TSTP Solution File: SYN953+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SYN953+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Thu Jul 21 02:58:21 EDT 2022

% Result   : Theorem 0.43s 1.07s
% Output   : Refutation 0.43s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11  % Problem  : SYN953+1 : TPTP v8.1.0. Released v3.1.0.
% 0.07/0.12  % Command  : bliksem %s
% 0.12/0.33  % Computer : n026.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % DateTime : Tue Jul 12 06:52:27 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.43/1.07  *** allocated 10000 integers for termspace/termends
% 0.43/1.07  *** allocated 10000 integers for clauses
% 0.43/1.07  *** allocated 10000 integers for justifications
% 0.43/1.07  Bliksem 1.12
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  Automatic Strategy Selection
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  Clauses:
% 0.43/1.07  
% 0.43/1.07  { ! p( X ), q( X ) }.
% 0.43/1.07  { p( X ) }.
% 0.43/1.07  { ! q( skol1 ) }.
% 0.43/1.07  
% 0.43/1.07  percentage equality = 0.000000, percentage horn = 1.000000
% 0.43/1.07  This is a near-Horn, non-equality  problem
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  Options Used:
% 0.43/1.07  
% 0.43/1.07  useres =            1
% 0.43/1.07  useparamod =        0
% 0.43/1.07  useeqrefl =         0
% 0.43/1.07  useeqfact =         0
% 0.43/1.07  usefactor =         1
% 0.43/1.07  usesimpsplitting =  0
% 0.43/1.07  usesimpdemod =      0
% 0.43/1.07  usesimpres =        4
% 0.43/1.07  
% 0.43/1.07  resimpinuse      =  1000
% 0.43/1.07  resimpclauses =     20000
% 0.43/1.07  substype =          standard
% 0.43/1.07  backwardsubs =      1
% 0.43/1.07  selectoldest =      5
% 0.43/1.07  
% 0.43/1.07  litorderings [0] =  split
% 0.43/1.07  litorderings [1] =  liftord
% 0.43/1.07  
% 0.43/1.07  termordering =      none
% 0.43/1.07  
% 0.43/1.07  litapriori =        1
% 0.43/1.07  termapriori =       0
% 0.43/1.07  litaposteriori =    0
% 0.43/1.07  termaposteriori =   0
% 0.43/1.07  demodaposteriori =  0
% 0.43/1.07  ordereqreflfact =   0
% 0.43/1.07  
% 0.43/1.07  litselect =         negative
% 0.43/1.07  
% 0.43/1.07  maxweight =         30000
% 0.43/1.07  maxdepth =          30000
% 0.43/1.07  maxlength =         115
% 0.43/1.07  maxnrvars =         195
% 0.43/1.07  excuselevel =       0
% 0.43/1.07  increasemaxweight = 0
% 0.43/1.07  
% 0.43/1.07  maxselected =       10000000
% 0.43/1.07  maxnrclauses =      10000000
% 0.43/1.07  
% 0.43/1.07  showgenerated =    0
% 0.43/1.07  showkept =         0
% 0.43/1.07  showselected =     0
% 0.43/1.07  showdeleted =      0
% 0.43/1.07  showresimp =       1
% 0.43/1.07  showstatus =       2000
% 0.43/1.07  
% 0.43/1.07  prologoutput =     0
% 0.43/1.07  nrgoals =          5000000
% 0.43/1.07  totalproof =       1
% 0.43/1.07  
% 0.43/1.07  Symbols occurring in the translation:
% 0.43/1.07  
% 0.43/1.07  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.43/1.07  .  [1, 2]      (w:1, o:15, a:1, s:1, b:0), 
% 0.43/1.07  !  [4, 1]      (w:1, o:8, a:1, s:1, b:0), 
% 0.43/1.07  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.43/1.07  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.43/1.07  p  [36, 1]      (w:1, o:13, a:1, s:1, b:0), 
% 0.43/1.07  q  [37, 1]      (w:1, o:14, a:1, s:1, b:0), 
% 0.43/1.07  skol1  [38, 0]      (w:1, o:7, a:1, s:1, b:0).
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  Starting Search:
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  Bliksems!, er is een bewijs:
% 0.43/1.07  % SZS status Theorem
% 0.43/1.07  % SZS output start Refutation
% 0.43/1.07  
% 0.43/1.07  (0) {G0,W5,D2,L2,V1,M1} I { q( X ), ! p( X ) }.
% 0.43/1.07  (1) {G0,W2,D2,L1,V1,M1} I { p( X ) }.
% 0.43/1.07  (2) {G0,W3,D2,L1,V0,M1} I { ! q( skol1 ) }.
% 0.43/1.07  (3) {G1,W2,D2,L1,V1,M1} S(0);r(1) { q( X ) }.
% 0.43/1.07  (4) {G2,W0,D0,L0,V0,M0} R(3,2) {  }.
