TSTP Solution File: SYO638+1 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYO638+1 : TPTP v8.1.0. Released v7.1.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n012.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 19:55:14 EDT 2022
% Result : Satisfiable 0.20s 0.43s
% Output : Saturation 0.20s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SYO638+1 : TPTP v8.1.0. Released v7.1.0.
% 0.07/0.12 % Command : run_spass %d %s
% 0.13/0.34 % Computer : n012.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Fri Jul 8 18:15:14 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.20/0.43
% 0.20/0.43 SPASS V 3.9
% 0.20/0.43 SPASS beiseite: Completion found.
% 0.20/0.43 % SZS status CounterSatisfiable
% 0.20/0.43 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.20/0.43 SPASS derived 1 clauses, backtracked 0 clauses, performed 0 splits and kept 3 clauses.
% 0.20/0.43 SPASS allocated 85055 KBytes.
% 0.20/0.43 SPASS spent 0:00:00.08 on the problem.
% 0.20/0.43 0:00:00.04 for the input.
% 0.20/0.43 0:00:00.02 for the FLOTTER CNF translation.
% 0.20/0.43 0:00:00.00 for inferences.
% 0.20/0.43 0:00:00.00 for the backtracking.
% 0.20/0.43 0:00:00.00 for the reduction.
% 0.20/0.43
% 0.20/0.43
% 0.20/0.43 The saturated set of worked-off clauses is :
% 0.20/0.43 % SZS output start Saturation
% 0.20/0.43 3[0:Inp] || f(u,v)* f(v,w)* -> f(u,w)*.
% 0.20/0.43 4[0:NCh:3.2,3.1,2.0,1.0] || f(skf1(u),u)*l -> .
% 0.20/0.43 2[0:Inp] || f(u,u)* -> .
% 0.20/0.43 1[0:Inp] || -> f(u,skf1(u))*r.
% 0.20/0.43 % SZS output end Saturation
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