TSTP Solution File: SYO086^5 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SYO086^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:21:27 EDT 2023
% Result : Theorem 3.38s 3.55s
% Output : Proof 3.38s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYO086^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.35 % Computer : n003.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Sat Aug 26 00:41:08 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.38/3.55 SZS status Theorem for theBenchmark.p
% 3.38/3.55 SZS output start Proof for theBenchmark.p
% 3.38/3.55 Clause #0 (by assumption #[]): Eq (Not (And (Not cP) (Or (And cQ (Not cR)) (And (Not cQ) cR)) → Or (And cP cQ) (And (Not cP) (Not cQ)) → cR)) True
% 3.38/3.55 Clause #1 (by clausification #[0]): Eq (And (Not cP) (Or (And cQ (Not cR)) (And (Not cQ) cR)) → Or (And cP cQ) (And (Not cP) (Not cQ)) → cR) False
% 3.38/3.55 Clause #2 (by clausification #[1]): Eq (And (Not cP) (Or (And cQ (Not cR)) (And (Not cQ) cR))) True
% 3.38/3.55 Clause #3 (by clausification #[1]): Eq (Or (And cP cQ) (And (Not cP) (Not cQ)) → cR) False
% 3.38/3.55 Clause #4 (by clausification #[2]): Eq (Or (And cQ (Not cR)) (And (Not cQ) cR)) True
% 3.38/3.55 Clause #5 (by clausification #[2]): Eq (Not cP) True
% 3.38/3.55 Clause #6 (by clausification #[4]): Or (Eq (And cQ (Not cR)) True) (Eq (And (Not cQ) cR) True)
% 3.38/3.55 Clause #8 (by clausification #[6]): Or (Eq (And (Not cQ) cR) True) (Eq cQ True)
% 3.38/3.55 Clause #12 (by clausification #[5]): Eq cP False
% 3.38/3.55 Clause #13 (by clausification #[3]): Eq (Or (And cP cQ) (And (Not cP) (Not cQ))) True
% 3.38/3.55 Clause #14 (by clausification #[3]): Eq cR False
% 3.38/3.55 Clause #15 (by clausification #[13]): Or (Eq (And cP cQ) True) (Eq (And (Not cP) (Not cQ)) True)
% 3.38/3.55 Clause #17 (by clausification #[15]): Or (Eq (And (Not cP) (Not cQ)) True) (Eq cP True)
% 3.38/3.55 Clause #22 (by clausification #[8]): Or (Eq cQ True) (Eq cR True)
% 3.38/3.55 Clause #23 (by superposition #[22, 14]): Or (Eq cQ True) (Eq True False)
% 3.38/3.55 Clause #24 (by clausification #[23]): Eq cQ True
% 3.38/3.55 Clause #29 (by clausification #[17]): Or (Eq cP True) (Eq (Not cQ) True)
% 3.38/3.55 Clause #31 (by clausification #[29]): Or (Eq cP True) (Eq cQ False)
% 3.38/3.55 Clause #32 (by forward demodulation #[31, 24]): Or (Eq cP True) (Eq True False)
% 3.38/3.55 Clause #33 (by clausification #[32]): Eq cP True
% 3.38/3.55 Clause #34 (by superposition #[33, 12]): Eq True False
% 3.38/3.55 Clause #35 (by clausification #[34]): False
% 3.38/3.55 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------