TSTP Solution File: SYO842+1 by Crossbow---0.1
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%------------------------------------------------------------------------------
% File : Crossbow---0.1
% Problem : SYO842+1 : TPTP v8.1.0. Released v7.5.0.
% Transfm : none
% Format : tptp:raw
% Command : do_Crossbow---0.1 %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 14:35:58 EDT 2022
% Result : CounterSatisfiable 5.35s 5.54s
% Output : FiniteModel 5.35s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13 % Problem : SYO842+1 : TPTP v8.1.0. Released v7.5.0.
% 0.04/0.14 % Command : do_Crossbow---0.1 %s
% 0.14/0.36 % Computer : n016.cluster.edu
% 0.14/0.36 % Model : x86_64 x86_64
% 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36 % Memory : 8042.1875MB
% 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36 % CPULimit : 300
% 0.14/0.36 % WCLimit : 600
% 0.14/0.36 % DateTime : Sat Jul 9 09:02:39 EDT 2022
% 0.14/0.36 % CPUTime :
% 0.14/0.36 /export/starexec/sandbox2/solver/bin
% 0.14/0.37 crossbow.opt
% 0.14/0.37 do_Crossbow---0.1
% 0.14/0.37 eprover
% 0.14/0.37 runsolver
% 0.14/0.37 starexec_run_Crossbow---0.1
% 5.35/5.54 % SZS status CounterSatisfiable for theBenchmark.p
% 5.35/5.54 % SZS output start FiniteModel for theBenchmark.p
% 5.35/5.54 % domain size: 4
% 5.35/5.54 fof(interp, fi_domain, ![X] : (X = 0 | X = 1 | X = 2 | X = 3)).
% 5.35/5.54 fof(interp, fi_functors, a0 = 1).
% 5.35/5.54 fof(interp, fi_functors, a1 = 1).
% 5.35/5.54 fof(interp, fi_functors, a2 = 0).
% 5.35/5.54 fof(interp, fi_functors, a3 = 0).
% 5.35/5.54 fof(interp, fi_functors, a4 = 0).
% 5.35/5.54 fof(interp, fi_predicates, ~aal2(0) & ~aal2(1) & aal2(2) & ~aal2(3)).
% 5.35/5.54 fof(interp, fi_predicates, aal3(0) & aal3(1) & aal3(2) & ~aal3(3)).
% 5.35/5.54 fof(interp, fi_predicates, ~aal4(0) & ~aal4(1) & aal4(2) & aal4(3)).
% 5.35/5.54 fof(interp, fi_predicates, ~aal5(0) & ~aal5(1) & ~aal5(2) & aal5(3)).
% 5.35/5.54 fof(interp, fi_predicates, ~aal6(0) & ~aal6(1) & ~aal6(2) & aal6(3)).
% 5.35/5.54 fof(interp, fi_predicates, ~aal7(0) & ~aal7(1) & ~aal7(2) & ~aal7(3)).
% 5.35/5.54 fof(interp, fi_predicates, ~adisjoint(0, 0) & ~adisjoint(0, 1) &
% 5.35/5.54 ~adisjoint(0, 2) &
% 5.35/5.54 ~adisjoint(0, 3) &
% 5.35/5.54 ~adisjoint(1, 0) &
% 5.35/5.54 ~adisjoint(1, 1) &
% 5.35/5.54 ~adisjoint(1, 2) &
% 5.35/5.54 ~adisjoint(1, 3) &
% 5.35/5.54 ~adisjoint(2, 0) &
% 5.35/5.54 ~adisjoint(2, 1) &
% 5.35/5.54 ~adisjoint(2, 2) &
% 5.35/5.54 ~adisjoint(2, 3) &
% 5.35/5.54 ~adisjoint(3, 0) &
% 5.35/5.54 ~adisjoint(3, 1) &
% 5.35/5.54 ~adisjoint(3, 2) &
% 5.35/5.54 ~adisjoint(3, 3)).
% 5.35/5.54 fof(interp, fi_predicates, aex3(0) & ~aex3(1) & aex3(2) & aex3(3)).
% 5.35/5.54 fof(interp, fi_predicates, ~aex4(0) & ~aex4(1) & ~aex4(2) & aex4(3)).
% 5.35/5.54 fof(interp, fi_predicates, ~ain(0, 0) & ~ain(0, 1) & ain(0, 2) & ain(0, 3) &
% 5.35/5.54 ~ain(1, 0) &
% 5.35/5.54 ~ain(1, 1) &
% 5.35/5.54 ain(1, 2) &
% 5.35/5.54 ~ain(1, 3) &
% 5.35/5.54 ~ain(2, 0) &
% 5.35/5.54 ~ain(2, 1) &
% 5.35/5.54 ain(2, 2) &
% 5.35/5.54 ~ain(2, 3) &
% 5.35/5.54 ~ain(3, 0) &
% 5.35/5.54 ~ain(3, 1) &
% 5.35/5.54 ain(3, 2) &
% 5.35/5.54 ~ain(3, 3)).
