TSTP Solution File: SYN980+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SYN980+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:25:36 EDT 2022

% Result   : Theorem 1.55s 1.75s
% Output   : Refutation 1.55s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    4
% Syntax   : Number of clauses     :    7 (   3 unt;   1 nHn;   6 RR)
%            Number of literals    :   11 (   0 equ;   4 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    2 (   2 usr;   1 con; 0-1 aty)
%            Number of variables   :    6 (   2 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ r(A)
    | p(f(A),A) ),
    file('SYN980+1.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ p(A,B)
    | q(f(dollar_c1),dollar_c1) ),
    file('SYN980+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ p(A,B)
    | ~ q(A,B) ),
    file('SYN980+1.p',unknown),
    [] ).

cnf(4,axiom,
    ( r(dollar_c1)
    | p(f(A),A) ),
    file('SYN980+1.p',unknown),
    [] ).

cnf(5,plain,
    p(f(dollar_c1),dollar_c1),
    inference(factor_simp,[status(thm)],[inference(hyper,[status(thm)],[4,1])]),
    [iquote('hyper,4,1,factor_simp')] ).

cnf(6,plain,
    q(f(dollar_c1),dollar_c1),
    inference(hyper,[status(thm)],[5,2]),
    [iquote('hyper,5,2')] ).

cnf(7,plain,
    $false,
    inference(hyper,[status(thm)],[6,3,5]),
    [iquote('hyper,6,3,5')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : SYN980+1 : TPTP v8.1.0. Released v3.1.0.
% 0.06/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n017.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 10:23:33 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.55/1.75  ----- Otter 3.3f, August 2004 -----
% 1.55/1.75  The process was started by sandbox2 on n017.cluster.edu,
% 1.55/1.75  Wed Jul 27 10:23:33 2022
% 1.55/1.75  The command was "./otter".  The process ID is 3597.
% 1.55/1.75  
% 1.55/1.75  set(prolog_style_variables).
% 1.55/1.75  set(auto).
% 1.55/1.75     dependent: set(auto1).
% 1.55/1.75     dependent: set(process_input).
% 1.55/1.75     dependent: clear(print_kept).
% 1.55/1.75     dependent: clear(print_new_demod).
% 1.55/1.75     dependent: clear(print_back_demod).
% 1.55/1.75     dependent: clear(print_back_sub).
% 1.55/1.75     dependent: set(control_memory).
% 1.55/1.75     dependent: assign(max_mem, 12000).
% 1.55/1.75     dependent: assign(pick_given_ratio, 4).
% 1.55/1.75     dependent: assign(stats_level, 1).
% 1.55/1.75     dependent: assign(max_seconds, 10800).
% 1.55/1.75  clear(print_given).
% 1.55/1.75  
% 1.55/1.75  formula_list(usable).
% 1.55/1.75  -(all B ((all Y ((r(B)->r(Y))->p(f(Y),Y)))-> (exists X Y (p(X,Y)& (q(f(B),B)->q(X,Y)))))).
% 1.55/1.75  end_of_list.
% 1.55/1.75  
% 1.55/1.75  -------> usable clausifies to:
% 1.55/1.75  
% 1.55/1.75  list(usable).
% 1.55/1.75  0 [] r($c1)|p(f(Y),Y).
% 1.55/1.75  0 [] -r(Y)|p(f(Y),Y).
% 1.55/1.75  0 [] -p(X,X1)|q(f($c1),$c1).
% 1.55/1.75  0 [] -p(X,X1)| -q(X,X1).
% 1.55/1.75  end_of_list.
% 1.55/1.75  
% 1.55/1.75  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=2.
% 1.55/1.75  
% 1.55/1.75  This is a non-Horn set without equality.  The strategy will
% 1.55/1.75  be ordered hyper_res, unit deletion, and factoring, with
% 1.55/1.75  satellites in sos and with nuclei in usable.
% 1.55/1.75  
% 1.55/1.75     dependent: set(hyper_res).
% 1.55/1.75     dependent: set(factor).
% 1.55/1.75     dependent: set(unit_deletion).
% 1.55/1.75  
% 1.55/1.75  ------------> process usable:
% 1.55/1.75  ** KEPT (pick-wt=6): 1 [] -r(A)|p(f(A),A).
% 1.55/1.75  ** KEPT (pick-wt=7): 2 [] -p(A,B)|q(f($c1),$c1).
% 1.55/1.75  ** KEPT (pick-wt=6): 3 [] -p(A,B)| -q(A,B).
% 1.55/1.75  
% 1.55/1.75  ------------> process sos:
% 1.55/1.75  ** KEPT (pick-wt=6): 4 [] r($c1)|p(f(A),A).
% 1.55/1.75  
% 1.55/1.75  ======= end of input processing =======
% 1.55/1.75  
% 1.55/1.75  =========== start of search ===========
% 1.55/1.75  
% 1.55/1.75  -------- PROOF -------- 
% 1.55/1.75  
% 1.55/1.75  -----> EMPTY CLAUSE at   0.00 sec ----> 7 [hyper,6,3,5] $F.
% 1.55/1.75  
% 1.55/1.75  Length of proof is 2.  Level of proof is 2.
% 1.55/1.75  
% 1.55/1.75  ---------------- PROOF ----------------
% 1.55/1.75  % SZS status Theorem
% 1.55/1.75  % SZS output start Refutation
% See solution above
% 1.55/1.75  ------------ end of proof -------------
% 1.55/1.75  
% 1.55/1.75  
% 1.55/1.75  Search stopped by max_proofs option.
% 1.55/1.75  
% 1.55/1.75  
% 1.55/1.75  Search stopped by max_proofs option.
% 1.55/1.75  
% 1.55/1.75  ============ end of search ============
% 1.55/1.75  
% 1.55/1.75  -------------- statistics -------------
% 1.55/1.75  clauses given                  3
% 1.55/1.75  clauses generated              3
% 1.55/1.75  clauses kept                   6
% 1.55/1.75  clauses forward subsumed       0
% 1.55/1.75  clauses back subsumed          1
% 1.55/1.75  Kbytes malloced              976
% 1.55/1.75  
% 1.55/1.75  ----------- times (seconds) -----------
% 1.55/1.75  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.55/1.75  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.55/1.75  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.55/1.75  
% 1.55/1.75  That finishes the proof of the theorem.
% 1.55/1.75  
% 1.55/1.75  Process 3597 finished Wed Jul 27 10:23:34 2022
% 1.55/1.75  Otter interrupted
% 1.55/1.75  PROOF FOUND
%------------------------------------------------------------------------------