TSTP Solution File: SYN964+1 by SnakeForV---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SnakeForV---1.0
% Problem  : SYN964+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Aug 31 19:36:12 EDT 2022

% Result   : Theorem 0.19s 0.49s
% Output   : Refutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    2
% Syntax   : Number of formulae    :    9 (   3 unt;   0 def)
%            Number of atoms       :   15 (   0 equ)
%            Maximal formula atoms :    2 (   1 avg)
%            Number of connectives :   11 (   5   ~;   0   |;   3   &)
%                                         (   0 <=>;   3  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    4 (   3 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-1 aty)
%            Number of functors    :    1 (   1 usr;   1 con; 0-0 aty)
%            Number of variables   :   11 (   4   !;   7   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f9,plain,
    $false,
    inference(resolution,[],[f8,f7]) ).

fof(f7,plain,
    p(sK0),
    inference(cnf_transformation,[],[f6]) ).

fof(f6,plain,
    ( ! [X0] : ~ p(X0)
    & p(sK0) ),
    inference(skolemisation,[status(esa),new_symbols(skolem,[sK0])],[f4,f5]) ).

fof(f5,plain,
    ( ? [X1] : p(X1)
   => p(sK0) ),
    introduced(choice_axiom,[]) ).

fof(f4,plain,
    ( ! [X0] : ~ p(X0)
    & ? [X1] : p(X1) ),
    inference(rectify,[],[f3]) ).

fof(f3,plain,
    ( ! [X1] : ~ p(X1)
    & ? [X0] : p(X0) ),
    inference(ennf_transformation,[],[f2]) ).

fof(f2,negated_conjecture,
    ~ ( ? [X0] : p(X0)
     => ? [X1] : p(X1) ),
    inference(negated_conjecture,[],[f1]) ).

fof(f1,conjecture,
    ( ? [X0] : p(X0)
   => ? [X1] : p(X1) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',prove_this) ).

fof(f8,plain,
    ! [X0] : ~ p(X0),
    inference(cnf_transformation,[],[f6]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYN964+1 : TPTP v8.1.0. Released v3.1.0.
% 0.12/0.13  % Command    : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_uns --cores 0 -t %d %s
% 0.13/0.34  % Computer : n024.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Tue Aug 30 22:35:19 EDT 2022
% 0.13/0.34  % CPUTime    : 
% 0.19/0.48  % (861)lrs+1011_1:1_fd=preordered:fsd=on:sos=on:thsq=on:thsqc=64:thsqd=32:uwa=ground:i=50:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/50Mi)
% 0.19/0.48  % (846)dis+1002_1:1_aac=none:bd=off:sac=on:sos=on:spb=units:i=3:si=on:rawr=on:rtra=on_0 on theBenchmark for (2999ds/3Mi)
% 0.19/0.48  % (846)First to succeed.
% 0.19/0.49  % (846)Refutation found. Thanks to Tanya!
% 0.19/0.49  % SZS status Theorem for theBenchmark
% 0.19/0.49  % SZS output start Proof for theBenchmark
% See solution above
% 0.19/0.49  % (846)------------------------------
% 0.19/0.49  % (846)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 0.19/0.49  % (846)Linked with Z3 4.8.13.0 f03d756e086f81f2596157241e0decfb1c982299 z3-4.8.4-5390-gf03d756e0
% 0.19/0.49  % (846)Termination reason: Refutation
% 0.19/0.49  
% 0.19/0.49  % (846)Memory used [KB]: 5884
% 0.19/0.49  % (846)Time elapsed: 0.073 s
% 0.19/0.49  % (846)Instructions burned: 1 (million)
% 0.19/0.49  % (846)------------------------------
% 0.19/0.49  % (846)------------------------------
% 0.19/0.49  % (843)Success in time 0.139 s
%------------------------------------------------------------------------------