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  % SZS output end Refutation
% 0.43/1.07  found a proof!
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  Unprocessed initial clauses:
% 0.43/1.07  
% 0.43/1.07  (6) {G0,W5,D2,L2,V1,M2}  { ! p( X ), q( X ) }.
% 0.43/1.07  (7) {G0,W2,D2,L1,V1,M1}  { p( X ) }.
% 0.43/1.07  (8) {G0,W3,D2,L1,V0,M1}  { ! q( skol1 ) }.
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  Total Proof:
% 0.43/1.07  
% 0.43/1.07  subsumption: (0) {G0,W5,D2,L2,V1,M1} I { q( X ), ! p( X ) }.
% 0.43/1.07  parent0: (6) {G0,W5,D2,L2,V1,M2}  { ! p( X ), q( X ) }.
% 0.43/1.07  substitution0:
% 0.43/1.07     X := X
% 0.43/1.07  end
% 0.43/1.07  permutation0:
% 0.43/1.07     0 ==> 1
% 0.43/1.07     1 ==> 0
% 0.43/1.07  end
% 0.43/1.07  
% 0.43/1.07  subsumption: (1) {G0,W2,D2,L1,V1,M1} I { p( X ) }.
% 0.43/1.07  parent0: (7) {G0,W2,D2,L1,V1,M1}  { p( X ) }.
% 0.43/1.07  substitution0:
% 0.43/1.07     X := X
% 0.43/1.07  end
% 0.43/1.07  permutation0:
% 0.43/1.07     0 ==> 0
% 0.43/1.07  end
% 0.43/1.07  
% 0.43/1.07  subsumption: (2) {G0,W3,D2,L1,V0,M1} I { ! q( skol1 ) }.
% 0.43/1.07  parent0: (8) {G0,W3,D2,L1,V0,M1}  { ! q( skol1 ) }.
% 0.43/1.07  substitution0:
% 0.43/1.07  end
% 0.43/1.07  permutation0:
% 0.43/1.07     0 ==> 0
% 0.43/1.07  end
% 0.43/1.07  
% 0.43/1.07  resolution: (9) {G1,W2,D2,L1,V1,M1}  { q( X ) }.
% 0.43/1.07  parent0[1]: (0) {G0,W5,D2,L2,V1,M1} I { q( X ), ! p( X ) }.
% 0.43/1.07  parent1[0]: (1) {G0,W2,D2,L1,V1,M1} I { p( X ) }.
% 0.43/1.07  substitution0:
% 0.43/1.07     X := X
% 0.43/1.07  end
% 0.43/1.07  substitution1:
% 0.43/1.07     X := X
% 0.43/1.07  end
% 0.43/1.07  
% 0.43/1.07  subsumption: (3) {G1,W2,D2,L1,V1,M1} S(0);r(1) { q( X ) }.
% 0.43/1.07  parent0: (9) {G1,W2,D2,L1,V1,M1}  { q( X ) }.
% 0.43/1.07  substitution0:
% 0.43/1.07     X := X
% 0.43/1.07  end
% 0.43/1.07  permutation0:
% 0.43/1.07     0 ==> 0
% 0.43/1.07  end
% 0.43/1.07  
% 0.43/1.07  resolution: (10) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.43/1.07  parent0[0]: (2) {G0,W3,D2,L1,V0,M1} I { ! q( skol1 ) }.
% 0.43/1.07  parent1[0]: (3) {G1,W2,D2,L1,V1,M1} S(0);r(1) { q( X ) }.
% 0.43/1.07  substitution0:
% 0.43/1.07  end
% 0.43/1.07  substitution1:
% 0.43/1.07     X := skol1
% 0.43/1.07  end
% 0.43/1.07  
% 0.43/1.07  subsumption: (4) {G2,W0,D0,L0,V0,M0} R(3,2) {  }.
% 0.43/1.07  parent0: (10) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.43/1.07  substitution0:
% 0.43/1.07  end
% 0.43/1.07  permutation0:
% 0.43/1.07  end
% 0.43/1.07  
% 0.43/1.07  Proof check complete!
% 0.43/1.07  
% 0.43/1.07  Memory use:
% 0.43/1.07  
% 0.43/1.07  space for terms:        48
% 0.43/1.07  space for clauses:      238
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  clauses generated:      5
% 0.43/1.07  clauses kept:           5
% 0.43/1.07  clauses selected:       3
% 0.43/1.07  clauses deleted:        1
% 0.43/1.07  clauses inuse deleted:  0
% 0.43/1.07  
% 0.43/1.07  subsentry:          0
% 0.43/1.07  literals s-matched: 0
% 0.43/1.07  literals matched:   0
% 0.43/1.07  full subsumption:   0
% 0.43/1.07  
% 0.43/1.07  checksum:           993
% 0.43/1.07  
% 0.43/1.07  
% 0.43/1.07  Bliksem ended
%------------------------------------------------------------------------------