% 5.35/5.54 fof(interp, fi_functors, aint(0, 0) = 0 & aint(0, 1) = 0 & aint(0, 2) = 0 &
% 5.35/5.54 aint(0, 3) = 0 &
% 5.35/5.54 aint(1, 0) = 0 &
% 5.35/5.54 aint(1, 1) = 0 &
% 5.35/5.54 aint(1, 2) = 0 &
% 5.35/5.54 aint(1, 3) = 0 &
% 5.35/5.54 aint(2, 0) = 0 &
% 5.35/5.54 aint(2, 1) = 0 &
% 5.35/5.54 aint(2, 2) = 2 &
% 5.35/5.54 aint(2, 3) = 3 &
% 5.35/5.54 aint(3, 0) = 0 &
% 5.35/5.54 aint(3, 1) = 0 &
% 5.35/5.54 aint(3, 2) = 3 &
% 5.35/5.54 aint(3, 3) = 3).
% 5.35/5.54 fof(interp, fi_functors, apow(0) = 3 & apow(1) = 0 & apow(2) = 1 & apow(3) = 1).
% 5.35/5.54 fof(interp, fi_functors, asing(0) = 1 & asing(1) = 1 & asing(2) = 2 &
% 5.35/5.54 asing(3) = 2).
% 5.35/5.54 fof(interp, fi_functors, asm(0, 0) = 1 & asm(0, 1) = 2 & asm(0, 2) = 3 &
% 5.35/5.54 asm(0, 3) = 2 &
% 5.35/5.54 asm(1, 0) = 1 &
% 5.35/5.54 asm(1, 1) = 3 &
% 5.35/5.54 asm(1, 2) = 2 &
% 5.35/5.54 asm(1, 3) = 2 &
% 5.35/5.54 asm(2, 0) = 1 &
% 5.35/5.54 asm(2, 1) = 2 &
% 5.35/5.54 asm(2, 2) = 0 &
% 5.35/5.54 asm(2, 3) = 0 &
% 5.35/5.54 asm(3, 0) = 3 &
% 5.35/5.54 asm(3, 1) = 3 &
% 5.35/5.54 asm(3, 2) = 0 &
% 5.35/5.54 asm(3, 3) = 2).
% 5.35/5.54 fof(interp, fi_predicates, asubq(0, 0) & asubq(0, 1) & asubq(0, 2) & asubq(0, 3) &
% 5.35/5.54 asubq(1, 0) &
% 5.35/5.54 asubq(1, 1) &
% 5.35/5.54 asubq(1, 2) &
% 5.35/5.54 asubq(1, 3) &
% 5.35/5.54 asubq(2, 0) &
% 5.35/5.54 asubq(2, 1) &
% 5.35/5.54 asubq(2, 2) &
% 5.35/5.54 ~asubq(2, 3) &
% 5.35/5.54 asubq(3, 0) &
% 5.35/5.54 ~asubq(3, 1) &
% 5.35/5.54 asubq(3, 2) &
% 5.35/5.54 asubq(3, 3)).
% 5.35/5.54 fof(interp, fi_functors, aun(0, 0) = 0 & aun(0, 1) = 2 & aun(0, 2) = 1 &
% 5.35/5.54 aun(0, 3) = 3 &
% 5.35/5.54 aun(1, 0) = 3 &
% 5.35/5.54 aun(1, 1) = 2 &
% 5.35/5.54 aun(1, 2) = 2 &
% 5.35/5.54 aun(1, 3) = 3 &
% 5.35/5.54 aun(2, 0) = 2 &
% 5.35/5.54 aun(2, 1) = 3 &
% 5.35/5.54 aun(2, 2) = 2 &
% 5.35/5.54 aun(2, 3) = 3 &
% 5.35/5.54 aun(3, 0) = 0 &
% 5.35/5.54 aun(3, 1) = 3 &
% 5.35/5.54 aun(3, 2) = 2 &
% 5.35/5.54 aun(3, 3) = 0).
