TSTP Solution File: SYO885^1.033.003 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO885^1.033.003 : TPTP v8.1.2. Released v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:23:52 EDT 2023

% Result   : Theorem 3.55s 3.73s
% Output   : Proof 3.55s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYO885^1.033.003 : TPTP v8.1.2. Released v7.5.0.
% 0.00/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n010.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Sat Aug 26 06:17:05 EDT 2023
% 0.14/0.34  % CPUTime    : 
% 3.55/3.73  SZS status Theorem for theBenchmark.p
% 3.55/3.73  SZS output start Proof for theBenchmark.p
% 3.55/3.73  Clause #0 (by assumption #[]): Eq
% 3.55/3.73    (Not
% 3.55/3.73      (Exists fun F =>
% 3.55/3.73        And (And (Eq (F a0 a1 a2) (f a0 a1 a2)) (Eq (F a0 a2 a1) (f a0 a1 a2))) (Eq (F a2 a1 a0) (f a0 a1 a2))))
% 3.55/3.73    True
% 3.55/3.73  Clause #1 (by clausification #[0]): Eq
% 3.55/3.73    (Exists fun F =>
% 3.55/3.73      And (And (Eq (F a0 a1 a2) (f a0 a1 a2)) (Eq (F a0 a2 a1) (f a0 a1 a2))) (Eq (F a2 a1 a0) (f a0 a1 a2)))
% 3.55/3.73    False
% 3.55/3.73  Clause #2 (by clausification #[1]): ∀ (a : Iota → Iota → Iota → Iota),
% 3.55/3.73    Eq (And (And (Eq (a a0 a1 a2) (f a0 a1 a2)) (Eq (a a0 a2 a1) (f a0 a1 a2))) (Eq (a a2 a1 a0) (f a0 a1 a2))) False
% 3.55/3.73  Clause #3 (by clausification #[2]): ∀ (a : Iota → Iota → Iota → Iota),
% 3.55/3.73    Or (Eq (And (Eq (a a0 a1 a2) (f a0 a1 a2)) (Eq (a a0 a2 a1) (f a0 a1 a2))) False)
% 3.55/3.73      (Eq (Eq (a a2 a1 a0) (f a0 a1 a2)) False)
% 3.55/3.73  Clause #4 (by clausification #[3]): ∀ (a : Iota → Iota → Iota → Iota),
% 3.55/3.73    Or (Eq (Eq (a a2 a1 a0) (f a0 a1 a2)) False)
% 3.55/3.73      (Or (Eq (Eq (a a0 a1 a2) (f a0 a1 a2)) False) (Eq (Eq (a a0 a2 a1) (f a0 a1 a2)) False))
% 3.55/3.73  Clause #5 (by clausification #[4]): ∀ (a : Iota → Iota → Iota → Iota),
% 3.55/3.73    Or (Eq (Eq (a a0 a1 a2) (f a0 a1 a2)) False)
% 3.55/3.73      (Or (Eq (Eq (a a0 a2 a1) (f a0 a1 a2)) False) (Ne (a a2 a1 a0) (f a0 a1 a2)))
% 3.55/3.73  Clause #6 (by clausification #[5]): ∀ (a : Iota → Iota → Iota → Iota),
% 3.55/3.73    Or (Eq (Eq (a a0 a2 a1) (f a0 a1 a2)) False) (Or (Ne (a a2 a1 a0) (f a0 a1 a2)) (Ne (a a0 a1 a2) (f a0 a1 a2)))
% 3.55/3.73  Clause #7 (by clausification #[6]): ∀ (a : Iota → Iota → Iota → Iota),
% 3.55/3.73    Or (Ne (a a2 a1 a0) (f a0 a1 a2)) (Or (Ne (a a0 a1 a2) (f a0 a1 a2)) (Ne (a a0 a2 a1) (f a0 a1 a2)))
% 3.55/3.73  Clause #8 (by equality resolution #[7]): Or (Ne ((fun x x x => f a0 a1 a2) a0 a1 a2) (f a0 a1 a2)) (Ne ((fun x x x => f a0 a1 a2) a0 a2 a1) (f a0 a1 a2))
% 3.55/3.73  Clause #9 (by betaEtaReduce #[8]): Or (Ne (f a0 a1 a2) (f a0 a1 a2)) (Ne (f a0 a1 a2) (f a0 a1 a2))
% 3.55/3.73  Clause #10 (by eliminate duplicate literals #[9]): Ne (f a0 a1 a2) (f a0 a1 a2)
% 3.55/3.73  Clause #11 (by eliminate resolved literals #[10]): False
% 3.55/3.73  SZS output end Proof for theBenchmark.p
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