TSTP Solution File: SYO129^5 by cocATP---0.2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SYO129^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:50:42 EDT 2022
% Result : Theorem 0.48s 0.67s
% Output : Proof 0.48s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11 % Problem : SYO129^5 : TPTP v7.5.0. Released v4.0.0.
% 0.07/0.12 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.13/0.33 % Computer : n016.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % RAMPerCPU : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % DateTime : Fri Mar 11 16:09:44 EST 2022
% 0.13/0.33 % CPUTime :
% 0.13/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.13/0.34 Python 2.7.5
% 0.48/0.67 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.48/0.67 FOF formula (<kernel.Constant object at 0x203dc68>, <kernel.Constant object at 0x203de18>) of role type named c
% 0.48/0.67 Using role type
% 0.48/0.67 Declaring c:fofType
% 0.48/0.67 FOF formula (<kernel.Constant object at 0x2aadb28ea0e0>, <kernel.DependentProduct object at 0x203df38>) of role type named cP
% 0.48/0.67 Using role type
% 0.48/0.67 Declaring cP:(fofType->Prop)
% 0.48/0.67 FOF formula (<kernel.Constant object at 0x203dc68>, <kernel.Single object at 0x203db90>) of role type named b
% 0.48/0.67 Using role type
% 0.48/0.67 Declaring b:fofType
% 0.48/0.67 FOF formula (<kernel.Constant object at 0x203d9e0>, <kernel.Single object at 0x203da70>) of role type named a
% 0.48/0.67 Using role type
% 0.48/0.67 Declaring a:fofType
% 0.48/0.67 FOF formula ((forall (Xx:fofType), (cP Xx))->((and ((and (cP a)) (cP b))) (cP c))) of role conjecture named cALLCONJ3
% 0.48/0.67 Conjecture to prove = ((forall (Xx:fofType), (cP Xx))->((and ((and (cP a)) (cP b))) (cP c))):Prop
% 0.48/0.67 We need to prove ['((forall (Xx:fofType), (cP Xx))->((and ((and (cP a)) (cP b))) (cP c)))']
% 0.48/0.67 Parameter fofType:Type.
% 0.48/0.67 Parameter c:fofType.
% 0.48/0.67 Parameter cP:(fofType->Prop).
% 0.48/0.67 Parameter b:fofType.
% 0.48/0.67 Parameter a:fofType.
% 0.48/0.67 Trying to prove ((forall (Xx:fofType), (cP Xx))->((and ((and (cP a)) (cP b))) (cP c)))
% 0.48/0.67 Found x0:=(x c):(cP c)
% 0.48/0.67 Found (x c) as proof of (cP c)
% 0.48/0.67 Found (x c) as proof of (cP c)
% 0.48/0.67 Found x0:=(x a):(cP a)
% 0.48/0.67 Found (x a) as proof of (cP a)
% 0.48/0.67 Found (x a) as proof of (cP a)
% 0.48/0.67 Found x0:=(x b):(cP b)
% 0.48/0.67 Found (x b) as proof of (cP b)
% 0.48/0.67 Found (x b) as proof of (cP b)
% 0.48/0.67 Found ((conj10 (x a)) (x b)) as proof of ((and (cP a)) (cP b))
% 0.48/0.67 Found (((conj1 (cP b)) (x a)) (x b)) as proof of ((and (cP a)) (cP b))
% 0.48/0.67 Found ((((conj (cP a)) (cP b)) (x a)) (x b)) as proof of ((and (cP a)) (cP b))
% 0.48/0.67 Found ((((conj (cP a)) (cP b)) (x a)) (x b)) as proof of ((and (cP a)) (cP b))
% 0.48/0.67 Found ((conj00 ((((conj (cP a)) (cP b)) (x a)) (x b))) (x c)) as proof of ((and ((and (cP a)) (cP b))) (cP c))
% 0.48/0.67 Found (((conj0 (cP c)) ((((conj (cP a)) (cP b)) (x a)) (x b))) (x c)) as proof of ((and ((and (cP a)) (cP b))) (cP c))
% 0.48/0.67 Found ((((conj ((and (cP a)) (cP b))) (cP c)) ((((conj (cP a)) (cP b)) (x a)) (x b))) (x c)) as proof of ((and ((and (cP a)) (cP b))) (cP c))
% 0.48/0.67 Found (fun (x:(forall (Xx:fofType), (cP Xx)))=> ((((conj ((and (cP a)) (cP b))) (cP c)) ((((conj (cP a)) (cP b)) (x a)) (x b))) (x c))) as proof of ((and ((and (cP a)) (cP b))) (cP c))
% 0.48/0.67 Found (fun (x:(forall (Xx:fofType), (cP Xx)))=> ((((conj ((and (cP a)) (cP b))) (cP c)) ((((conj (cP a)) (cP b)) (x a)) (x b))) (x c))) as proof of ((forall (Xx:fofType), (cP Xx))->((and ((and (cP a)) (cP b))) (cP c)))
% 0.48/0.67 Got proof (fun (x:(forall (Xx:fofType), (cP Xx)))=> ((((conj ((and (cP a)) (cP b))) (cP c)) ((((conj (cP a)) (cP b)) (x a)) (x b))) (x c)))
% 0.48/0.67 Time elapsed = 0.054870s
% 0.48/0.67 node=14 cost=137.000000 depth=10
% 0.48/0.67 ::::::::::::::::::::::
% 0.48/0.67 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.48/0.67 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.48/0.67 (fun (x:(forall (Xx:fofType), (cP Xx)))=> ((((conj ((and (cP a)) (cP b))) (cP c)) ((((conj (cP a)) (cP b)) (x a)) (x b))) (x c)))
% 0.48/0.67 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
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