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y, Z being set
for f being Function of X,Y
for g being Function of X,Z st ( Y = {} implies X = {} ) & ( Z = {} implies X = {} ) holds
<:f,g:> is Function of X,[:Y,Z:]
proof end;

definition
let X be set ;
let D1, D2 be non empty set ;
let f1 be Function of X,D1;
let f2 be Function of X,D2;
:: original: <:
redefine func <:f1,f2:> -> Function of X,[:D1,D2:];
coherence
<:f1,f2:> is Function of X,[:D1,D2:]
by Th78;
end;

theorem :: FUNCT_3:79  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for C, D1, D2 being non empty set
for f1 being Function of C,D1
for f2 being Function of C,D2
for c being Element of C holds <:f1,f2:> . c = [(f1 . c),(f2 . c)]
proof end;

theorem :: FUNCT_3:80  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y, Z being set
for f being Function of X,Y
for g being Function of X,Z holds rng <:f,g:> c= [:Y,Z:]
proof end;

theorem Th81: :: FUNCT_3:81  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y, Z being set
for f being Function of X,Y
for g being Function of X,Z st ( Y = {} implies X = {} ) & ( Z = {} implies X = {} ) holds
( (pr1 Y,Z) * <:f,g:> = f & (pr2 Y,Z) * <:f,g:> = g )
proof end;

theorem :: FUNCT_3:82  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set
for D1, D2 being non empty set
for f being Function of X,D1
for g being Function of X,D2 holds
( (pr1 D1,D2) * <:f,g:> = f & (pr2 D1,D2) * <:f,g:> = g ) by Th81;

theorem :: FUNCT_3:83  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y, Z being set
for f1, f2 being Function of X,Y
for g1, g2 being Function of X,Z st ( Y = {} implies X = {} ) & ( Z = {} implies X = {} ) & <:f1,g1:> = <:f2,g2:> holds
( f1 = f2 & g1 = g2 )
proof end;

theorem :: FUNCT_3:84  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set
for D1, D2 being non empty set
for f1, f2 being Function of X,D1
for g1, g2 being Function of X,D2 st <:f1,g1:> = <:f2,g2:> holds
( f1 = f2 & g1 = g2 )
proof end;

definition
let f, g be Function;
func [:f,g:] -> Function means :Def9: :: FUNCT_3:def 9
( dom it = [:(dom f),(dom g):] & ( for x, y being set st x in dom f & y in dom g holds
it . [x,y] = [(f . x),(g . y)] ) );
existence
ex b1 being Function st
( dom b1 = [:(dom f),(dom g):] & ( for x, y being set st x in dom f & y in dom g holds
b1 . [x,y] = [(f . x),(g . y)] ) )
proof end;
uniqueness
for b1, b2 being Function st dom b1 = [:(dom f),(dom g):] & ( for x, y being set st x in dom f & y in dom g holds
b1 . [x,y] = [(f . x),(g . y)] ) & dom b2 = [:(dom f),(dom g):] & ( for x, y being set st x in dom f & y in dom g holds
b2 . [x,y] = [(f . x),(g . y)] ) holds
b1 = b2
proof end;
end;

:: deftheorem Def9 defines [: FUNCT_3:def 9 :
for f, g, b3 being Function holds
( b3 = [:f,g:] iff ( dom b3 = [:(dom f),(dom g):] & ( for x, y being set st x in dom f & y in dom g holds
b3 . [x,y] = [(f . x),(g . y)] ) ) );

theorem :: FUNCT_3:85  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
canceled;

theorem Th86: :: FUNCT_3:86  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g being Function
for x, y being set st [x,y] in [:(dom f),(dom g):] holds
[:f,g:] . [x,y] = [(f . x),(g . y)]
proof end;

theorem Th87: :: FUNCT_3:87  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g being Function holds [:f,g:] = <:(f * (pr1 (dom f),(dom g))),(g * (pr2 (dom f),(dom g))):>
proof end;

theorem Th88: :: FUNCT_3:88  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g being Function holds rng [:f,g:] = [:(rng f),(rng g):]
proof end;

theorem Th89: :: FUNCT_3:89  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X being set
for f, g being Function st dom f = X & dom g = X holds
<:f,g:> = [:f,g:] * (delta X)
proof end;

theorem :: FUNCT_3:90  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y being set holds [:(id X),(id Y):] = id [:X,Y:]
proof end;

theorem :: FUNCT_3:91  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g, h, k being Function holds [:f,h:] * <:g,k:> = <:(f * g),(h * k):>
proof end;

theorem :: FUNCT_3:92  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f, g, h, k being Function holds [:f,h:] * [:g,k:] = [:(f * g),(h * k):]
proof end;

theorem :: FUNCT_3:93  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B, A being set
for f, g being Function holds [:f,g:] .: [:B,A:] = [:(f .: B),(g .: A):]
proof end;

theorem :: FUNCT_3:94  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for B, A being set
for f, g being Function holds [:f,g:] " [:B,A:] = [:(f " B),(g " A):]
proof end;

theorem Th95: :: FUNCT_3:95  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y, V, Z being set
for f being Function of X,Y
for g being Function of V,Z holds [:f,g:] is Function of [:X,V:],[:Y,Z:]
proof end;

definition
let X1, X2, Y1, Y2 be set ;
let f1 be Function of X1,Y1;
let f2 be Function of X2,Y2;
:: original: [:
redefine func [:f1,f2:] -> Function of [:X1,X2:],[:Y1,Y2:];
coherence
[:f1,f2:] is Function of [:X1,X2:],[:Y1,Y2:]
by Th95;
end;

theorem :: FUNCT_3:96  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for C1, D1, C2, D2 being non empty set
for f1 being Function of C1,D1
for f2 being Function of C2,D2
for c1 being Element of C1
for c2 being Element of C2 holds [:f1,f2:] . [c1,c2] = [(f1 . c1),(f2 . c2)]
proof end;

theorem :: FUNCT_3:97  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X1, Y1, X2, Y2 being set
for f1 being Function of X1,Y1
for f2 being Function of X2,Y2 st ( Y1 = {} implies X1 = {} ) & ( Y2 = {} implies X2 = {} ) holds
[:f1,f2:] = <:(f1 * (pr1 X1,X2)),(f2 * (pr2 X1,X2)):>
proof end;

theorem :: FUNCT_3:98  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X1, X2 being set
for D1, D2 being non empty set
for f1 being Function of X1,D1
for f2 being Function of X2,D2 holds [:f1,f2:] = <:(f1 * (pr1 X1,X2)),(f2 * (pr2 X1,X2)):>
proof end;

theorem :: FUNCT_3:99  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for X, Y1, Y2 being set
for f1 being Function of X,Y1
for f2 being Function of X,Y2 holds <:f1,f2:> = [:f1,f2:] * (delta X)
proof end;

theorem :: FUNCT_3:100  Show TPTP formulae Show IDV graph:: Showing IDV graph ... (Click the Palm Tree again to close it) Show TPTP problem
for f being Function holds (pr1 (dom f),(rng f)) .: f = dom f
proof end;