TSTP Solution File: SYN986+1.003 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN986+1.003 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:32:32 EDT 2022

% Result   : Theorem 0.20s 0.43s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   13
%            Number of leaves      :    3
% Syntax   : Number of clauses     :   20 (   3 unt;   0 nHn;  20 RR)
%            Number of literals    :   49 (   0 equ;  36 neg)
%            Maximal clause size   :    4 (   2 avg)
%            Maximal term depth    :   16 (   2 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-3 aty)
%            Number of functors    :    6 (   6 usr;   5 con; 0-1 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    r(u,zero,succ(u)),
    file('SYN986+1.003.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ r(u,v,w)
    | ~ r(x,v,u)
    | r(x,succ(v),w) ),
    file('SYN986+1.003.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ r(zero,u,v)
    | ~ r(zero,w,u)
    | ~ r(zero,v,x)
    | ~ r(zero,zero,w) ),
    file('SYN986+1.003.p',unknown),
    [] ).

cnf(5,plain,
    ( ~ r(zero,u,v)
    | ~ r(zero,v,w)
    | ~ r(zero,succ(zero),u) ),
    inference(res,[status(thm),theory(equality)],[1,3]),
    [iquote('0:Res:1.0,3.1')] ).

cnf(9,plain,
    ( ~ r(u,zero,v)
    | r(u,succ(zero),succ(v)) ),
    inference(res,[status(thm),theory(equality)],[1,2]),
    [iquote('0:Res:1.0,2.0')] ).

cnf(11,plain,
    ( ~ r(u,zero,v)
    | ~ r(w,succ(zero),u)
    | r(w,succ(succ(zero)),succ(v)) ),
    inference(res,[status(thm),theory(equality)],[9,2]),
    [iquote('0:Res:9.1,2.0')] ).

cnf(18,plain,
    ( ~ r(zero,zero,u)
    | ~ r(zero,succ(u),v)
    | ~ r(zero,v,w) ),
    inference(res,[status(thm),theory(equality)],[9,5]),
    [iquote('0:Res:9.1,5.2')] ).

cnf(23,plain,
    ( ~ r(u,zero,v)
    | ~ r(succ(v),zero,w)
    | r(u,succ(succ(zero)),succ(w)) ),
    inference(res,[status(thm),theory(equality)],[9,11]),
    [iquote('0:Res:9.1,11.1')] ).

cnf(24,plain,
    ( ~ r(u,zero,v)
    | r(u,succ(succ(zero)),succ(succ(succ(v)))) ),
    inference(res,[status(thm),theory(equality)],[1,23]),
    [iquote('0:Res:1.0,23.1')] ).

cnf(25,plain,
    ( ~ r(u,zero,v)
    | ~ r(w,succ(succ(zero)),u)
    | r(w,succ(succ(succ(zero))),succ(succ(succ(v)))) ),
    inference(res,[status(thm),theory(equality)],[24,2]),
    [iquote('0:Res:24.1,2.0')] ).

cnf(28,plain,
    ( ~ r(zero,zero,u)
    | ~ r(zero,zero,succ(zero))
    | ~ r(zero,succ(succ(succ(u))),v) ),
    inference(res,[status(thm),theory(equality)],[24,18]),
    [iquote('0:Res:24.1,18.1')] ).

cnf(29,plain,
    ( ~ r(zero,zero,u)
    | ~ r(zero,succ(succ(succ(u))),v) ),
    inference(mrr,[status(thm)],[28,1]),
    [iquote('0:MRR:28.1,1.0')] ).

cnf(32,plain,
    ( ~ r(u,zero,v)
    | ~ r(succ(succ(succ(v))),zero,w)
    | r(u,succ(succ(succ(zero))),succ(succ(succ(w)))) ),
    inference(res,[status(thm),theory(equality)],[24,25]),
    [iquote('0:Res:24.1,25.1')] ).

cnf(33,plain,
    ( ~ r(u,zero,v)
    | r(u,succ(succ(succ(zero))),succ(succ(succ(succ(succ(succ(succ(v)))))))) ),
    inference(res,[status(thm),theory(equality)],[1,32]),
    [iquote('0:Res:1.0,32.1')] ).

cnf(34,plain,
    ( ~ r(u,zero,v)
    | ~ r(w,succ(succ(succ(zero))),u)
    | r(w,succ(succ(succ(succ(zero)))),succ(succ(succ(succ(succ(succ(succ(v)))))))) ),
    inference(res,[status(thm),theory(equality)],[33,2]),
    [iquote('0:Res:33.1,2.0')] ).

cnf(40,plain,
    ( ~ r(u,zero,v)
    | ~ r(succ(succ(succ(succ(succ(succ(succ(v))))))),zero,w)
    | r(u,succ(succ(succ(succ(zero)))),succ(succ(succ(succ(succ(succ(succ(w)))))))) ),
    inference(res,[status(thm),theory(equality)],[33,34]),
    [iquote('0:Res:33.1,34.1')] ).

cnf(41,plain,
    ( ~ r(u,zero,v)
    | r(u,succ(succ(succ(succ(zero)))),succ(succ(succ(succ(succ(succ(succ(succ(succ(succ(succ(succ(succ(succ(succ(v)))))))))))))))) ),
    inference(res,[status(thm),theory(equality)],[1,40]),
    [iquote('0:Res:1.0,40.1')] ).

cnf(46,plain,
    ( ~ r(zero,zero,u)
    | ~ r(zero,zero,succ(zero)) ),
    inference(res,[status(thm),theory(equality)],[41,29]),
    [iquote('0:Res:41.1,29.1')] ).

cnf(47,plain,
    ~ r(zero,zero,succ(zero)),
    inference(con,[status(thm)],[46]),
    [iquote('0:Con:46.0')] ).

cnf(48,plain,
    $false,
    inference(mrr,[status(thm)],[47,1]),
    [iquote('0:MRR:47.0,1.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SYN986+1.003 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.12/0.33  % Computer : n022.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Mon Jul 11 15:47:55 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.20/0.43  
% 0.20/0.43  SPASS V 3.9 
% 0.20/0.43  SPASS beiseite: Proof found.
% 0.20/0.43  % SZS status Theorem
% 0.20/0.43  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.43  SPASS derived 37 clauses, backtracked 0 clauses, performed 0 splits and kept 33 clauses.
% 0.20/0.43  SPASS allocated 85121 KBytes.
% 0.20/0.43  SPASS spent	0:00:00.08 on the problem.
% 0.20/0.43  		0:00:00.03 for the input.
% 0.20/0.43  		0:00:00.02 for the FLOTTER CNF translation.
% 0.20/0.43  		0:00:00.00 for inferences.
% 0.20/0.43  		0:00:00.00 for the backtracking.
% 0.20/0.43  		0:00:00.00 for the reduction.
% 0.20/0.43  
% 0.20/0.43  
% 0.20/0.43  Here is a proof with depth 11, length 20 :
% 0.20/0.43  % SZS output start Refutation
% See solution above
% 0.20/0.43  Formulae used in the proof : hyp1 hyp2 ck
% 0.20/0.43  
%------------------------------------------------------------------------------