TSTP Solution File: SYO367^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SYO367^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n001.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:22:16 EDT 2023
% Result : Theorem 3.61s 3.78s
% Output : Proof 3.61s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYO367^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n001.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 04:24:14 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.61/3.78 SZS status Theorem for theBenchmark.p
% 3.61/3.78 SZS output start Proof for theBenchmark.p
% 3.61/3.78 Clause #0 (by assumption #[]): Eq (Not (cC cA → cC (Not (Not cA)))) True
% 3.61/3.78 Clause #1 (by clausification #[0]): Eq (cC cA → cC (Not (Not cA))) False
% 3.61/3.78 Clause #2 (by clausification #[1]): Eq (cC cA) True
% 3.61/3.78 Clause #3 (by clausification #[1]): Eq (cC (Not (Not cA))) False
% 3.61/3.78 Clause #4 (by identity loobHoist #[2]): Or (Eq (cC True) True) (Eq cA False)
% 3.61/3.78 Clause #5 (by identity boolHoist #[2]): Or (Eq (cC False) True) (Eq cA True)
% 3.61/3.78 Clause #6 (by bool simp #[3]): Eq (cC cA) False
% 3.61/3.78 Clause #7 (by identity loobHoist #[6]): Or (Eq (cC True) False) (Eq cA False)
% 3.61/3.78 Clause #8 (by identity boolHoist #[6]): Or (Eq (cC False) False) (Eq cA True)
% 3.61/3.78 Clause #9 (by superposition #[8, 5]): Or (Eq cA True) (Or (Eq False True) (Eq cA True))
% 3.61/3.78 Clause #10 (by clausification #[9]): Or (Eq cA True) (Eq cA True)
% 3.61/3.78 Clause #11 (by eliminate duplicate literals #[10]): Eq cA True
% 3.61/3.78 Clause #12 (by backward demodulation #[11, 4]): Or (Eq (cC True) True) (Eq True False)
% 3.61/3.78 Clause #14 (by backward demodulation #[11, 7]): Or (Eq (cC True) False) (Eq True False)
% 3.61/3.78 Clause #16 (by clausification #[12]): Eq (cC True) True
% 3.61/3.78 Clause #17 (by clausification #[14]): Eq (cC True) False
% 3.61/3.78 Clause #18 (by superposition #[17, 16]): Eq False True
% 3.61/3.78 Clause #19 (by clausification #[18]): False
% 3.61/3.78 SZS output end Proof for theBenchmark.p
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