TSTP Solution File: SYO232^5 by cocATP---0.2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SYO232^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n005.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:50:58 EDT 2022
% Result : Theorem 0.61s 0.78s
% Output : Proof 0.61s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11 % Problem : SYO232^5 : TPTP v7.5.0. Released v4.0.0.
% 0.07/0.12 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.13/0.33 % Computer : n005.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % RAMPerCPU : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % DateTime : Fri Mar 11 20:22:27 EST 2022
% 0.13/0.33 % CPUTime :
% 0.13/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.13/0.34 Python 2.7.5
% 0.61/0.78 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.61/0.78 FOF formula (<kernel.Constant object at 0xb02fc8>, <kernel.Type object at 0xb02d40>) of role type named a_type
% 0.61/0.78 Using role type
% 0.61/0.78 Declaring a:Type
% 0.61/0.78 FOF formula (<kernel.Constant object at 0x2b6081ea4ab8>, <kernel.DependentProduct object at 0xb02248>) of role type named cP
% 0.61/0.78 Using role type
% 0.61/0.78 Declaring cP:(a->Prop)
% 0.61/0.78 FOF formula (<kernel.Constant object at 0xb02ef0>, <kernel.Constant object at 0xb02248>) of role type named x
% 0.61/0.78 Using role type
% 0.61/0.78 Declaring x:a
% 0.61/0.78 FOF formula (<kernel.Constant object at 0xb02fc8>, <kernel.Sort object at 0x2b6081e9d638>) of role type named cB
% 0.61/0.78 Using role type
% 0.61/0.78 Declaring cB:Prop
% 0.61/0.78 FOF formula (<kernel.Constant object at 0xb02e60>, <kernel.Constant object at 0xb02ef0>) of role type named y
% 0.61/0.78 Using role type
% 0.61/0.78 Declaring y:fofType
% 0.61/0.78 FOF formula (((((eq fofType) y) y)->cB)->((cP x)->((ex a) (fun (Xx0:a)=> (cP Xx0))))) of role conjecture named cADDHYP4
% 0.61/0.78 Conjecture to prove = (((((eq fofType) y) y)->cB)->((cP x)->((ex a) (fun (Xx0:a)=> (cP Xx0))))):Prop
% 0.61/0.78 We need to prove ['(((((eq fofType) y) y)->cB)->((cP x)->((ex a) (fun (Xx0:a)=> (cP Xx0)))))']
% 0.61/0.78 Parameter a:Type.
% 0.61/0.78 Parameter cP:(a->Prop).
% 0.61/0.78 Parameter x:a.
% 0.61/0.78 Parameter cB:Prop.
% 0.61/0.78 Parameter fofType:Type.
% 0.61/0.78 Parameter y:fofType.
% 0.61/0.78 Trying to prove (((((eq fofType) y) y)->cB)->((cP x)->((ex a) (fun (Xx0:a)=> (cP Xx0)))))
% 0.61/0.78 Found x1:(cP x)
% 0.61/0.78 Found x1 as proof of (cP x)
% 0.61/0.78 Found (ex_intro000 x1) as proof of ((ex a) (fun (Xx0:a)=> (cP Xx0)))
% 0.61/0.78 Found ((ex_intro00 x) x1) as proof of ((ex a) (fun (Xx0:a)=> (cP Xx0)))
% 0.61/0.78 Found (((ex_intro0 (fun (Xx0:a)=> (cP Xx0))) x) x1) as proof of ((ex a) (fun (Xx0:a)=> (cP Xx0)))
% 0.61/0.78 Found ((((ex_intro a) (fun (Xx0:a)=> (cP Xx0))) x) x1) as proof of ((ex a) (fun (Xx0:a)=> (cP Xx0)))
% 0.61/0.78 Found (fun (x1:(cP x))=> ((((ex_intro a) (fun (Xx0:a)=> (cP Xx0))) x) x1)) as proof of ((ex a) (fun (Xx0:a)=> (cP Xx0)))
% 0.61/0.78 Found (fun (x0:((((eq fofType) y) y)->cB)) (x1:(cP x))=> ((((ex_intro a) (fun (Xx0:a)=> (cP Xx0))) x) x1)) as proof of ((cP x)->((ex a) (fun (Xx0:a)=> (cP Xx0))))
% 0.61/0.78 Found (fun (x0:((((eq fofType) y) y)->cB)) (x1:(cP x))=> ((((ex_intro a) (fun (Xx0:a)=> (cP Xx0))) x) x1)) as proof of (((((eq fofType) y) y)->cB)->((cP x)->((ex a) (fun (Xx0:a)=> (cP Xx0)))))
% 0.61/0.78 Got proof (fun (x0:((((eq fofType) y) y)->cB)) (x1:(cP x))=> ((((ex_intro a) (fun (Xx0:a)=> (cP Xx0))) x) x1))
% 0.61/0.78 Time elapsed = 0.152918s
% 0.61/0.78 node=36 cost=330.000000 depth=7
% 0.61/0.78 ::::::::::::::::::::::
% 0.61/0.78 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.61/0.78 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.61/0.78 (fun (x0:((((eq fofType) y) y)->cB)) (x1:(cP x))=> ((((ex_intro a) (fun (Xx0:a)=> (cP Xx0))) x) x1))
% 0.61/0.78 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
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