TSTP Solution File: SYO652-1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SYO652-1 : TPTP v8.1.0. Released v7.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 19:50:11 EDT 2022

% Result   : Unsatisfiable 2.59s 2.85s
% Output   : Refutation 2.59s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SYO652-1 : TPTP v8.1.0. Released v7.3.0.
% 0.07/0.13  % Command  : sos-script %s
% 0.12/0.34  % Computer : n022.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Sat Jul  9 08:49:56 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.57/1.77  ----- Otter 3.2, August 2001 -----
% 1.57/1.77  The process was started by sandbox2 on n022.cluster.edu,
% 1.57/1.77  Sat Jul  9 08:49:56 2022
% 1.57/1.77  The command was "./sos".  The process ID is 19500.
% 1.57/1.77  
% 1.57/1.77  set(prolog_style_variables).
% 1.57/1.77  set(auto).
% 1.57/1.77     dependent: set(auto1).
% 1.57/1.77     dependent: set(process_input).
% 1.57/1.77     dependent: clear(print_kept).
% 1.57/1.77     dependent: clear(print_new_demod).
% 1.57/1.77     dependent: clear(print_back_demod).
% 1.57/1.77     dependent: clear(print_back_sub).
% 1.57/1.77     dependent: set(control_memory).
% 1.57/1.77     dependent: assign(max_mem, 12000).
% 1.57/1.77     dependent: assign(pick_given_ratio, 4).
% 1.57/1.77     dependent: assign(stats_level, 1).
% 1.57/1.77     dependent: assign(pick_semantic_ratio, 3).
% 1.57/1.77     dependent: assign(sos_limit, 5000).
% 1.57/1.77     dependent: assign(max_weight, 60).
% 1.57/1.77  clear(print_given).
% 1.57/1.77  
% 1.57/1.77  list(usable).
% 1.57/1.77  
% 1.57/1.77  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=19.
% 1.57/1.77  
% 1.57/1.77  This is a non-Horn set without equality.  The strategy
% 1.57/1.77  will be ordered hyper_res, ur_res, unit deletion, and
% 1.57/1.77  factoring, with satellites in sos and nuclei in usable.
% 1.57/1.77  
% 1.57/1.77     dependent: set(hyper_res).
% 1.57/1.77     dependent: set(factor).
% 1.57/1.77     dependent: set(unit_deletion).
% 1.57/1.77  
% 1.57/1.77  ------------> process usable:
% 1.57/1.77  29 back subsumes 28.
% 1.57/1.77  29 back subsumes 23.
% 1.57/1.77  
% 1.57/1.77  ------------> process sos:
% 1.57/1.77  
% 1.57/1.77  ======= end of input processing =======
% 2.52/2.75  
% 2.52/2.75  Model 1 (0.00 seconds, 0 Inserts)
% 2.52/2.75  
% 2.52/2.75  Stopped by limit on number of solutions
% 2.52/2.75  
% 2.52/2.75  
% 2.52/2.75  -------------- Softie stats --------------
% 2.52/2.75  
% 2.52/2.75  UPDATE_STOP: 300
% 2.52/2.75  SFINDER_TIME_LIMIT: 2
% 2.52/2.75  SHORT_CLAUSE_CUTOFF: 4
% 2.52/2.75  number of clauses in intial UL: 34
% 2.52/2.75  number of clauses initially in problem: 35
% 2.52/2.75  percentage of clauses intially in UL: 97
% 2.52/2.75  percentage of distinct symbols occuring in initial UL: 100
% 2.52/2.75  percent of all initial clauses that are short: 100
% 2.52/2.75  absolute distinct symbol count: 8
% 2.52/2.75     distinct predicate count: 3
% 2.52/2.75     distinct function count: 3
% 2.52/2.75     distinct constant count: 2
% 2.52/2.75  
% 2.52/2.75  ---------- no more Softie stats ----------
% 2.52/2.75  
% 2.52/2.75  
% 2.52/2.75  
% 2.52/2.75  Stopped by limit on insertions
% 2.52/2.75  
% 2.52/2.75  =========== start of search ===========
% 2.59/2.85  
% 2.59/2.85  -------- PROOF -------- 
% 2.59/2.85  % SZS status Unsatisfiable
% 2.59/2.85  % SZS output start Refutation
% 2.59/2.85  
% 2.59/2.85  Stopped by limit on insertions
% 2.59/2.85  
% 2.59/2.85  Model 2 [ 1 0 326 ] (0.00 seconds, 250000 Inserts)
% 2.59/2.85  
% 2.59/2.85  -----> EMPTY CLAUSE at   2.47 sec ----> 48 [hyper,47,30,42,47,44,42,44,41,41,46,46] {-} $F.
% 2.59/2.85  
% 2.59/2.85  Length of proof is 11.  Level of proof is 5.
% 2.59/2.85  
% 2.59/2.85  ---------------- PROOF ----------------
% 2.59/2.85  % SZS status Unsatisfiable
% 2.59/2.85  % SZS output start Refutation
% 2.59/2.85  
% 2.59/2.85  3 [] {+} -'E'('0',f(suc(A)))| -iLEQ(suc(B),suc(C))| -'E'('0',f(suc(D)))| -'E'('0',f(A))| -'E'('0',f(D))| -'E'('0',f(C))| -'E'('0',f(suc(B)))| -iLEQ(suc(D),suc(A))| -'E'('0',f(suc(C)))| -'E'('0',f(B))| -iLEQ(suc(A),suc(B))|'E'(f(D),f(suc(D)))|'E'(f(A),f(suc(A)))|'E'(f(B),f(suc(B)))|'E'(f(C),f(suc(C))).
