TSTP Solution File: SYN976+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN976+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n032.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:13:30 EDT 2023
% Result : Theorem 3.41s 3.58s
% Output : Proof 3.41s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.09 % Problem : SYN976+1 : TPTP v8.1.2. Released v3.1.0.
% 0.00/0.10 % Command : duper %s
% 0.10/0.29 % Computer : n032.cluster.edu
% 0.10/0.29 % Model : x86_64 x86_64
% 0.10/0.29 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.29 % Memory : 8042.1875MB
% 0.10/0.29 % OS : Linux 3.10.0-693.el7.x86_64
% 0.10/0.29 % CPULimit : 300
% 0.10/0.29 % WCLimit : 300
% 0.10/0.29 % DateTime : Sat Aug 26 19:02:59 EDT 2023
% 0.10/0.29 % CPUTime :
% 3.41/3.58 SZS status Theorem for theBenchmark.p
% 3.41/3.58 SZS output start Proof for theBenchmark.p
% 3.41/3.58 Clause #0 (by assumption #[]): Eq (Not (∀ (A : Iota), And (Or f g) (∀ (X : Iota), And (p X) (q X)) → q A)) True
% 3.41/3.58 Clause #1 (by clausification #[0]): Eq (∀ (A : Iota), And (Or f g) (∀ (X : Iota), And (p X) (q X)) → q A) False
% 3.41/3.58 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (Not (And (Or f g) (∀ (X : Iota), And (p X) (q X)) → q (skS.0 0 a))) True
% 3.41/3.58 Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (And (Or f g) (∀ (X : Iota), And (p X) (q X)) → q (skS.0 0 a)) False
% 3.41/3.58 Clause #4 (by clausification #[3]): Eq (And (Or f g) (∀ (X : Iota), And (p X) (q X))) True
% 3.41/3.58 Clause #5 (by clausification #[3]): ∀ (a : Iota), Eq (q (skS.0 0 a)) False
% 3.41/3.58 Clause #6 (by clausification #[4]): Eq (∀ (X : Iota), And (p X) (q X)) True
% 3.41/3.58 Clause #8 (by clausification #[6]): ∀ (a : Iota), Eq (And (p a) (q a)) True
% 3.41/3.58 Clause #9 (by clausification #[8]): ∀ (a : Iota), Eq (q a) True
% 3.41/3.58 Clause #12 (by superposition #[5, 9]): Eq True False
% 3.41/3.58 Clause #13 (by clausification #[12]): False
% 3.41/3.58 SZS output end Proof for theBenchmark.p
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