TSTP Solution File: SYO084^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO084^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n031.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:21:27 EDT 2023

% Result   : Theorem 3.55s 3.78s
% Output   : Proof 3.55s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYO084^5 : TPTP v8.1.2. Released v4.0.0.
% 0.13/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n031.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Sat Aug 26 00:24:52 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 3.55/3.78  SZS status Theorem for theBenchmark.p
% 3.55/3.78  SZS output start Proof for theBenchmark.p
% 3.55/3.78  Clause #0 (by assumption #[]): Eq (Not (Exists fun Xv => ∀ (Xj : Iota), Exists fun Xq => Or (cP a Xj (h Xj)) (cP Xv Xj (k Xj)) → cP Xv Xj Xq)) True
% 3.55/3.78  Clause #1 (by clausification #[0]): Eq (Exists fun Xv => ∀ (Xj : Iota), Exists fun Xq => Or (cP a Xj (h Xj)) (cP Xv Xj (k Xj)) → cP Xv Xj Xq) False
% 3.55/3.78  Clause #2 (by clausification #[1]): ∀ (a_1 : Iota), Eq (∀ (Xj : Iota), Exists fun Xq => Or (cP a Xj (h Xj)) (cP a_1 Xj (k Xj)) → cP a_1 Xj Xq) False
% 3.55/3.78  Clause #3 (by clausification #[2]): ∀ (a_1 a_2 : Iota),
% 3.55/3.78    Eq
% 3.55/3.78      (Not
% 3.55/3.78        (Exists fun Xq =>
% 3.55/3.78          Or (cP a (skS.0 0 a_1 a_2) (h (skS.0 0 a_1 a_2))) (cP a_1 (skS.0 0 a_1 a_2) (k (skS.0 0 a_1 a_2))) →
% 3.55/3.78            cP a_1 (skS.0 0 a_1 a_2) Xq))
% 3.55/3.78      True
% 3.55/3.78  Clause #4 (by clausification #[3]): ∀ (a_1 a_2 : Iota),
% 3.55/3.78    Eq
% 3.55/3.78      (Exists fun Xq =>
% 3.55/3.78        Or (cP a (skS.0 0 a_1 a_2) (h (skS.0 0 a_1 a_2))) (cP a_1 (skS.0 0 a_1 a_2) (k (skS.0 0 a_1 a_2))) →
% 3.55/3.78          cP a_1 (skS.0 0 a_1 a_2) Xq)
% 3.55/3.78      False
% 3.55/3.78  Clause #5 (by clausification #[4]): ∀ (a_1 a_2 a_3 : Iota),
% 3.55/3.78    Eq
% 3.55/3.78      (Or (cP a (skS.0 0 a_1 a_2) (h (skS.0 0 a_1 a_2))) (cP a_1 (skS.0 0 a_1 a_2) (k (skS.0 0 a_1 a_2))) →
% 3.55/3.78        cP a_1 (skS.0 0 a_1 a_2) a_3)
% 3.55/3.78      False
% 3.55/3.78  Clause #6 (by clausification #[5]): ∀ (a_1 a_2 : Iota),
% 3.55/3.78    Eq (Or (cP a (skS.0 0 a_1 a_2) (h (skS.0 0 a_1 a_2))) (cP a_1 (skS.0 0 a_1 a_2) (k (skS.0 0 a_1 a_2)))) True
% 3.55/3.78  Clause #7 (by clausification #[5]): ∀ (a a_1 a_2 : Iota), Eq (cP a (skS.0 0 a a_1) a_2) False
% 3.55/3.78  Clause #8 (by clausification #[6]): ∀ (a_1 a_2 : Iota),
% 3.55/3.78    Or (Eq (cP a (skS.0 0 a_1 a_2) (h (skS.0 0 a_1 a_2))) True) (Eq (cP a_1 (skS.0 0 a_1 a_2) (k (skS.0 0 a_1 a_2))) True)
% 3.55/3.78  Clause #10 (by superposition #[7, 8]): ∀ (a_1 a_2 : Iota), Or (Eq (cP a (skS.0 0 a_1 a_2) (h (skS.0 0 a_1 a_2))) True) (Eq True False)
% 3.55/3.78  Clause #11 (by clausification #[10]): ∀ (a_1 a_2 : Iota), Eq (cP a (skS.0 0 a_1 a_2) (h (skS.0 0 a_1 a_2))) True
% 3.55/3.78  Clause #12 (by superposition #[11, 7]): Eq True False
% 3.55/3.78  Clause #13 (by clausification #[12]): False
% 3.55/3.78  SZS output end Proof for theBenchmark.p
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