TSTP Solution File: SYO629-1 by SPASS---3.9
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% File : SPASS---3.9
% Problem : SYO629-1 : TPTP v8.1.0. Released v7.1.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n028.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 19:55:10 EDT 2022
% Result : Unsatisfiable 0.20s 0.42s
% Output : Refutation 0.20s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : SYO629-1 : TPTP v8.1.0. Released v7.1.0.
% 0.03/0.13 % Command : run_spass %d %s
% 0.14/0.34 % Computer : n028.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 600
% 0.14/0.34 % DateTime : Sat Jul 9 08:14:56 EDT 2022
% 0.14/0.34 % CPUTime :
% 0.20/0.42
% 0.20/0.42 SPASS V 3.9
% 0.20/0.42 SPASS beiseite: Proof found.
% 0.20/0.42 % SZS status Theorem
% 0.20/0.42 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.20/0.42 SPASS derived 12 clauses, backtracked 0 clauses, performed 0 splits and kept 18 clauses.
% 0.20/0.42 SPASS allocated 63097 KBytes.
% 0.20/0.42 SPASS spent 0:00:00.06 on the problem.
% 0.20/0.42 0:00:00.04 for the input.
% 0.20/0.42 0:00:00.00 for the FLOTTER CNF translation.
% 0.20/0.42 0:00:00.00 for inferences.
% 0.20/0.42 0:00:00.00 for the backtracking.
% 0.20/0.42 0:00:00.00 for the reduction.
% 0.20/0.42
% 0.20/0.42
% 0.20/0.42 Here is a proof with depth 5, length 21 :
% 0.20/0.42 % SZS output start Refutation
% 0.20/0.42 3[0:Inp] || E(0,f(u)) E(0,f(g(u))) -> E(f(u),f(g(u)))*.
% 0.20/0.42 4[0:Inp] || -> LE(f(u),s(0)) E(s(0),f(u))*.
% 0.20/0.42 5[0:Inp] || LE(f(u),0)* -> .
% 0.20/0.42 6[0:Inp] || LE(f(u),s(0))* iLEQ(u,v)* -> E(0,f(v))* LE(f(v),0).
% 0.20/0.42 7[0:Inp] || E(s(0),f(u)) E(s(0),f(g(u))) -> E(f(u),f(g(u)))*.
% 0.20/0.42 10[0:Inp] || -> iLEQ(u,g(u))*.
% 0.20/0.42 11[0:Inp] || E(f(u),f(g(u)))* -> .
% 0.20/0.42 12[0:Inp] || -> iLEQ(u,u)*.
% 0.20/0.42 13[0:MRR:3.2,11.0] || E(0,f(u)) E(0,f(g(u)))* -> .
% 0.20/0.42 14[0:MRR:6.3,5.0] || iLEQ(u,v)* LE(f(u),s(0))*+ -> E(0,f(v))*.
% 0.20/0.42 15[0:MRR:7.2,11.0] || E(s(0),f(u)) E(s(0),f(g(u)))* -> .
% 0.20/0.42 16[0:Res:4.1,15.1] || E(s(0),f(u)) -> LE(f(g(u)),s(0))*.
% 0.20/0.42 17[0:Res:16.1,14.1] || E(s(0),f(u))*+ iLEQ(g(u),v)* -> E(0,f(v))*.
% 0.20/0.42 18[0:Res:4.1,17.0] || iLEQ(g(u),v)*+ -> LE(f(u),s(0))* E(0,f(v))*.
% 0.20/0.42 19[0:Res:12.0,18.0] || -> LE(f(u),s(0)) E(0,f(g(u)))*.
% 0.20/0.42 20[0:Res:10.0,18.0] || -> LE(f(u),s(0)) E(0,f(g(g(u))))*.
% 0.20/0.42 23[0:Res:20.1,13.1] || E(0,f(g(u)))* -> LE(f(u),s(0)).
% 0.20/0.42 24[0:MRR:23.0,19.1] || -> LE(f(u),s(0))*.
% 0.20/0.42 25[0:MRR:14.1,24.0] || iLEQ(u,v)*+ -> E(0,f(v))*.
% 0.20/0.42 26[0:Res:12.0,25.0] || -> E(0,f(u))*.
% 0.20/0.42 28[0:MRR:13.0,13.1,26.0] || -> .
% 0.20/0.42 % SZS output end Refutation
% 0.20/0.42 Formulae used in the proof : clause_11_03 clause_6_04 clause_7_05 clause_10_06 clause_1_07 clause_5_10 clause_4_11 clause_9_12
% 0.20/0.42
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