%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN969+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n031.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:13:28 EDT 2023

% Result   : Theorem 3.42s 3.60s
% Output   : Proof 3.42s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.13  % Problem    : SYN969+1 : TPTP v8.1.2. Released v3.1.0.
% 0.12/0.15  % Command    : duper %s
% 0.14/0.36  % Computer : n031.cluster.edu
% 0.14/0.36  % Model    : x86_64 x86_64
% 0.14/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36  % Memory   : 8042.1875MB
% 0.14/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36  % CPULimit   : 300
% 0.14/0.36  % WCLimit    : 300
% 0.14/0.36  % DateTime   : Sat Aug 26 17:31:53 EDT 2023
% 0.14/0.36  % CPUTime    : 
% 3.42/3.60  SZS status Theorem for theBenchmark.p
% 3.42/3.60  SZS output start Proof for theBenchmark.p
% 3.42/3.60  Clause #0 (by assumption #[]): Eq (Not (∀ (B : Iota), And (∀ (X : Iota), p X → q X) (r B) → (∀ (Y : Iota), r Y → p Y) → q B)) True
% 3.42/3.60  Clause #1 (by clausification #[0]): Eq (∀ (B : Iota), And (∀ (X : Iota), p X → q X) (r B) → (∀ (Y : Iota), r Y → p Y) → q B) False
% 3.42/3.60  Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (Not (And (∀ (X : Iota), p X → q X) (r (skS.0 0 a)) → (∀ (Y : Iota), r Y → p Y) → q (skS.0 0 a))) True
% 3.42/3.60  Clause #3 (by clausification #[2]): ∀ (a : Iota), Eq (And (∀ (X : Iota), p X → q X) (r (skS.0 0 a)) → (∀ (Y : Iota), r Y → p Y) → q (skS.0 0 a)) False
% 3.42/3.60  Clause #4 (by clausification #[3]): ∀ (a : Iota), Eq (And (∀ (X : Iota), p X → q X) (r (skS.0 0 a))) True
% 3.42/3.60  Clause #5 (by clausification #[3]): ∀ (a : Iota), Eq ((∀ (Y : Iota), r Y → p Y) → q (skS.0 0 a)) False
% 3.42/3.60  Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (r (skS.0 0 a)) True
% 3.42/3.60  Clause #7 (by clausification #[4]): Eq (∀ (X : Iota), p X → q X) True
% 3.42/3.60  Clause #8 (by clausification #[7]): ∀ (a : Iota), Eq (p a → q a) True
% 3.42/3.60  Clause #9 (by clausification #[8]): ∀ (a : Iota), Or (Eq (p a) False) (Eq (q a) True)
% 3.42/3.60  Clause #10 (by clausification #[5]): Eq (∀ (Y : Iota), r Y → p Y) True
% 3.42/3.60  Clause #11 (by clausification #[5]): ∀ (a : Iota), Eq (q (skS.0 0 a)) False
% 3.42/3.60  Clause #12 (by clausification #[10]): ∀ (a : Iota), Eq (r a → p a) True
% 3.42/3.60  Clause #13 (by clausification #[12]): ∀ (a : Iota), Or (Eq (r a) False) (Eq (p a) True)
% 3.42/3.60  Clause #14 (by superposition #[13, 6]): ∀ (a : Iota), Or (Eq (p (skS.0 0 a)) True) (Eq False True)
% 3.42/3.60  Clause #15 (by clausification #[14]): ∀ (a : Iota), Eq (p (skS.0 0 a)) True
% 3.42/3.60  Clause #16 (by superposition #[15, 9]): ∀ (a : Iota), Or (Eq True False) (Eq (q (skS.0 0 a)) True)
% 3.42/3.60  Clause #17 (by clausification #[16]): ∀ (a : Iota), Eq (q (skS.0 0 a)) True
% 3.42/3.60  Clause #18 (by superposition #[17, 11]): Eq True False
% 3.42/3.60  Clause #19 (by clausification #[18]): False
% 3.42/3.60  SZS output end Proof for theBenchmark.p
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