TSTP Solution File: SYN979+1 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SYN979+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n011.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:13:31 EDT 2023
% Result : Theorem 3.51s 3.68s
% Output : Proof 3.51s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13 % Problem : SYN979+1 : TPTP v8.1.2. Released v3.1.0.
% 0.13/0.14 % Command : duper %s
% 0.15/0.36 % Computer : n011.cluster.edu
% 0.15/0.36 % Model : x86_64 x86_64
% 0.15/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36 % Memory : 8042.1875MB
% 0.15/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36 % CPULimit : 300
% 0.15/0.36 % WCLimit : 300
% 0.15/0.36 % DateTime : Sat Aug 26 20:09:54 EDT 2023
% 0.15/0.36 % CPUTime :
% 3.51/3.68 SZS status Theorem for theBenchmark.p
% 3.51/3.68 SZS output start Proof for theBenchmark.p
% 3.51/3.68 Clause #0 (by assumption #[]): Eq
% 3.51/3.68 (Not
% 3.51/3.68 (∀ (A B : Iota),
% 3.51/3.68 Exists fun X =>
% 3.51/3.68 Exists fun Y =>
% 3.51/3.68 And (And (And (And (And (And (And (q X → p X A) (q A)) (q B)) (r Y → p B Y)) (r A)) (r B)) (s A → p X Y))
% 3.51/3.68 (s A) →
% 3.51/3.68 p A B))
% 3.51/3.68 True
% 3.51/3.68 Clause #1 (by clausification #[0]): Eq
% 3.51/3.68 (∀ (A B : Iota),
% 3.51/3.68 Exists fun X =>
% 3.51/3.68 Exists fun Y =>
% 3.51/3.68 And (And (And (And (And (And (And (q X → p X A) (q A)) (q B)) (r Y → p B Y)) (r A)) (r B)) (s A → p X Y))
% 3.51/3.68 (s A) →
% 3.51/3.68 p A B)
% 3.51/3.68 False
% 3.51/3.68 Clause #2 (by clausification #[1]): ∀ (a : Iota),
% 3.51/3.68 Eq
% 3.51/3.68 (Not
% 3.51/3.68 (∀ (B : Iota),
% 3.51/3.68 Exists fun X =>
% 3.51/3.68 Exists fun Y =>
% 3.51/3.68 And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And (And (And (And (q X → p X (skS.0 0 a)) (q (skS.0 0 a))) (q B)) (r Y → p B Y)) (r (skS.0 0 a)))
% 3.51/3.68 (r B))
% 3.51/3.68 (s (skS.0 0 a) → p X Y))
% 3.51/3.68 (s (skS.0 0 a)) →
% 3.51/3.68 p (skS.0 0 a) B))
% 3.51/3.68 True
% 3.51/3.68 Clause #3 (by clausification #[2]): ∀ (a : Iota),
% 3.51/3.68 Eq
% 3.51/3.68 (∀ (B : Iota),
% 3.51/3.68 Exists fun X =>
% 3.51/3.68 Exists fun Y =>
% 3.51/3.68 And
% 3.51/3.68 (And
% 3.51/3.68 (And (And (And (And (And (q X → p X (skS.0 0 a)) (q (skS.0 0 a))) (q B)) (r Y → p B Y)) (r (skS.0 0 a)))
% 3.51/3.68 (r B))
% 3.51/3.68 (s (skS.0 0 a) → p X Y))
% 3.51/3.68 (s (skS.0 0 a)) →
% 3.51/3.68 p (skS.0 0 a) B)
% 3.51/3.68 False
% 3.51/3.68 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota),
% 3.51/3.68 Eq
% 3.51/3.68 (Not
% 3.51/3.68 (Exists fun X =>
% 3.51/3.68 Exists fun Y =>
% 3.51/3.68 And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And (And (And (q X → p X (skS.0 0 a)) (q (skS.0 0 a))) (q (skS.0 1 a a_1)))
% 3.51/3.68 (r Y → p (skS.0 1 a a_1) Y))
% 3.51/3.68 (r (skS.0 0 a)))
% 3.51/3.68 (r (skS.0 1 a a_1)))
% 3.51/3.68 (s (skS.0 0 a) → p X Y))
% 3.51/3.68 (s (skS.0 0 a)) →
% 3.51/3.68 p (skS.0 0 a) (skS.0 1 a a_1)))
% 3.51/3.68 True
% 3.51/3.68 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota),
% 3.51/3.68 Eq
% 3.51/3.68 (Exists fun X =>
% 3.51/3.68 Exists fun Y =>
