TSTP Solution File: SYO614-1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYO614-1 : TPTP v8.1.0. Released v7.1.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 19:55:05 EDT 2022
% Result : Unsatisfiable 0.18s 0.42s
% Output : Refutation 0.18s
% Verified :
% SZS Type : Refutation
% Derivation depth : 7
% Number of leaves : 6
% Syntax : Number of clauses : 18 ( 6 unt; 1 nHn; 18 RR)
% Number of literals : 32 ( 0 equ; 21 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 4 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 8 ( 8 usr; 5 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
le(u,u),
file('SYO614-1.p',unknown),
[] ).
cnf(2,axiom,
( ~ le(max(u,v),w)
| le(u,w) ),
file('SYO614-1.p',unknown),
[] ).
cnf(3,axiom,
( ~ le(max(u,v),w)
| le(v,w) ),
file('SYO614-1.p',unknown),
[] ).
cnf(4,axiom,
( eq(f(u),a1)
| eq(f(u),a0) ),
file('SYO614-1.p',unknown),
[] ).
cnf(5,axiom,
( ~ le(s(u),v)
| ~ eq(f(v),a0)
| ~ eq(f(u),a0) ),
file('SYO614-1.p',unknown),
[] ).
cnf(6,axiom,
( ~ le(s(u),v)
| ~ eq(f(v),a1)
| ~ eq(f(u),a1) ),
file('SYO614-1.p',unknown),
[] ).
cnf(7,plain,
le(u,max(v,u)),
inference(res,[status(thm),theory(equality)],[1,3]),
[iquote('0:Res:1.0,3.0')] ).
cnf(9,plain,
le(u,max(u,v)),
inference(res,[status(thm),theory(equality)],[1,2]),
[iquote('0:Res:1.0,2.0')] ).
cnf(19,plain,
( ~ eq(f(s(u)),a1)
| ~ eq(f(u),a1) ),
inference(res,[status(thm),theory(equality)],[1,6]),
[iquote('0:Res:1.0,6.0')] ).
cnf(23,plain,
( ~ eq(f(max(s(u),v)),a1)
| ~ eq(f(u),a1) ),
inference(res,[status(thm),theory(equality)],[9,6]),
[iquote('0:Res:9.0,6.0')] ).
cnf(37,plain,
( ~ eq(f(s(u)),a0)
| ~ eq(f(u),a0) ),
inference(res,[status(thm),theory(equality)],[1,5]),
[iquote('0:Res:1.0,5.0')] ).
cnf(38,plain,
( ~ eq(f(max(u,s(v))),a0)
| ~ eq(f(v),a0) ),
inference(res,[status(thm),theory(equality)],[7,5]),
[iquote('0:Res:7.0,5.0')] ).
cnf(67,plain,
( ~ eq(f(u),a0)
| eq(f(s(u)),a1) ),
inference(res,[status(thm),theory(equality)],[4,37]),
[iquote('0:Res:4.1,37.0')] ).
cnf(102,plain,
( ~ eq(f(u),a0)
| eq(f(max(v,s(u))),a1) ),
inference(res,[status(thm),theory(equality)],[4,38]),
[iquote('0:Res:4.1,38.0')] ).
cnf(137,plain,
( ~ eq(f(u),a0)
| ~ eq(f(v),a1) ),
inference(res,[status(thm),theory(equality)],[102,23]),
[iquote('0:Res:102.1,23.0')] ).
cnf(138,plain,
~ eq(f(u),a0),
inference(mrr,[status(thm)],[67,137]),
[iquote('0:MRR:67.1,137.1')] ).
cnf(141,plain,
eq(f(u),a1),
inference(mrr,[status(thm)],[4,138]),
[iquote('0:MRR:4.1,138.0')] ).
cnf(143,plain,
$false,
inference(mrr,[status(thm)],[19,141]),
[iquote('0:MRR:19.0,19.1,141.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : SYO614-1 : TPTP v8.1.0. Released v7.1.0.
% 0.06/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n009.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Sat Jul 9 11:42:07 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.42
% 0.18/0.42 SPASS V 3.9
% 0.18/0.42 SPASS beiseite: Proof found.
% 0.18/0.42 % SZS status Theorem
% 0.18/0.42 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.18/0.42 SPASS derived 167 clauses, backtracked 0 clauses, performed 0 splits and kept 138 clauses.
% 0.18/0.42 SPASS allocated 63353 KBytes.
% 0.18/0.42 SPASS spent 0:00:00.08 on the problem.
% 0.18/0.42 0:00:00.04 for the input.
% 0.18/0.42 0:00:00.00 for the FLOTTER CNF translation.
% 0.18/0.42 0:00:00.00 for inferences.
% 0.18/0.42 0:00:00.00 for the backtracking.
% 0.18/0.42 0:00:00.01 for the reduction.
% 0.18/0.42
% 0.18/0.42
% 0.18/0.42 Here is a proof with depth 4, length 18 :
% 0.18/0.42 % SZS output start Refutation
% See solution above
% 0.18/0.42 Formulae used in the proof : sos_01 sos_02 sos_03 sos_04 sos_05 sos_06
% 0.18/0.42
%------------------------------------------------------------------------------