TSTP Solution File: SYN965+1 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYN965+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n023.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:32:21 EDT 2022
% Result : Theorem 0.18s 0.42s
% Output : Refutation 0.18s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 4
% Syntax : Number of clauses : 12 ( 4 unt; 4 nHn; 12 RR)
% Number of literals : 20 ( 0 equ; 6 neg)
% Maximal clause size : 2 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-2 aty)
% Number of functors : 4 ( 4 usr; 3 con; 0-1 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
( skP0(u,v)
| p(v,u) ),
file('SYN965+1.p',unknown),
[] ).
cnf(2,axiom,
( ~ p(u,v)
| skP0(w,v) ),
file('SYN965+1.p',unknown),
[] ).
cnf(4,axiom,
( ~ skP0(skf1(u),v)
| p(v,u) ),
file('SYN965+1.p',unknown),
[] ).
cnf(5,axiom,
( ~ p(u,skf1(v))
| ~ skP0(skf1(v),u) ),
file('SYN965+1.p',unknown),
[] ).
cnf(6,plain,
( p(u,skf1(v))
| p(u,v) ),
inference(res,[status(thm),theory(equality)],[1,4]),
[iquote('0:Res:1.0,4.0')] ).
cnf(7,plain,
( p(u,v)
| skP0(w,skf1(v)) ),
inference(res,[status(thm),theory(equality)],[6,2]),
[iquote('0:Res:6.0,2.0')] ).
cnf(11,plain,
( p(u,v)
| p(skf1(v),w) ),
inference(res,[status(thm),theory(equality)],[7,4]),
[iquote('0:Res:7.1,4.0')] ).
cnf(21,plain,
( ~ p(skf1(u),skf1(v))
| p(w,u) ),
inference(res,[status(thm),theory(equality)],[7,5]),
[iquote('0:Res:7.1,5.1')] ).
cnf(24,plain,
p(u,v),
inference(mrr,[status(thm)],[21,11]),
[iquote('0:MRR:21.0,11.1')] ).
cnf(25,plain,
skP0(u,v),
inference(mrr,[status(thm)],[2,24]),
[iquote('0:MRR:2.0,24.0')] ).
cnf(26,plain,
~ skP0(skf1(u),v),
inference(mrr,[status(thm)],[5,24]),
[iquote('0:MRR:5.0,24.0')] ).
cnf(27,plain,
$false,
inference(mrr,[status(thm)],[26,25]),
[iquote('0:MRR:26.0,25.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : SYN965+1 : TPTP v8.1.0. Released v3.1.0.
% 0.03/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n023.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Mon Jul 11 18:44:24 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.42
% 0.18/0.42 SPASS V 3.9
% 0.18/0.42 SPASS beiseite: Proof found.
% 0.18/0.42 % SZS status Theorem
% 0.18/0.42 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.18/0.42 SPASS derived 19 clauses, backtracked 0 clauses, performed 0 splits and kept 18 clauses.
% 0.18/0.42 SPASS allocated 85062 KBytes.
% 0.18/0.42 SPASS spent 0:00:00.08 on the problem.
% 0.18/0.42 0:00:00.03 for the input.
% 0.18/0.42 0:00:00.02 for the FLOTTER CNF translation.
% 0.18/0.42 0:00:00.00 for inferences.
% 0.18/0.42 0:00:00.00 for the backtracking.
% 0.18/0.42 0:00:00.00 for the reduction.
% 0.18/0.42
% 0.18/0.42
% 0.18/0.42 Here is a proof with depth 3, length 12 :
% 0.18/0.42 % SZS output start Refutation
% See solution above
% 0.18/0.42 Formulae used in the proof : prove_this
% 0.18/0.42
%------------------------------------------------------------------------------