TSTP Solution File: SYO327^5 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SYO327^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n010.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Mar 29 00:51:10 EDT 2022

% Result   : Unknown 0.85s 1.00s
% Output   : None 
% Verified : 
% SZS Type : -

% Comments : 
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%----No solution output by system
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.10  % Problem    : SYO327^5 : TPTP v7.5.0. Released v4.0.0.
% 0.00/0.11  % Command    : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.12/0.32  % Computer   : n010.cluster.edu
% 0.12/0.32  % Model      : x86_64 x86_64
% 0.12/0.32  % CPUModel   : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32  % RAMPerCPU  : 8042.1875MB
% 0.12/0.32  % OS         : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32  % CPULimit   : 300
% 0.12/0.32  % DateTime   : Sat Mar 12 03:52:37 EST 2022
% 0.12/0.32  % CPUTime    : 
% 0.17/0.33  ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.17/0.33  Python 2.7.5
% 0.85/1.00  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.85/1.00  FOF formula (<kernel.Constant object at 0x1a4e6c8>, <kernel.DependentProduct object at 0x1a4e878>) of role type named cHALF
% 0.85/1.00  Using role type
% 0.85/1.00  Declaring cHALF:(fofType->(fofType->Prop))
% 0.85/1.00  FOF formula (<kernel.Constant object at 0x1a52d88>, <kernel.DependentProduct object at 0x1a2cc68>) of role type named cDOUBLE
% 0.85/1.00  Using role type
% 0.85/1.00  Declaring cDOUBLE:(fofType->(fofType->Prop))
% 0.85/1.00  FOF formula (<kernel.Constant object at 0x1a4edd0>, <kernel.DependentProduct object at 0x1a2ce18>) of role type named cS
% 0.85/1.00  Using role type
% 0.85/1.00  Declaring cS:(fofType->fofType)
% 0.85/1.00  FOF formula (<kernel.Constant object at 0x1a4e320>, <kernel.Single object at 0x1a4e6c8>) of role type named c0
% 0.85/1.00  Using role type
% 0.85/1.00  Declaring c0:fofType
% 0.85/1.00  FOF formula (((and ((and ((and (forall (Q:(fofType->(fofType->Prop))) (Xu:fofType) (Xv:fofType), (((and ((and ((cDOUBLE Xu) Xv)) ((Q c0) c0))) (forall (Xx:fofType) (Xy:fofType), (((Q Xx) Xy)->((Q (cS Xx)) (cS (cS Xy))))))->((Q Xu) Xv)))) ((cHALF c0) c0))) ((cHALF c0) (cS c0)))) (forall (Xx:fofType) (Xy:fofType), (((cHALF Xx) Xy)->((cHALF (cS (cS Xx))) (cS Xy)))))->(forall (Xu:fofType) (Xv:fofType), (((cDOUBLE Xu) Xv)->((cHALF Xv) Xu)))) of role conjecture named cDOUBLE_TO_HALF_6
% 0.85/1.00  Conjecture to prove = (((and ((and ((and (forall (Q:(fofType->(fofType->Prop))) (Xu:fofType) (Xv:fofType), (((and ((and ((cDOUBLE Xu) Xv)) ((Q c0) c0))) (forall (Xx:fofType) (Xy:fofType), (((Q Xx) Xy)->((Q (cS Xx)) (cS (cS Xy))))))->((Q Xu) Xv)))) ((cHALF c0) c0))) ((cHALF c0) (cS c0)))) (forall (Xx:fofType) (Xy:fofType), (((cHALF Xx) Xy)->((cHALF (cS (cS Xx))) (cS Xy)))))->(forall (Xu:fofType) (Xv:fofType), (((cDOUBLE Xu) Xv)->((cHALF Xv) Xu)))):Prop
% 0.85/1.00  We need to prove ['(((and ((and ((and (forall (Q:(fofType->(fofType->Prop))) (Xu:fofType) (Xv:fofType), (((and ((and ((cDOUBLE Xu) Xv)) ((Q c0) c0))) (forall (Xx:fofType) (Xy:fofType), (((Q Xx) Xy)->((Q (cS Xx)) (cS (cS Xy))))))->((Q Xu) Xv)))) ((cHALF c0) c0))) ((cHALF c0) (cS c0)))) (forall (Xx:fofType) (Xy:fofType), (((cHALF Xx) Xy)->((cHALF (cS (cS Xx))) (cS Xy)))))->(forall (Xu:fofType) (Xv:fofType), (((cDOUBLE Xu) Xv)->((cHALF Xv) Xu))))']
% 0.85/1.00  Parameter fofType:Type.
% 0.85/1.00  Parameter cHALF:(fofType->(fofType->Prop)).
% 0.85/1.00  Parameter cDOUBLE:(fofType->(fofType->Prop)).
% 0.85/1.00  Parameter cS:(fofType->fofType).
% 0.85/1.00  Parameter c0:fofType.
% 0.85/1.00  Trying to prove (((and ((and ((and (forall (Q:(fofType->(fofType->Prop))) (Xu:fofType) (Xv:fofType), (((and ((and ((cDOUBLE Xu) Xv)) ((Q c0) c0))) (forall (Xx:fofType) (Xy:fofType), (((Q Xx) Xy)->((Q (cS Xx)) (cS (cS Xy))))))->((Q Xu) Xv)))) ((cHALF c0) c0))) ((cHALF c0) (cS c0)))) (forall (Xx:fofType) (Xy:fofType), (((cHALF Xx) Xy)->((cHALF (cS (cS Xx))) (cS Xy)))))->(forall (Xu:fofType) (Xv:fofType), (((cDOUBLE Xu) Xv)->((cHALF Xv) Xu))))
% 0.85/1.00  Found x6:((cHALF c0) c0)
% 0.85/1.00  Found x6 as proof of ((cHALF c0) c0)
% 0.85/1.00  % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
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