% 5.35/5.54 fof(interp, fi_functors, esk1_3(0, 0, 0) = 0 & esk1_3(0, 0, 1) = 2 &
% 5.35/5.54 esk1_3(0, 0, 2) = 3 &
% 5.35/5.54 esk1_3(0, 0, 3) = 2 &
% 5.35/5.54 esk1_3(0, 1, 0) = 2 &
% 5.35/5.54 esk1_3(0, 1, 1) = 2 &
% 5.35/5.54 esk1_3(0, 1, 2) = 0 &
% 5.35/5.54 esk1_3(0, 1, 3) = 0 &
% 5.35/5.54 esk1_3(0, 2, 0) = 1 &
% 5.35/5.54 esk1_3(0, 2, 1) = 1 &
% 5.35/5.54 esk1_3(0, 2, 2) = 2 &
% 5.35/5.54 esk1_3(0, 2, 3) = 0 &
% 5.35/5.54 esk1_3(0, 3, 0) = 2 &
% 5.35/5.54 esk1_3(0, 3, 1) = 0 &
% 5.35/5.54 esk1_3(0, 3, 2) = 3 &
% 5.35/5.54 esk1_3(0, 3, 3) = 3 &
% 5.35/5.54 esk1_3(1, 0, 0) = 3 &
% 5.35/5.54 esk1_3(1, 0, 1) = 2 &
% 5.35/5.54 esk1_3(1, 0, 2) = 2 &
% 5.35/5.54 esk1_3(1, 0, 3) = 2 &
% 5.35/5.54 esk1_3(1, 1, 0) = 3 &
% 5.35/5.54 esk1_3(1, 1, 1) = 0 &
% 5.35/5.54 esk1_3(1, 1, 2) = 0 &
% 5.35/5.54 esk1_3(1, 1, 3) = 2 &
% 5.35/5.54 esk1_3(1, 2, 0) = 2 &
% 5.35/5.54 esk1_3(1, 2, 1) = 3 &
% 5.35/5.54 esk1_3(1, 2, 2) = 2 &
% 5.35/5.54 esk1_3(1, 2, 3) = 1 &
% 5.35/5.54 esk1_3(1, 3, 0) = 0 &
% 5.35/5.54 esk1_3(1, 3, 1) = 2 &
% 5.35/5.54 esk1_3(1, 3, 2) = 1 &
% 5.35/5.54 esk1_3(1, 3, 3) = 1 &
% 5.35/5.54 esk1_3(2, 0, 0) = 1 &
% 5.35/5.54 esk1_3(2, 0, 1) = 3 &
% 5.35/5.54 esk1_3(2, 0, 2) = 2 &
% 5.35/5.54 esk1_3(2, 0, 3) = 0 &
% 5.35/5.54 esk1_3(2, 1, 0) = 2 &
% 5.35/5.54 esk1_3(2, 1, 1) = 3 &
% 5.35/5.54 esk1_3(2, 1, 2) = 1 &
% 5.35/5.54 esk1_3(2, 1, 3) = 2 &
% 5.35/5.54 esk1_3(2, 2, 0) = 0 &
% 5.35/5.54 esk1_3(2, 2, 1) = 0 &
% 5.35/5.54 esk1_3(2, 2, 2) = 2 &
% 5.35/5.54 esk1_3(2, 2, 3) = 2 &
% 5.35/5.54 esk1_3(2, 3, 0) = 0 &
% 5.35/5.54 esk1_3(2, 3, 1) = 0 &
% 5.35/5.54 esk1_3(2, 3, 2) = 0 &
% 5.35/5.54 esk1_3(2, 3, 3) = 3 &
% 5.35/5.54 esk1_3(3, 0, 0) = 3 &
% 5.35/5.54 esk1_3(3, 0, 1) = 3 &
% 5.35/5.54 esk1_3(3, 0, 2) = 3 &
% 5.35/5.54 esk1_3(3, 0, 3) = 3 &
% 5.35/5.54 esk1_3(3, 1, 0) = 0 &
% 5.35/5.54 esk1_3(3, 1, 1) = 3 &
% 5.35/5.54 esk1_3(3, 1, 2) = 1 &
% 5.35/5.54 esk1_3(3, 1, 3) = 1 &
% 5.35/5.54 esk1_3(3, 2, 0) = 0 &
% 5.35/5.54 esk1_3(3, 2, 1) = 0 &
% 5.35/5.54 esk1_3(3, 2, 2) = 1 &
% 5.35/5.54 esk1_3(3, 2, 3) = 0 &
% 5.35/5.54 esk1_3(3, 3, 0) = 1 &
% 5.35/5.54 esk1_3(3, 3, 1) = 0 &
% 5.35/5.54 esk1_3(3, 3, 2) = 1 &
% 5.35/5.54 esk1_3(3, 3, 3) = 0).
% 5.35/5.54 fof(interp, fi_functors, esk2_0 = 1).
% 5.35/5.54 fof(interp, fi_functors, esk3_0 = 0).
% 5.35/5.54 % SZS output end FiniteModel for theBenchmark.p
% 5.35/5.55 % 4 lemma(s) from E
% 5.35/5.55 % cnf(cl, axiom, asubq(esk3_0, esk2_0)).
% 5.35/5.55 % cnf(cl, axiom, asubq(aint(A, B), B)).
% 5.35/5.55 % cnf(cl, axiom, asubq(aint(A, B), A)).
% 5.35/5.55 % cnf(cl, axiom, ~ain(esk3_0, apow(esk2_0))).
% 5.35/5.55 % 23 pred(s)
% 5.35/5.55 % 71 func(s)
% 5.35/5.55 % 1 sort(s)
% 5.35/5.55 % 140 clause(s)
% 5.35/5.55 % Instantiating 1 (5125 ms)
% 5.35/5.55 % Solving (5125 ms)
% 5.35/5.55 % Instantiating 2 (5125 ms)
% 5.35/5.55 % Solving (5126 ms)
% 5.35/5.55 % Instantiating 3 (5127 ms)
% 5.35/5.55 % Solving (5130 ms)
% 5.35/5.55 % Instantiating 4 (5135 ms)
% 5.35/5.55 % Solving (5140 ms)
% 5.35/5.55 %
% 5.35/5.55 % 1 model found (5148 ms)
%------------------------------------------------------------------------------