TSTP Solution File: SYN966+1 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYN966+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n007.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:32:22 EDT 2022
% Result : Theorem 0.19s 0.43s
% Output : Refutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 6
% Syntax : Number of clauses : 14 ( 4 unt; 3 nHn; 14 RR)
% Number of literals : 30 ( 0 equ; 12 neg)
% Maximal clause size : 3 ( 2 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 6 ( 6 usr; 5 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
eq(skc6,skc7),
file('SYN966+1.p',unknown),
[] ).
cnf(2,axiom,
~ eq(skc7,skc6),
file('SYN966+1.p',unknown),
[] ).
cnf(3,axiom,
( ~ eq(u,v)
| ~ a_member_of(w,u)
| a_member_of(w,v) ),
file('SYN966+1.p',unknown),
[] ).
cnf(4,axiom,
( ~ eq(u,v)
| ~ a_member_of(w,v)
| a_member_of(w,u) ),
file('SYN966+1.p',unknown),
[] ).
cnf(5,axiom,
( eq(u,v)
| a_member_of(skf1(v,u),v)
| a_member_of(skf1(v,u),u) ),
file('SYN966+1.p',unknown),
[] ).
cnf(6,axiom,
( ~ a_member_of(skf1(u,v),u)
| ~ a_member_of(skf1(u,v),v)
| eq(v,u) ),
file('SYN966+1.p',unknown),
[] ).
cnf(7,plain,
( ~ a_member_of(u,skc7)
| a_member_of(u,skc6) ),
inference(res,[status(thm),theory(equality)],[1,4]),
[iquote('0:Res:1.0,4.0')] ).
cnf(8,plain,
( ~ a_member_of(u,skc6)
| a_member_of(u,skc7) ),
inference(res,[status(thm),theory(equality)],[1,3]),
[iquote('0:Res:1.0,3.0')] ).
cnf(11,plain,
( eq(u,skc6)
| a_member_of(skf1(skc6,u),u)
| a_member_of(skf1(skc6,u),skc7) ),
inference(res,[status(thm),theory(equality)],[5,8]),
[iquote('0:Res:5.1,8.0')] ).
cnf(14,plain,
( ~ a_member_of(skf1(skc6,u),skc7)
| ~ a_member_of(skf1(skc6,u),u)
| eq(u,skc6) ),
inference(res,[status(thm),theory(equality)],[7,6]),
[iquote('0:Res:7.1,6.0')] ).
cnf(21,plain,
( eq(skc7,skc6)
| a_member_of(skf1(skc6,skc7),skc7) ),
inference(fac,[status(thm)],[11]),
[iquote('0:Fac:11.1,11.2')] ).
cnf(24,plain,
a_member_of(skf1(skc6,skc7),skc7),
inference(mrr,[status(thm)],[21,2]),
[iquote('0:MRR:21.0,2.0')] ).
cnf(33,plain,
( ~ a_member_of(skf1(skc6,skc7),skc7)
| eq(skc7,skc6) ),
inference(res,[status(thm),theory(equality)],[24,14]),
[iquote('0:Res:24.0,14.0')] ).
cnf(34,plain,
$false,
inference(mrr,[status(thm)],[33,24,2]),
[iquote('0:MRR:33.0,33.1,24.0,2.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SYN966+1 : TPTP v8.1.0. Released v3.1.0.
% 0.07/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n007.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Mon Jul 11 19:28:03 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.19/0.43
% 0.19/0.43 SPASS V 3.9
% 0.19/0.43 SPASS beiseite: Proof found.
% 0.19/0.43 % SZS status Theorem
% 0.19/0.43 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.19/0.43 SPASS derived 20 clauses, backtracked 0 clauses, performed 0 splits and kept 16 clauses.
% 0.19/0.43 SPASS allocated 85165 KBytes.
% 0.19/0.43 SPASS spent 0:00:00.08 on the problem.
% 0.19/0.43 0:00:00.03 for the input.
% 0.19/0.43 0:00:00.03 for the FLOTTER CNF translation.
% 0.19/0.43 0:00:00.00 for inferences.
% 0.19/0.43 0:00:00.00 for the backtracking.
% 0.19/0.43 0:00:00.00 for the reduction.
% 0.19/0.43
% 0.19/0.43
% 0.19/0.43 Here is a proof with depth 4, length 14 :
% 0.19/0.43 % SZS output start Refutation
% See solution above
% 0.19/0.43 Formulae used in the proof : prove_this
% 0.19/0.43
%------------------------------------------------------------------------------