TSTP Solution File: SYO367^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO367^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n001.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:22:16 EDT 2023

% Result   : Theorem 3.61s 3.78s
% Output   : Proof 3.61s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYO367^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n001.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Sat Aug 26 04:24:14 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.61/3.78  SZS status Theorem for theBenchmark.p
% 3.61/3.78  SZS output start Proof for theBenchmark.p
% 3.61/3.78  Clause #0 (by assumption #[]): Eq (Not (cC cA → cC (Not (Not cA)))) True
% 3.61/3.78  Clause #1 (by clausification #[0]): Eq (cC cA → cC (Not (Not cA))) False
% 3.61/3.78  Clause #2 (by clausification #[1]): Eq (cC cA) True
% 3.61/3.78  Clause #3 (by clausification #[1]): Eq (cC (Not (Not cA))) False
% 3.61/3.78  Clause #4 (by identity loobHoist #[2]): Or (Eq (cC True) True) (Eq cA False)
% 3.61/3.78  Clause #5 (by identity boolHoist #[2]): Or (Eq (cC False) True) (Eq cA True)
% 3.61/3.78  Clause #6 (by bool simp #[3]): Eq (cC cA) False
% 3.61/3.78  Clause #7 (by identity loobHoist #[6]): Or (Eq (cC True) False) (Eq cA False)
% 3.61/3.78  Clause #8 (by identity boolHoist #[6]): Or (Eq (cC False) False) (Eq cA True)
% 3.61/3.78  Clause #9 (by superposition #[8, 5]): Or (Eq cA True) (Or (Eq False True) (Eq cA True))
% 3.61/3.78  Clause #10 (by clausification #[9]): Or (Eq cA True) (Eq cA True)
% 3.61/3.78  Clause #11 (by eliminate duplicate literals #[10]): Eq cA True
% 3.61/3.78  Clause #12 (by backward demodulation #[11, 4]): Or (Eq (cC True) True) (Eq True False)
% 3.61/3.78  Clause #14 (by backward demodulation #[11, 7]): Or (Eq (cC True) False) (Eq True False)
% 3.61/3.78  Clause #16 (by clausification #[12]): Eq (cC True) True
% 3.61/3.78  Clause #17 (by clausification #[14]): Eq (cC True) False
% 3.61/3.78  Clause #18 (by superposition #[17, 16]): Eq False True
% 3.61/3.78  Clause #19 (by clausification #[18]): False
% 3.61/3.78  SZS output end Proof for theBenchmark.p
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