TSTP Solution File: SYN974+1 by Otter---3.3
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%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : SYN974+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n027.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:25:36 EDT 2022
% Result : Theorem 1.63s 1.85s
% Output : Refutation 1.63s
% Verified :
% SZS Type : Refutation
% Derivation depth : 1
% Number of leaves : 2
% Syntax : Number of clauses : 3 ( 3 unt; 0 nHn; 3 RR)
% Number of literals : 3 ( 0 equ; 1 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-1 aty)
% Number of functors : 1 ( 1 usr; 1 con; 0-0 aty)
% Number of variables : 1 ( 1 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
~ p(A),
file('SYN974+1.p',unknown),
[] ).
cnf(2,axiom,
p(dollar_c1),
file('SYN974+1.p',unknown),
[] ).
cnf(3,plain,
$false,
inference(binary,[status(thm)],[2,1]),
[iquote('binary,2.1,1.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : SYN974+1 : TPTP v8.1.0. Released v3.1.0.
% 0.03/0.12 % Command : otter-tptp-script %s
% 0.12/0.33 % Computer : n027.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Wed Jul 27 11:38:21 EDT 2022
% 0.12/0.33 % CPUTime :
% 1.63/1.85
% 1.63/1.85 -------- PROOF --------
% 1.63/1.85 ----- Otter 3.3f, August 2004 -----
% 1.63/1.85 The process was started by sandbox on n027.cluster.edu,
% 1.63/1.85 Wed Jul 27 11:38:22 2022
% 1.63/1.85 The command was "./otter". The process ID is 14094.
% 1.63/1.85
% 1.63/1.85 set(prolog_style_variables).
% 1.63/1.85 set(auto).
% 1.63/1.85 dependent: set(auto1).
% 1.63/1.85 dependent: set(process_input).
% 1.63/1.85 dependent: clear(print_kept).
% 1.63/1.85 dependent: clear(print_new_demod).
% 1.63/1.85 dependent: clear(print_back_demod).
% 1.63/1.85 dependent: clear(print_back_sub).
% 1.63/1.85 dependent: set(control_memory).
% 1.63/1.85 dependent: assign(max_mem, 12000).
% 1.63/1.85 dependent: assign(pick_given_ratio, 4).
% 1.63/1.85 dependent: assign(stats_level, 1).
% 1.63/1.85 dependent: assign(max_seconds, 10800).
% 1.63/1.85 clear(print_given).
% 1.63/1.85
% 1.63/1.85 formula_list(usable).
% 1.63/1.85 -((exists X p(X))-> (exists Y p(Y))).
% 1.63/1.85 end_of_list.
% 1.63/1.85
% 1.63/1.85 -------> usable clausifies to:
% 1.63/1.85
% 1.63/1.85 list(usable).
% 1.63/1.85 0 [] p($c1).
% 1.63/1.85 0 [] -p(Y).
% 1.63/1.85 end_of_list.
% 1.63/1.85
% 1.63/1.85 SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=1.
% 1.63/1.85
% 1.63/1.85 This is a Horn set without equality. The strategy will
% 1.63/1.85 be hyperresolution, with satellites in sos and nuclei
% 1.63/1.85 in usable.
% 1.63/1.85
% 1.63/1.85 dependent: set(hyper_res).
% 1.63/1.85 dependent: clear(order_hyper).
% 1.63/1.85
% 1.63/1.85 ------------> process usable:
% 1.63/1.85 ** KEPT (pick-wt=2): 1 [] -p(A).
% 1.63/1.85
% 1.63/1.85 ------------> process sos:
% 1.63/1.85 ** KEPT (pick-wt=2): 2 [] p($c1).
% 1.63/1.85
% 1.63/1.85 ----> UNIT CONFLICT at 0.00 sec ----> 3 [binary,2.1,1.1] $F.
% 1.63/1.85
% 1.63/1.85 Length of proof is 0. Level of proof is 0.
% 1.63/1.85
% 1.63/1.85 ---------------- PROOF ----------------
% 1.63/1.85 % SZS status Theorem
% 1.63/1.85 % SZS output start Refutation
% See solution above
% 1.63/1.85 ------------ end of proof -------------
% 1.63/1.85
% 1.63/1.85
% 1.63/1.85 Search stopped by max_proofs option.
% 1.63/1.85
% 1.63/1.85
% 1.63/1.85 Search stopped by max_proofs option.
% 1.63/1.85
% 1.63/1.85 ============ end of search ============
% 1.63/1.85
% 1.63/1.85 -------------- statistics -------------
% 1.63/1.85 clauses given 0
% 1.63/1.85 clauses generated 0
% 1.63/1.85 clauses kept 2
% 1.63/1.85 clauses forward subsumed 0
% 1.63/1.85 clauses back subsumed 0
% 1.63/1.85 Kbytes malloced 976
% 1.63/1.85
% 1.63/1.85 ----------- times (seconds) -----------
% 1.63/1.85 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.63/1.85 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.63/1.85 wall-clock time 1 (0 hr, 0 min, 1 sec)
% 1.63/1.85
% 1.63/1.85 That finishes the proof of the theorem.
% 1.63/1.85
% 1.63/1.85 Process 14094 finished Wed Jul 27 11:38:23 2022
% 1.63/1.85 Otter interrupted
% 1.63/1.85 PROOF FOUND
%------------------------------------------------------------------------------