TSTP Solution File: SYN953+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN953+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n022.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:13:24 EDT 2023
% Result : Theorem 3.32s 3.58s
% Output : Proof 3.32s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SYN953+1 : TPTP v8.1.2. Released v3.1.0.
% 0.07/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n022.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Sat Aug 26 21:21:10 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.32/3.58 SZS status Theorem for theBenchmark.p
% 3.32/3.58 SZS output start Proof for theBenchmark.p
% 3.32/3.58 Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), p X → q X) → (∀ (X : Iota), p X) → ∀ (X : Iota), q X)) True
% 3.32/3.58 Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), p X → q X) → (∀ (X : Iota), p X) → ∀ (X : Iota), q X) False
% 3.32/3.58 Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), p X → q X) True
% 3.32/3.58 Clause #3 (by clausification #[1]): Eq ((∀ (X : Iota), p X) → ∀ (X : Iota), q X) False
% 3.32/3.58 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (p a → q a) True
% 3.32/3.58 Clause #5 (by clausification #[4]): ∀ (a : Iota), Or (Eq (p a) False) (Eq (q a) True)
% 3.32/3.58 Clause #6 (by clausification #[3]): Eq (∀ (X : Iota), p X) True
% 3.32/3.58 Clause #7 (by clausification #[3]): Eq (∀ (X : Iota), q X) False
% 3.32/3.58 Clause #8 (by clausification #[6]): ∀ (a : Iota), Eq (p a) True
% 3.32/3.58 Clause #9 (by superposition #[8, 5]): ∀ (a : Iota), Or (Eq True False) (Eq (q a) True)
% 3.32/3.58 Clause #10 (by clausification #[7]): ∀ (a : Iota), Eq (Not (q (skS.0 0 a))) True
% 3.32/3.58 Clause #11 (by clausification #[10]): ∀ (a : Iota), Eq (q (skS.0 0 a)) False
% 3.32/3.58 Clause #12 (by clausification #[9]): ∀ (a : Iota), Eq (q a) True
% 3.32/3.58 Clause #14 (by superposition #[12, 11]): Eq True False
% 3.32/3.58 Clause #15 (by clausification #[14]): False
% 3.32/3.58 SZS output end Proof for theBenchmark.p
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