% 3.51/3.68 And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And (And (And (q X → p X (skS.0 0 a)) (q (skS.0 0 a))) (q (skS.0 1 a a_1)))
% 3.51/3.68 (r Y → p (skS.0 1 a a_1) Y))
% 3.51/3.68 (r (skS.0 0 a)))
% 3.51/3.68 (r (skS.0 1 a a_1)))
% 3.51/3.68 (s (skS.0 0 a) → p X Y))
% 3.51/3.68 (s (skS.0 0 a)) →
% 3.51/3.68 p (skS.0 0 a) (skS.0 1 a a_1))
% 3.51/3.68 False
% 3.51/3.68 Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 : Iota),
% 3.51/3.68 Eq
% 3.51/3.68 (Exists fun Y =>
% 3.51/3.68 And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And (And (And (q a → p a (skS.0 0 a_1)) (q (skS.0 0 a_1))) (q (skS.0 1 a_1 a_2)))
% 3.51/3.68 (r Y → p (skS.0 1 a_1 a_2) Y))
% 3.51/3.68 (r (skS.0 0 a_1)))
% 3.51/3.68 (r (skS.0 1 a_1 a_2)))
% 3.51/3.68 (s (skS.0 0 a_1) → p a Y))
% 3.51/3.68 (s (skS.0 0 a_1)) →
% 3.51/3.68 p (skS.0 0 a_1) (skS.0 1 a_1 a_2))
% 3.51/3.68 False
% 3.51/3.68 Clause #7 (by clausification #[6]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.51/3.68 Eq
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And (And (And (q a → p a (skS.0 0 a_1)) (q (skS.0 0 a_1))) (q (skS.0 1 a_1 a_2)))
% 3.51/3.68 (r a_3 → p (skS.0 1 a_1 a_2) a_3))
% 3.51/3.68 (r (skS.0 0 a_1)))
% 3.51/3.68 (r (skS.0 1 a_1 a_2)))
% 3.51/3.68 (s (skS.0 0 a_1) → p a a_3))
% 3.51/3.68 (s (skS.0 0 a_1)) →
% 3.51/3.68 p (skS.0 0 a_1) (skS.0 1 a_1 a_2))
% 3.51/3.68 False
% 3.51/3.68 Clause #8 (by clausification #[7]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.51/3.68 Eq
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And (And (And (q a → p a (skS.0 0 a_1)) (q (skS.0 0 a_1))) (q (skS.0 1 a_1 a_2)))
% 3.51/3.68 (r a_3 → p (skS.0 1 a_1 a_2) a_3))
% 3.51/3.68 (r (skS.0 0 a_1)))
% 3.51/3.68 (r (skS.0 1 a_1 a_2)))
% 3.51/3.68 (s (skS.0 0 a_1) → p a a_3))
% 3.51/3.68 (s (skS.0 0 a_1)))
% 3.51/3.68 True
% 3.51/3.68 Clause #9 (by clausification #[7]): ∀ (a a_1 : Iota), Eq (p (skS.0 0 a) (skS.0 1 a a_1)) False
% 3.51/3.68 Clause #10 (by clausification #[8]): ∀ (a : Iota), Eq (s (skS.0 0 a)) True
% 3.51/3.68 Clause #11 (by clausification #[8]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.51/3.68 Eq
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And
% 3.51/3.68 (And (And (And (q a → p a (skS.0 0 a_1)) (q (skS.0 0 a_1))) (q (skS.0 1 a_1 a_2)))
% 3.51/3.68 (r a_3 → p (skS.0 1 a_1 a_2) a_3))
% 3.51/3.68 (r (skS.0 0 a_1)))
% 3.51/3.68 (r (skS.0 1 a_1 a_2)))
% 3.51/3.68 (s (skS.0 0 a_1) → p a a_3))
% 3.51/3.68 True
% 3.51/3.68 Clause #12 (by clausification #[11]): ∀ (a a_1 a_2 : Iota), Eq (s (skS.0 0 a) → p a_1 a_2) True
% 3.51/3.68 Clause #14 (by clausification #[12]): ∀ (a a_1 a_2 : Iota), Or (Eq (s (skS.0 0 a)) False) (Eq (p a_1 a_2) True)
% 3.51/3.68 Clause #15 (by superposition #[14, 10]): ∀ (a a_1 : Iota), Or (Eq (p a a_1) True) (Eq False True)
% 3.51/3.68 Clause #16 (by clausification #[15]): ∀ (a a_1 : Iota), Eq (p a a_1) True
% 3.51/3.68 Clause #17 (by superposition #[16, 9]): Eq True False
% 3.51/3.68 Clause #18 (by clausification #[17]): False
% 3.51/3.68 SZS output end Proof for theBenchmark.p
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