TSTP Solution File: SYN962+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN962+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:13:27 EDT 2023
% Result : Theorem 3.78s 3.93s
% Output : Proof 3.78s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : SYN962+1 : TPTP v8.1.2. Released v3.1.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.35 % Computer : n021.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Sat Aug 26 18:40:27 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.78/3.93 SZS status Theorem for theBenchmark.p
% 3.78/3.93 SZS output start Proof for theBenchmark.p
% 3.78/3.93 Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), p X) → And (∀ (X : Iota), p X) (∀ (Y : Iota), p Y))) True
% 3.78/3.93 Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), p X) → And (∀ (X : Iota), p X) (∀ (Y : Iota), p Y)) False
% 3.78/3.93 Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), p X) True
% 3.78/3.93 Clause #3 (by clausification #[1]): Eq (And (∀ (X : Iota), p X) (∀ (Y : Iota), p Y)) False
% 3.78/3.93 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (p a) True
% 3.78/3.93 Clause #5 (by clausification #[3]): Or (Eq (∀ (X : Iota), p X) False) (Eq (∀ (Y : Iota), p Y) False)
% 3.78/3.93 Clause #6 (by clausification #[5]): ∀ (a : Iota), Or (Eq (∀ (Y : Iota), p Y) False) (Eq (Not (p (skS.0 0 a))) True)
% 3.78/3.93 Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Or (Eq (Not (p (skS.0 0 a))) True) (Eq (Not (p (skS.0 1 a_1))) True)
% 3.78/3.93 Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq (Not (p (skS.0 1 a))) True) (Eq (p (skS.0 0 a_1)) False)
% 3.78/3.93 Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a_1)) False)
% 3.78/3.93 Clause #10 (by superposition #[9, 4]): ∀ (a : Iota), Or (Eq (p (skS.0 1 a)) False) (Eq False True)
% 3.78/3.93 Clause #11 (by clausification #[10]): ∀ (a : Iota), Eq (p (skS.0 1 a)) False
% 3.78/3.93 Clause #12 (by superposition #[11, 4]): Eq False True
% 3.78/3.93 Clause #13 (by clausification #[12]): False
% 3.78/3.93 SZS output end Proof for theBenchmark.p
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