TSTP Solution File: SYO136^5 by cocATP---0.2.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SYO136^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:50:43 EDT 2022
% Result : Theorem 0.50s 0.68s
% Output : Proof 0.50s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : SYO136^5 : TPTP v7.5.0. Released v4.0.0.
% 0.03/0.12 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.12/0.33 % Computer : n018.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % RAMPerCPU : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % DateTime : Fri Mar 11 16:10:08 EST 2022
% 0.12/0.33 % CPUTime :
% 0.12/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.35 Python 2.7.5
% 0.50/0.68 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.50/0.68 FOF formula (<kernel.Constant object at 0x1e99950>, <kernel.DependentProduct object at 0x2ac7eb936f80>) of role type named cQ
% 0.50/0.68 Using role type
% 0.50/0.68 Declaring cQ:(fofType->Prop)
% 0.50/0.68 FOF formula (<kernel.Constant object at 0x1e99518>, <kernel.Single object at 0x1e996c8>) of role type named x
% 0.50/0.68 Using role type
% 0.50/0.68 Declaring x:fofType
% 0.50/0.68 FOF formula (<kernel.Constant object at 0x1e99e18>, <kernel.Sort object at 0x2ac7eb911638>) of role type named cB
% 0.50/0.68 Using role type
% 0.50/0.68 Declaring cB:Prop
% 0.50/0.68 FOF formula (<kernel.Constant object at 0x1e9dea8>, <kernel.DependentProduct object at 0x2ac7eb936128>) of role type named cP
% 0.50/0.68 Using role type
% 0.50/0.68 Declaring cP:(fofType->Prop)
% 0.50/0.68 FOF formula (((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)->((cQ x)->((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0))))) of role conjecture named cADDHYP3
% 0.50/0.68 Conjecture to prove = (((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)->((cQ x)->((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0))))):Prop
% 0.50/0.68 We need to prove ['(((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)->((cQ x)->((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0)))))']
% 0.50/0.68 Parameter fofType:Type.
% 0.50/0.68 Parameter cQ:(fofType->Prop).
% 0.50/0.68 Parameter x:fofType.
% 0.50/0.68 Parameter cB:Prop.
% 0.50/0.68 Parameter cP:(fofType->Prop).
% 0.50/0.68 Trying to prove (((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)->((cQ x)->((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0)))))
% 0.50/0.68 Found x1:(cQ x)
% 0.50/0.68 Found x1 as proof of (cQ x)
% 0.50/0.68 Found (ex_intro000 x1) as proof of ((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0)))
% 0.50/0.68 Found ((ex_intro00 x) x1) as proof of ((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0)))
% 0.50/0.68 Found (((ex_intro0 (fun (Xx0:fofType)=> (cQ Xx0))) x) x1) as proof of ((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0)))
% 0.50/0.68 Found ((((ex_intro fofType) (fun (Xx0:fofType)=> (cQ Xx0))) x) x1) as proof of ((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0)))
% 0.50/0.68 Found (fun (x1:(cQ x))=> ((((ex_intro fofType) (fun (Xx0:fofType)=> (cQ Xx0))) x) x1)) as proof of ((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0)))
% 0.50/0.68 Found (fun (x0:((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)) (x1:(cQ x))=> ((((ex_intro fofType) (fun (Xx0:fofType)=> (cQ Xx0))) x) x1)) as proof of ((cQ x)->((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0))))
% 0.50/0.68 Found (fun (x0:((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)) (x1:(cQ x))=> ((((ex_intro fofType) (fun (Xx0:fofType)=> (cQ Xx0))) x) x1)) as proof of (((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)->((cQ x)->((ex fofType) (fun (Xx0:fofType)=> (cQ Xx0)))))
% 0.50/0.68 Got proof (fun (x0:((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)) (x1:(cQ x))=> ((((ex_intro fofType) (fun (Xx0:fofType)=> (cQ Xx0))) x) x1))
% 0.50/0.68 Time elapsed = 0.059546s
% 0.50/0.68 node=10 cost=324.000000 depth=7
% 0.50/0.68 ::::::::::::::::::::::
% 0.50/0.68 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.50/0.68 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.50/0.68 (fun (x0:((((ex fofType) (fun (Xx0:fofType)=> (cP Xx0)))->cB)->cB)) (x1:(cQ x))=> ((((ex_intro fofType) (fun (Xx0:fofType)=> (cQ Xx0))) x) x1))
% 0.50/0.68 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
%------------------------------------------------------------------------------