TSTP Solution File: SYO200^5 by Duper---1.0

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% File     : Duper---1.0
% Problem  : SYO200^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:21:49 EDT 2023

% Result   : Theorem 3.67s 3.87s
% Output   : Proof 3.67s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYO200^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.15/0.35  % Computer : n008.cluster.edu
% 0.15/0.35  % Model    : x86_64 x86_64
% 0.15/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.35  % Memory   : 8042.1875MB
% 0.15/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.35  % CPULimit   : 300
% 0.15/0.35  % WCLimit    : 300
% 0.15/0.35  % DateTime   : Sat Aug 26 07:33:32 EDT 2023
% 0.15/0.35  % CPUTime    : 
% 3.67/3.87  SZS status Theorem for theBenchmark.p
% 3.67/3.87  SZS output start Proof for theBenchmark.p
% 3.67/3.87  Clause #0 (by assumption #[]): Eq (Not (∀ (Xx Xy : Prop), Exists fun Xp => Xp Xx → Xp Xy)) True
% 3.67/3.87  Clause #1 (by clausification #[0]): Eq (∀ (Xx Xy : Prop), Exists fun Xp => Xp Xx → Xp Xy) False
% 3.67/3.87  Clause #2 (by clausification #[1]): ∀ (a : Prop), Eq (Not (∀ (Xy : Prop), Exists fun Xp => Xp (skS.0 0 a) → Xp Xy)) True
% 3.67/3.87  Clause #3 (by clausification #[2]): ∀ (a : Prop), Eq (∀ (Xy : Prop), Exists fun Xp => Xp (skS.0 0 a) → Xp Xy) False
% 3.67/3.87  Clause #4 (by clausification #[3]): ∀ (a a_1 : Prop), Eq (Not (Exists fun Xp => Xp (skS.0 0 a) → Xp (skS.0 1 a a_1))) True
% 3.67/3.87  Clause #5 (by clausification #[4]): ∀ (a a_1 : Prop), Eq (Exists fun Xp => Xp (skS.0 0 a) → Xp (skS.0 1 a a_1)) False
% 3.67/3.87  Clause #6 (by clausification #[5]): ∀ (a : Prop → Prop) (a_1 a_2 : Prop), Eq (a (skS.0 0 a_1) → a (skS.0 1 a_1 a_2)) False
% 3.67/3.87  Clause #7 (by clausification #[6]): ∀ (a : Prop → Prop) (a_1 : Prop), Eq (a (skS.0 0 a_1)) True
% 3.67/3.87  Clause #9 (by identity loobHoist #[7]): ∀ (a : Prop → Prop) (a_1 : Prop), Or (Eq (a True) True) (Eq (skS.0 0 a_1) False)
% 3.67/3.87  Clause #10 (by identity boolHoist #[7]): ∀ (a : Prop → Prop) (a_1 : Prop), Or (Eq (a False) True) (Eq (skS.0 0 a_1) True)
% 3.67/3.87  Clause #11 (by identity loobHoist #[9]): ∀ (a : Prop → Prop) (a_1 : Prop), Or (Eq (a True) True) (Or (Eq (skS.0 0 True) False) (Eq a_1 False))
% 3.67/3.87  Clause #13 (by identity loobHoist #[10]): ∀ (a : Prop → Prop) (a_1 : Prop), Or (Eq (a False) True) (Or (Eq (skS.0 0 True) True) (Eq a_1 False))
% 3.67/3.87  Clause #15 (by falseElim #[13]): ∀ (a : Prop → Prop), Or (Eq (a False) True) (Eq (skS.0 0 True) True)
% 3.67/3.87  Clause #16 (by superposition #[15, 11]): ∀ (a a_1 : Prop → Prop) (a_2 : Prop),
% 3.67/3.87    Or (Eq (a False) True) (Or (Eq (a_1 True) True) (Or (Eq True False) (Eq a_2 False)))
% 3.67/3.87  Clause #23 (by clausification #[16]): ∀ (a a_1 : Prop → Prop) (a_2 : Prop), Or (Eq (a False) True) (Or (Eq (a_1 True) True) (Eq a_2 False))
% 3.67/3.87  Clause #25 (by falseElim #[23]): ∀ (a a_1 : Prop → Prop), Or (Eq (a False) True) (Eq (a_1 True) True)
% 3.67/3.87  Clause #59 (by equality factoring #[25]): Or (Ne True True) (Eq ((fun x => x) False) True)
% 3.67/3.87  Clause #60 (by betaEtaReduce #[59]): Or (Ne True True) (Eq False True)
% 3.67/3.87  Clause #61 (by clausification #[60]): Or (Eq False True) (Or (Eq True False) (Eq True False))
% 3.67/3.87  Clause #63 (by clausification #[61]): Or (Eq True False) (Eq True False)
% 3.67/3.87  Clause #64 (by clausification #[63]): Eq True False
% 3.67/3.87  Clause #65 (by clausification #[64]): False
% 3.67/3.87  SZS output end Proof for theBenchmark.p
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