TSTP Solution File: SYO058^4 by Satallax---3.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Satallax---3.5
% Problem  : SYO058^4 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 19:29:55 EDT 2022

% Result   : Theorem 0.12s 0.36s
% Output   : Proof 0.12s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SYO058^4 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.12  % Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s
% 0.12/0.33  % Computer : n013.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sat Jul  9 04:13:29 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.12/0.36  % SZS status Theorem
% 0.12/0.36  % Mode: mode213
% 0.12/0.36  % Inferences: 24
% 0.12/0.36  % SZS output start Proof
% 0.12/0.36  thf(ty_a, type, a : ($i>$o)).
% 0.12/0.36  thf(ty_eigen__0, type, eigen__0 : $i).
% 0.12/0.36  thf(sP1,plain,sP1 <=> ((!!) @ a),introduced(definition,[new_symbols(definition,[sP1])])).
% 0.12/0.36  thf(sP2,plain,sP2 <=> (a @ eigen__0),introduced(definition,[new_symbols(definition,[sP2])])).
% 0.12/0.36  thf(def_mnot,definition,(mnot = (^[X1:$i>$o]:(^[X2:$i]:(~((X1 @ X2))))))).
% 0.12/0.36  thf(def_mor,definition,(mor = (^[X1:$i>$o]:(^[X2:$i>$o]:(^[X3:$i]:((~((X1 @ X3))) => (X2 @ X3))))))).
% 0.12/0.36  thf(def_mand,definition,(mand = (^[X1:$i>$o]:(^[X2:$i>$o]:(^[X3:$i]:(~(((X1 @ X3) => (~((X2 @ X3))))))))))).
% 0.12/0.36  thf(def_mimplies,definition,(mimplies = (^[X1:$i>$o]:(mor @ (mnot @ X1))))).
% 0.12/0.36  thf(def_mbox_s4,definition,(mbox_s4 = (^[X1:$i>$o]:(^[X2:$i]:(![X3:$i]:(((irel @ X2) @ X3) => (X1 @ X3))))))).
% 0.12/0.36  thf(def_iatom,definition,(iatom = (^[X1:$i>$o]:X1))).
% 0.12/0.36  thf(def_inot,definition,(inot = (^[X1:$i>$o]:(mnot @ (mbox_s4 @ X1))))).
% 0.12/0.36  thf(def_itrue,definition,(itrue = (^[X1:$i]:(~($false))))).
% 0.12/0.36  thf(def_ifalse,definition,(ifalse = (inot @ itrue))).
% 0.12/0.36  thf(def_iand,definition,(iand = mand)).
% 0.12/0.36  thf(def_ior,definition,(ior = (^[X1:$i>$o]:(^[X2:$i>$o]:((mor @ (mbox_s4 @ X1)) @ (mbox_s4 @ X2)))))).
% 0.12/0.36  thf(def_iimplies,definition,(iimplies = (^[X1:$i>$o]:(^[X2:$i>$o]:((mimplies @ (mbox_s4 @ X1)) @ (mbox_s4 @ X2)))))).
% 0.12/0.36  thf(def_iimplied,definition,(iimplied = (^[X1:$i>$o]:(^[X2:$i>$o]:((iimplies @ X2) @ X1))))).
% 0.12/0.36  thf(def_iequiv,definition,(iequiv = (^[X1:$i>$o]:(^[X2:$i>$o]:((iand @ ((iimplies @ X1) @ X2)) @ ((iimplies @ X2) @ X1)))))).
% 0.12/0.36  thf(def_ixor,definition,(ixor = (^[X1:$i>$o]:(^[X2:$i>$o]:(inot @ ((iequiv @ X1) @ X2)))))).
% 0.12/0.36  thf(def_ivalid,definition,(ivalid = (!!))).
% 0.12/0.36  thf(def_isatisfiable,definition,(isatisfiable = (^[X1:$i>$o]:(~((![X2:$i]:(~((X1 @ X2))))))))).
% 0.12/0.36  thf(def_icountersatisfiable,definition,(icountersatisfiable = (^[X1:$i>$o]:(~(((!!) @ X1)))))).
% 0.12/0.36  thf(def_iinvalid,definition,(iinvalid = (^[X1:$i>$o]:(![X2:$i]:(~((X1 @ X2))))))).
% 0.12/0.36  thf(con,conjecture,sP1).
% 0.12/0.36  thf(h0,negated_conjecture,(~(sP1)),inference(assume_negation,[status(cth)],[con])).
% 0.12/0.36  thf(h1,assumption,(~(sP2)),introduced(assumption,[])).
% 0.12/0.36  thf(1,plain,(~(sP1) | sP2),inference(all_rule,[status(thm)],[])).
% 0.12/0.36  thf(axiom1,axiom,(ivalid @ (iatom @ a))).
% 0.12/0.36  thf(2,plain,sP1,inference(preprocess,[status(thm)],[axiom1]).
% 0.12/0.36  thf(3,plain,$false,inference(prop_unsat,[status(thm),assumptions([h1,h0])],[1,2,h1])).
% 0.12/0.36  thf(4,plain,$false,inference(tab_negall,[status(thm),assumptions([h0]),tab_negall(discharge,[h1]),tab_negall(eigenvar,eigen__0)],[h0,3,h1])).
% 0.12/0.36  thf(0,theorem,sP1,inference(contra,[status(thm),contra(discharge,[h0])],[4,h0])).
% 0.12/0.36  % SZS output end Proof
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