TSTP Solution File: SYN953+1 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : SYN953+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n025.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 06:15:03 EDT 2022
% Result : Theorem 0.12s 0.35s
% Output : CNFRefutation 0.12s
% Verified :
% SZS Type : Refutation
% Derivation depth : 5
% Number of leaves : 1
% Syntax : Number of formulae : 8 ( 4 unt; 0 def)
% Number of atoms : 18 ( 0 equ)
% Maximal formula atoms : 4 ( 2 avg)
% Number of connectives : 15 ( 5 ~; 2 |; 2 &)
% ( 0 <=>; 6 =>; 0 <=; 0 <~>)
% Maximal formula depth : 6 ( 3 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 3 ( 2 usr; 1 prp; 0-1 aty)
% Number of functors : 1 ( 1 usr; 1 con; 0-0 aty)
% Number of variables : 11 ( 2 sgn 8 !; 0 ?)
% Comments :
%------------------------------------------------------------------------------
fof(prove_this,conjecture,
( ! [X1] :
( p(X1)
=> q(X1) )
=> ( ! [X1] : p(X1)
=> ! [X1] : q(X1) ) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',prove_this) ).
fof(c_0_1,negated_conjecture,
~ ( ! [X1] :
( p(X1)
=> q(X1) )
=> ( ! [X1] : p(X1)
=> ! [X1] : q(X1) ) ),
inference(assume_negation,[status(cth)],[prove_this]) ).
fof(c_0_2,negated_conjecture,
! [X2,X3] :
( ( ~ p(X2)
| q(X2) )
& p(X3)
& ~ q(esk1_0) ),
inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_1])])])]) ).
cnf(c_0_3,negated_conjecture,
( q(X1)
| ~ p(X1) ),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_4,negated_conjecture,
p(X1),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_5,negated_conjecture,
~ q(esk1_0),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_6,negated_conjecture,
q(X1),
inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_3,c_0_4])]) ).
cnf(c_0_7,negated_conjecture,
$false,
inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_5,c_0_6])]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11 % Problem : SYN953+1 : TPTP v8.1.0. Released v3.1.0.
% 0.06/0.12 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.12/0.32 % Computer : n025.cluster.edu
% 0.12/0.32 % Model : x86_64 x86_64
% 0.12/0.32 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32 % Memory : 8042.1875MB
% 0.12/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32 % CPULimit : 300
% 0.12/0.32 % WCLimit : 600
% 0.12/0.32 % DateTime : Tue Jul 12 06:47:03 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.12/0.35 # No SInE strategy applied
% 0.12/0.35 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.12/0.35 # and selection function SelectComplexExceptUniqMaxHorn.
% 0.12/0.35 #
% 0.12/0.35 # Presaturation interreduction done
% 0.12/0.35
% 0.12/0.35 # Proof found!
% 0.12/0.35 # SZS status Theorem
% 0.12/0.35 # SZS output start CNFRefutation
% See solution above
% 0.12/0.35 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------