TSTP Solution File: SYN949+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SYN949+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:25:33 EDT 2022

% Result   : Theorem 1.95s 2.12s
% Output   : Refutation 1.95s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    2
%            Number of leaves      :    5
% Syntax   : Number of clauses     :    8 (   5 unt;   0 nHn;   8 RR)
%            Number of literals    :   11 (   0 equ;   4 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    5 (   4 usr;   1 prp; 0-2 aty)
%            Number of functors    :    2 (   2 usr;   2 con; 0-0 aty)
%            Number of variables   :    5 (   1 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ s(A)
    | p(A) ),
    file('SYN949+1.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ r(A,B)
    | q(A,B) ),
    file('SYN949+1.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ p(A)
    | ~ q(A,B) ),
    file('SYN949+1.p',unknown),
    [] ).

cnf(5,axiom,
    s(dollar_c2),
    file('SYN949+1.p',unknown),
    [] ).

cnf(6,axiom,
    r(dollar_c2,dollar_c1),
    file('SYN949+1.p',unknown),
    [] ).

cnf(8,plain,
    p(dollar_c2),
    inference(hyper,[status(thm)],[5,1]),
    [iquote('hyper,5,1')] ).

cnf(9,plain,
    q(dollar_c2,dollar_c1),
    inference(hyper,[status(thm)],[6,2]),
    [iquote('hyper,6,2')] ).

cnf(10,plain,
    $false,
    inference(hyper,[status(thm)],[9,3,8]),
    [iquote('hyper,9,3,8')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : SYN949+1 : TPTP v8.1.0. Released v3.1.0.
% 0.06/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n026.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 11:34:24 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.95/2.11  ----- Otter 3.3f, August 2004 -----
% 1.95/2.11  The process was started by sandbox2 on n026.cluster.edu,
% 1.95/2.11  Wed Jul 27 11:34:24 2022
% 1.95/2.11  The command was "./otter".  The process ID is 23650.
% 1.95/2.11  
% 1.95/2.11  set(prolog_style_variables).
% 1.95/2.11  set(auto).
% 1.95/2.11     dependent: set(auto1).
% 1.95/2.11     dependent: set(process_input).
% 1.95/2.11     dependent: clear(print_kept).
% 1.95/2.11     dependent: clear(print_new_demod).
% 1.95/2.11     dependent: clear(print_back_demod).
% 1.95/2.11     dependent: clear(print_back_sub).
% 1.95/2.11     dependent: set(control_memory).
% 1.95/2.11     dependent: assign(max_mem, 12000).
% 1.95/2.11     dependent: assign(pick_given_ratio, 4).
% 1.95/2.11     dependent: assign(stats_level, 1).
% 1.95/2.11     dependent: assign(max_seconds, 10800).
% 1.95/2.11  clear(print_given).
% 1.95/2.11  
% 1.95/2.11  formula_list(usable).
% 1.95/2.11  -(all A B C (s(A)&s(B)&r(B,C)& (all X (s(X)->p(X)))& (all X Y (r(X,Y)->q(X,Y)))-> (exists X Y (p(X)&q(X,Y))))).
% 1.95/2.11  end_of_list.
% 1.95/2.11  
% 1.95/2.11  -------> usable clausifies to:
% 1.95/2.11  
% 1.95/2.11  list(usable).
% 1.95/2.11  0 [] s($c3).
% 1.95/2.11  0 [] s($c2).
% 1.95/2.11  0 [] r($c2,$c1).
% 1.95/2.11  0 [] -s(X)|p(X).
% 1.95/2.11  0 [] -r(X1,Y)|q(X1,Y).
% 1.95/2.11  0 [] -p(X2)| -q(X2,X3).
% 1.95/2.11  end_of_list.
% 1.95/2.11  
% 1.95/2.11  SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=2.
% 1.95/2.11  
% 1.95/2.11  This is a Horn set without equality.  The strategy will
% 1.95/2.12  be hyperresolution, with satellites in sos and nuclei
% 1.95/2.12  in usable.
% 1.95/2.12  
% 1.95/2.12     dependent: set(hyper_res).
% 1.95/2.12     dependent: clear(order_hyper).
% 1.95/2.12  
% 1.95/2.12  ------------> process usable:
% 1.95/2.12  ** KEPT (pick-wt=4): 1 [] -s(A)|p(A).
% 1.95/2.12  ** KEPT (pick-wt=6): 2 [] -r(A,B)|q(A,B).
% 1.95/2.12  ** KEPT (pick-wt=5): 3 [] -p(A)| -q(A,B).
% 1.95/2.12  
% 1.95/2.12  ------------> process sos:
% 1.95/2.12  ** KEPT (pick-wt=2): 4 [] s($c3).
% 1.95/2.12  ** KEPT (pick-wt=2): 5 [] s($c2).
% 1.95/2.12  ** KEPT (pick-wt=3): 6 [] r($c2,$c1).
% 1.95/2.12  
% 1.95/2.12  ======= end of input processing =======
% 1.95/2.12  
% 1.95/2.12  =========== start of search ===========
% 1.95/2.12  
% 1.95/2.12  -------- PROOF -------- 
% 1.95/2.12  
% 1.95/2.12  -----> EMPTY CLAUSE at   0.00 sec ----> 10 [hyper,9,3,8] $F.
% 1.95/2.12  
% 1.95/2.12  Length of proof is 2.  Level of proof is 1.
% 1.95/2.12  
% 1.95/2.12  ---------------- PROOF ----------------
% 1.95/2.12  % SZS status Theorem
% 1.95/2.12  % SZS output start Refutation
% See solution above
% 1.95/2.12  ------------ end of proof -------------
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Search stopped by max_proofs option.
% 1.95/2.12  
% 1.95/2.12  
% 1.95/2.12  Search stopped by max_proofs option.
% 1.95/2.12  
% 1.95/2.12  ============ end of search ============
% 1.95/2.12  
% 1.95/2.12  -------------- statistics -------------
% 1.95/2.12  clauses given                  6
% 1.95/2.12  clauses generated              4
% 1.95/2.12  clauses kept                   9
% 1.95/2.12  clauses forward subsumed       0
% 1.95/2.12  clauses back subsumed          0
% 1.95/2.12  Kbytes malloced              976
% 1.95/2.12  
% 1.95/2.12  ----------- times (seconds) -----------
% 1.95/2.12  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.95/2.12  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.95/2.12  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.95/2.12  
% 1.95/2.12  That finishes the proof of the theorem.
% 1.95/2.12  
% 1.95/2.12  Process 23650 finished Wed Jul 27 11:34:26 2022
% 1.95/2.12  Otter interrupted
% 1.95/2.12  PROOF FOUND
%------------------------------------------------------------------------------