TSTP Solution File: SYN978+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN978+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:13:31 EDT 2023

% Result   : Theorem 3.26s 3.56s
% Output   : Proof 3.26s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : SYN978+1 : TPTP v8.1.2. Released v3.1.0.
% 0.00/0.14  % Command    : duper %s
% 0.14/0.36  % Computer : n029.cluster.edu
% 0.14/0.36  % Model    : x86_64 x86_64
% 0.14/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36  % Memory   : 8042.1875MB
% 0.14/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36  % CPULimit   : 300
% 0.14/0.36  % WCLimit    : 300
% 0.14/0.36  % DateTime   : Sat Aug 26 19:58:10 EDT 2023
% 0.14/0.36  % CPUTime    : 
% 3.26/3.56  SZS status Theorem for theBenchmark.p
% 3.26/3.56  SZS output start Proof for theBenchmark.p
% 3.26/3.56  Clause #0 (by assumption #[]): Eq (Not (And a b → Iff a b)) True
% 3.26/3.56  Clause #1 (by clausification #[0]): Eq (And a b → Iff a b) False
% 3.26/3.56  Clause #2 (by clausification #[1]): Eq (And a b) True
% 3.26/3.56  Clause #3 (by clausification #[1]): Eq (Iff a b) False
% 3.26/3.56  Clause #4 (by clausification #[2]): Eq b True
% 3.26/3.56  Clause #5 (by clausification #[2]): Eq a True
% 3.26/3.56  Clause #6 (by clausification #[3]): Or (Eq a False) (Eq b False)
% 3.26/3.56  Clause #8 (by forward demodulation #[6, 4]): Or (Eq a False) (Eq True False)
% 3.26/3.56  Clause #9 (by clausification #[8]): Eq a False
% 3.26/3.56  Clause #10 (by superposition #[9, 5]): Eq False True
% 3.26/3.56  Clause #11 (by clausification #[10]): False
% 3.26/3.56  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------