TSTP Solution File: SYO087^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO087^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n001.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:21:27 EDT 2023

% Result   : Theorem 3.60s 3.85s
% Output   : Proof 3.60s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYO087^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.14/0.34  % Computer : n001.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Sat Aug 26 06:21:45 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.60/3.85  SZS status Theorem for theBenchmark.p
% 3.60/3.85  SZS output start Proof for theBenchmark.p
% 3.60/3.85  Clause #0 (by assumption #[]): Eq
% 3.60/3.85    (Not
% 3.60/3.85      (Exists fun Xx =>
% 3.60/3.85        And (Not cP) (Or (And cQ (Not cR)) (And (Not cQ) cR)) → Or (And cP cQ) (And (Not cP) (Not cQ)) → cR))
% 3.60/3.85    True
% 3.60/3.85  Clause #1 (by clausification #[0]): Eq
% 3.60/3.85    (Exists fun Xx => And (Not cP) (Or (And cQ (Not cR)) (And (Not cQ) cR)) → Or (And cP cQ) (And (Not cP) (Not cQ)) → cR)
% 3.60/3.85    False
% 3.60/3.85  Clause #2 (by clausification #[1]): Iota → Eq (And (Not cP) (Or (And cQ (Not cR)) (And (Not cQ) cR)) → Or (And cP cQ) (And (Not cP) (Not cQ)) → cR) False
% 3.60/3.85  Clause #3 (by clausification #[2]): Eq (And (Not cP) (Or (And cQ (Not cR)) (And (Not cQ) cR))) True
% 3.60/3.85  Clause #4 (by clausification #[2]): Eq (Or (And cP cQ) (And (Not cP) (Not cQ)) → cR) False
% 3.60/3.85  Clause #5 (by clausification #[3]): Eq (Or (And cQ (Not cR)) (And (Not cQ) cR)) True
% 3.60/3.85  Clause #6 (by clausification #[3]): Eq (Not cP) True
% 3.60/3.85  Clause #7 (by clausification #[5]): Or (Eq (And cQ (Not cR)) True) (Eq (And (Not cQ) cR) True)
% 3.60/3.85  Clause #9 (by clausification #[7]): Or (Eq (And (Not cQ) cR) True) (Eq cQ True)
% 3.60/3.85  Clause #13 (by clausification #[6]): Eq cP False
% 3.60/3.85  Clause #14 (by clausification #[4]): Eq (Or (And cP cQ) (And (Not cP) (Not cQ))) True
% 3.60/3.85  Clause #15 (by clausification #[4]): Eq cR False
% 3.60/3.85  Clause #16 (by clausification #[14]): Or (Eq (And cP cQ) True) (Eq (And (Not cP) (Not cQ)) True)
% 3.60/3.85  Clause #18 (by clausification #[16]): Or (Eq (And (Not cP) (Not cQ)) True) (Eq cP True)
% 3.60/3.85  Clause #23 (by clausification #[9]): Or (Eq cQ True) (Eq cR True)
% 3.60/3.85  Clause #24 (by superposition #[23, 15]): Or (Eq cQ True) (Eq True False)
% 3.60/3.85  Clause #25 (by clausification #[24]): Eq cQ True
% 3.60/3.85  Clause #30 (by clausification #[18]): Or (Eq cP True) (Eq (Not cQ) True)
% 3.60/3.85  Clause #32 (by clausification #[30]): Or (Eq cP True) (Eq cQ False)
% 3.60/3.85  Clause #33 (by forward demodulation #[32, 25]): Or (Eq cP True) (Eq True False)
% 3.60/3.85  Clause #34 (by clausification #[33]): Eq cP True
% 3.60/3.85  Clause #35 (by superposition #[34, 13]): Eq True False
% 3.60/3.85  Clause #36 (by clausification #[35]): False
% 3.60/3.85  SZS output end Proof for theBenchmark.p
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