TSTP Solution File: SYO006^1 by cocATP---0.2.0
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- Process Solution
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% File : cocATP---0.2.0
% Problem : SYO006^1 : TPTP v7.5.0. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:50:22 EDT 2022
% Result : Theorem 0.51s 0.67s
% Output : Proof 0.51s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : SYO006^1 : TPTP v7.5.0. Released v3.7.0.
% 0.03/0.12 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.12/0.33 % Computer : n016.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % RAMPerCPU : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % DateTime : Thu Mar 10 23:54:28 EST 2022
% 0.12/0.33 % CPUTime :
% 0.12/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.34 Python 2.7.5
% 0.51/0.67 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.51/0.67 FOF formula (<kernel.Constant object at 0x18e3fc8>, <kernel.DependentProduct object at 0x18c6e60>) of role type named leibeq1_type
% 0.51/0.67 Using role type
% 0.51/0.67 Declaring leibeq:(Prop->(Prop->Prop))
% 0.51/0.67 FOF formula (((eq (Prop->(Prop->Prop))) leibeq) (fun (U:Prop) (V:Prop)=> (forall (Q:(Prop->Prop)), ((Q U)->(Q V))))) of role definition named leibeq1
% 0.51/0.67 A new definition: (((eq (Prop->(Prop->Prop))) leibeq) (fun (U:Prop) (V:Prop)=> (forall (Q:(Prop->Prop)), ((Q U)->(Q V)))))
% 0.51/0.67 Defined: leibeq:=(fun (U:Prop) (V:Prop)=> (forall (Q:(Prop->Prop)), ((Q U)->(Q V))))
% 0.51/0.67 FOF formula (forall (A:Prop) (B:Prop), (((leibeq A) B)->((iff A) B))) of role conjecture named conj
% 0.51/0.67 Conjecture to prove = (forall (A:Prop) (B:Prop), (((leibeq A) B)->((iff A) B))):Prop
% 0.51/0.67 We need to prove ['(forall (A:Prop) (B:Prop), (((leibeq A) B)->((iff A) B)))']
% 0.51/0.67 Definition leibeq:=(fun (U:Prop) (V:Prop)=> (forall (Q:(Prop->Prop)), ((Q U)->(Q V)))):(Prop->(Prop->Prop)).
% 0.51/0.67 Trying to prove (forall (A:Prop) (B:Prop), (((leibeq A) B)->((iff A) B)))
% 0.51/0.67 Found iff_refl0:=(iff_refl A):((iff A) A)
% 0.51/0.67 Found (iff_refl A) as proof of ((iff A) A)
% 0.51/0.67 Found (iff_refl A) as proof of ((iff A) A)
% 0.51/0.67 Found (x0 (iff_refl A)) as proof of ((iff A) B)
% 0.51/0.67 Found ((x (iff A)) (iff_refl A)) as proof of ((iff A) B)
% 0.51/0.67 Found (fun (x:((leibeq A) B))=> ((x (iff A)) (iff_refl A))) as proof of ((iff A) B)
% 0.51/0.67 Found (fun (B:Prop) (x:((leibeq A) B))=> ((x (iff A)) (iff_refl A))) as proof of (((leibeq A) B)->((iff A) B))
% 0.51/0.67 Found (fun (A:Prop) (B:Prop) (x:((leibeq A) B))=> ((x (iff A)) (iff_refl A))) as proof of (forall (B:Prop), (((leibeq A) B)->((iff A) B)))
% 0.51/0.67 Found (fun (A:Prop) (B:Prop) (x:((leibeq A) B))=> ((x (iff A)) (iff_refl A))) as proof of (forall (A:Prop) (B:Prop), (((leibeq A) B)->((iff A) B)))
% 0.51/0.67 Got proof (fun (A:Prop) (B:Prop) (x:((leibeq A) B))=> ((x (iff A)) (iff_refl A)))
% 0.51/0.67 Time elapsed = 0.055535s
% 0.51/0.67 node=10 cost=-46.000000 depth=7
% 0.51/0.67 ::::::::::::::::::::::
% 0.51/0.67 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.51/0.67 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.51/0.67 (fun (A:Prop) (B:Prop) (x:((leibeq A) B))=> ((x (iff A)) (iff_refl A)))
% 0.51/0.67 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
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