% 2.59/2.85  4 [] {+} -'E'('0',f(suc(suc(A))))| -'E'('0',f(suc(A)))| -'E'(f(A),f(suc(A)))| -'E'('0',f(A))|iLEQ(suc(A),suc(A)).
% 2.59/2.85  6 [] {+} -'LE'(f(suc(A)),s('0'))|'E'('0',f(suc(A)))|'LE'(f(A),'0').
% 2.59/2.85  10 [] {+} -'E'('0',f(suc(A)))| -iLEQ(suc(B),suc(C))| -'E'('0',f(suc(suc(A))))| -'E'('0',f(suc(D)))| -'E'('0',f(suc(suc(D))))| -'E'('0',f(A))| -'E'('0',f(D))| -'E'('0',f(C))| -'E'('0',f(suc(B)))| -'E'(f(B),f(suc(B)))| -'E'('0',f(suc(suc(B))))| -'E'(f(D),f(suc(D)))| -'E'(f(A),f(suc(A)))| -iLEQ(suc(D),suc(A))| -'E'('0',f(suc(C)))| -'E'('0',f(B))| -'E'('0',f(suc(suc(C))))| -'E'(f(C),f(suc(C)))| -iLEQ(suc(A),suc(B)).
% 2.59/2.85  11 [] {+} -'LE'(f(A),s('0'))|'E'('0',f(A))|'LE'(f(A),'0').
% 2.59/2.85  13 [] {+} -'LE'(f(suc(suc(A))),s('0'))|'E'('0',f(suc(suc(A))))|'LE'(f(A),'0').
% 2.59/2.85  15 [] {+} -'LE'(f(z),'0').
% 2.59/2.85  21 [] {+} -'E'('0',f(A))| -'E'('0',f(suc(A)))|'E'(f(A),f(suc(A)))|iLEQ(suc(A),suc(A)).
% 2.59/2.85  27 [factor,3.3.9,factor_simp,factor_simp] {+} -'E'('0',f(suc(A)))| -iLEQ(suc(B),suc(C))| -'E'('0',f(suc(C)))| -'E'('0',f(A))| -'E'('0',f(C))| -'E'('0',f(suc(B)))| -iLEQ(suc(C),suc(A))| -'E'('0',f(B))| -iLEQ(suc(A),suc(B))|'E'(f(C),f(suc(C)))|'E'(f(A),f(suc(A)))|'E'(f(B),f(suc(B))).
% 2.59/2.85  30 [factor,10.1.15,factor_simp,factor_simp,factor_simp,factor_simp,factor_simp,factor_simp,factor_simp,factor_simp] {+} -'E'('0',f(suc(A)))| -iLEQ(suc(B),suc(A))| -'E'('0',f(suc(suc(A))))| -'E'('0',f(suc(B)))| -'E'('0',f(suc(suc(B))))| -'E'('0',f(A))| -'E'('0',f(B))| -'E'(f(B),f(suc(B)))| -'E'(f(A),f(suc(A)))| -iLEQ(suc(A),suc(B)).
% 2.59/2.85  37 [] {-} 'LE'(f(A),s('0')).
% 2.59/2.85  38 [hyper,37,13] {-} 'E'('0',f(suc(suc(A))))|'LE'(f(A),'0').
% 2.59/2.85  39 [hyper,37,11] {+} 'E'('0',f(A))|'LE'(f(A),'0').
% 2.59/2.85  40 [hyper,37,6] {-} 'E'('0',f(suc(A)))|'LE'(f(A),'0').
% 2.59/2.85  41 [hyper,39,15] {+} 'E'('0',f(z)).
% 2.59/2.85  42 [hyper,40,15] {-} 'E'('0',f(suc(z))).
% 2.59/2.85  43 [hyper,41,21,42] {+} 'E'(f(z),f(suc(z)))|iLEQ(suc(z),suc(z)).
% 2.59/2.85  44 [hyper,38,15] {-} 'E'('0',f(suc(suc(z)))).
% 2.59/2.85  46 [hyper,43,27,42,43,42,41,41,42,43,41,factor_simp,factor_simp,factor_simp,factor_simp,factor_simp] {+} 'E'(f(z),f(suc(z))).
% 2.59/2.85  47 [hyper,46,4,44,42,41] {+} iLEQ(suc(z),suc(z)).
% 2.59/2.85  48 [hyper,47,30,42,47,44,42,44,41,41,46,46] {-} $F.
% 2.59/2.85  
% 2.59/2.85  % SZS output end Refutation
% 2.59/2.85  ------------ end of proof -------------
% 2.59/2.85  
% 2.59/2.85  
% 2.59/2.85  Search stopped by max_proofs option.
% 2.59/2.85  
% 2.59/2.85  
% 2.59/2.85  Search stopped by max_proofs option.
% 2.59/2.85  
% 2.59/2.85  ============ end of search ============
% 2.59/2.85  
% 2.59/2.85  ----------- soft-scott stats ----------
% 2.59/2.85  
% 2.59/2.85  true clauses given           4      (40.0%)
% 2.59/2.85  false clauses given          6
% 2.59/2.85  
% 2.59/2.85        FALSE     TRUE
% 2.59/2.85    15  0         1
% 2.59/2.85  tot:  0         1      (100.0% true)
% 2.59/2.85  
% 2.59/2.85  
% 2.59/2.85  Model 2 [ 1 0 326 ] (0.00 seconds, 250000 Inserts)
% 2.59/2.85  
% 2.59/2.85  That finishes the proof of the theorem.
% 2.59/2.85  
% 2.59/2.85  Process 19500 finished Sat Jul  9 08:49:58 2022
%------------------------------------------------------------------------------