TSTP Solution File: SYN951+1 by Metis---2.4
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%------------------------------------------------------------------------------
% File : Metis---2.4
% Problem : SYN951+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : metis --show proof --show saturation %s
% Computer : n005.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 09:12:24 EDT 2022
% Result : Theorem 0.13s 0.35s
% Output : CNFRefutation 0.13s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 1
% Syntax : Number of formulae : 13 ( 6 unt; 0 def)
% Number of atoms : 41 ( 0 equ)
% Maximal formula atoms : 7 ( 3 avg)
% Number of connectives : 38 ( 10 ~; 3 |; 16 &)
% ( 0 <=>; 9 =>; 0 <=; 0 <~>)
% Maximal formula depth : 9 ( 4 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 4 prp; 0-1 aty)
% Number of functors : 0 ( 0 usr; 0 con; --- aty)
% Number of variables : 14 ( 0 sgn 0 !; 14 ?)
% Comments :
%------------------------------------------------------------------------------
fof(prove_this,conjecture,
( ? [X] : p(X)
=> ( ? [X] : p(X)
& ( a
=> ( ( b
| ~ b )
& ( q
=> q ) ) ) ) ) ).
fof(subgoal_0,plain,
( ? [X] : p(X)
=> ? [X] : p(X) ),
inference(strip,[],[prove_this]) ).
fof(subgoal_1,plain,
( ( ? [X] : p(X)
& ? [X] : p(X)
& a
& ~ b )
=> ~ b ),
inference(strip,[],[prove_this]) ).
fof(subgoal_2,plain,
( ( ? [X] : p(X)
& ? [X] : p(X)
& a
& ( b
| ~ b )
& q )
=> q ),
inference(strip,[],[prove_this]) ).
fof(negate_0_0,plain,
~ ( ? [X] : p(X)
=> ? [X] : p(X) ),
inference(negate,[],[subgoal_0]) ).
fof(normalize_0_0,plain,
$false,
inference(canonicalize,[],[negate_0_0]) ).
cnf(refute_0_0,plain,
$false,
inference(canonicalize,[],[normalize_0_0]) ).
fof(negate_1_0,plain,
~ ( ( ? [X] : p(X)
& ? [X] : p(X)
& a
& ~ b )
=> ~ b ),
inference(negate,[],[subgoal_1]) ).
fof(normalize_1_0,plain,
$false,
inference(canonicalize,[],[negate_1_0]) ).
cnf(refute_1_0,plain,
$false,
inference(canonicalize,[],[normalize_1_0]) ).
fof(negate_2_0,plain,
~ ( ( ? [X] : p(X)
& ? [X] : p(X)
& a
& ( b
| ~ b )
& q )
=> q ),
inference(negate,[],[subgoal_2]) ).
fof(normalize_2_0,plain,
$false,
inference(canonicalize,[],[negate_2_0]) ).
cnf(refute_2_0,plain,
$false,
inference(canonicalize,[],[normalize_2_0]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12 % Problem : SYN951+1 : TPTP v8.1.0. Released v3.1.0.
% 0.04/0.13 % Command : metis --show proof --show saturation %s
% 0.13/0.34 % Computer : n005.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Mon Jul 11 12:20:06 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.13/0.35 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% 0.13/0.35 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.13/0.35
% 0.13/0.35 % SZS output start CNFRefutation for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
% 0.13/0.35
%------------------------------------------------------------------------------