TSTP Solution File: SYN946+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SYN946+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n009.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Thu Jul 21 02:58:19 EDT 2022

% Result   : Theorem 0.68s 1.05s
% Output   : Refutation 0.68s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SYN946+1 : TPTP v8.1.0. Released v3.1.0.
% 0.07/0.12  % Command  : bliksem %s
% 0.12/0.33  % Computer : n009.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % DateTime : Mon Jul 11 20:06:52 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.68/1.05  *** allocated 10000 integers for termspace/termends
% 0.68/1.05  *** allocated 10000 integers for clauses
% 0.68/1.05  *** allocated 10000 integers for justifications
% 0.68/1.05  Bliksem 1.12
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  Automatic Strategy Selection
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  Clauses:
% 0.68/1.05  
% 0.68/1.05  { p( X ) }.
% 0.68/1.05  { q( skol1 ) }.
% 0.68/1.05  { ! p( skol2 ) }.
% 0.68/1.05  { ! r( X ) }.
% 0.68/1.05  
% 0.68/1.05  percentage equality = 0.000000, percentage horn = 1.000000
% 0.68/1.05  This is a near-Horn, non-equality  problem
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  Options Used:
% 0.68/1.05  
% 0.68/1.05  useres =            1
% 0.68/1.05  useparamod =        0
% 0.68/1.05  useeqrefl =         0
% 0.68/1.05  useeqfact =         0
% 0.68/1.05  usefactor =         1
% 0.68/1.05  usesimpsplitting =  0
% 0.68/1.05  usesimpdemod =      0
% 0.68/1.05  usesimpres =        4
% 0.68/1.05  
% 0.68/1.05  resimpinuse      =  1000
% 0.68/1.05  resimpclauses =     20000
% 0.68/1.05  substype =          standard
% 0.68/1.05  backwardsubs =      1
% 0.68/1.05  selectoldest =      5
% 0.68/1.05  
% 0.68/1.05  litorderings [0] =  split
% 0.68/1.05  litorderings [1] =  liftord
% 0.68/1.05  
% 0.68/1.05  termordering =      none
% 0.68/1.05  
% 0.68/1.05  litapriori =        1
% 0.68/1.05  termapriori =       0
% 0.68/1.05  litaposteriori =    0
% 0.68/1.05  termaposteriori =   0
% 0.68/1.05  demodaposteriori =  0
% 0.68/1.05  ordereqreflfact =   0
% 0.68/1.05  
% 0.68/1.05  litselect =         negative
% 0.68/1.05  
% 0.68/1.05  maxweight =         30000
% 0.68/1.05  maxdepth =          30000
% 0.68/1.05  maxlength =         115
% 0.68/1.05  maxnrvars =         195
% 0.68/1.05  excuselevel =       0
% 0.68/1.05  increasemaxweight = 0
% 0.68/1.05  
% 0.68/1.05  maxselected =       10000000
% 0.68/1.05  maxnrclauses =      10000000
% 0.68/1.05  
% 0.68/1.05  showgenerated =    0
% 0.68/1.05  showkept =         0
% 0.68/1.05  showselected =     0
% 0.68/1.05  showdeleted =      0
% 0.68/1.05  showresimp =       1
% 0.68/1.05  showstatus =       2000
% 0.68/1.05  
% 0.68/1.05  prologoutput =     0
% 0.68/1.05  nrgoals =          5000000
% 0.68/1.05  totalproof =       1
% 0.68/1.05  
% 0.68/1.05  Symbols occurring in the translation:
% 0.68/1.05  
% 0.68/1.05  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.68/1.05  .  [1, 2]      (w:1, o:19, a:1, s:1, b:0), 
% 0.68/1.05  !  [4, 1]      (w:1, o:11, a:1, s:1, b:0), 
% 0.68/1.05  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.68/1.05  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.68/1.05  p  [36, 1]      (w:1, o:16, a:1, s:1, b:0), 
% 0.68/1.05  q  [38, 1]      (w:1, o:17, a:1, s:1, b:0), 
% 0.68/1.05  r  [40, 1]      (w:1, o:18, a:1, s:1, b:0), 
% 0.68/1.05  skol1  [41, 0]      (w:1, o:9, a:1, s:1, b:0), 
% 0.68/1.05  skol2  [42, 0]      (w:1, o:10, a:1, s:1, b:0).
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  Starting Search:
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  Bliksems!, er is een bewijs:
% 0.68/1.05  % SZS status Theorem
% 0.68/1.05  % SZS output start Refutation
% 0.68/1.05  
% 0.68/1.05  (0) {G0,W2,D2,L1,V1,M1} I { p( X ) }.
% 0.68/1.05  (2) {G1,W0,D0,L0,V0,M0} I;r(0) {  }.
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  % SZS output end Refutation
% 0.68/1.05  found a proof!
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  Unprocessed initial clauses:
% 0.68/1.05  
% 0.68/1.05  (4) {G0,W2,D2,L1,V1,M1}  { p( X ) }.
% 0.68/1.05  (5) {G0,W2,D2,L1,V0,M1}  { q( skol1 ) }.
% 0.68/1.05  (6) {G0,W3,D2,L1,V0,M1}  { ! p( skol2 ) }.
% 0.68/1.05  (7) {G0,W3,D2,L1,V1,M1}  { ! r( X ) }.
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  Total Proof:
% 0.68/1.05  
% 0.68/1.05  subsumption: (0) {G0,W2,D2,L1,V1,M1} I { p( X ) }.
% 0.68/1.05  parent0: (4) {G0,W2,D2,L1,V1,M1}  { p( X ) }.
% 0.68/1.05  substitution0:
% 0.68/1.05     X := X
% 0.68/1.05  end
% 0.68/1.05  permutation0:
% 0.68/1.05     0 ==> 0
% 0.68/1.05  end
% 0.68/1.05  
% 0.68/1.05  resolution: (8) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.68/1.05  parent0[0]: (6) {G0,W3,D2,L1,V0,M1}  { ! p( skol2 ) }.
% 0.68/1.05  parent1[0]: (0) {G0,W2,D2,L1,V1,M1} I { p( X ) }.
% 0.68/1.05  substitution0:
% 0.68/1.05  end
% 0.68/1.05  substitution1:
% 0.68/1.05     X := skol2
% 0.68/1.05  end
% 0.68/1.05  
% 0.68/1.05  subsumption: (2) {G1,W0,D0,L0,V0,M0} I;r(0) {  }.
% 0.68/1.05  parent0: (8) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.68/1.05  substitution0:
% 0.68/1.05  end
% 0.68/1.05  permutation0:
% 0.68/1.05  end
% 0.68/1.05  
% 0.68/1.05  Proof check complete!
% 0.68/1.05  
% 0.68/1.05  Memory use:
% 0.68/1.05  
% 0.68/1.05  space for terms:        43
% 0.68/1.05  space for clauses:      118
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  clauses generated:      3
% 0.68/1.05  clauses kept:           3
% 0.68/1.05  clauses selected:       0
% 0.68/1.05  clauses deleted:        0
% 0.68/1.05  clauses inuse deleted:  0
% 0.68/1.05  
% 0.68/1.05  subsentry:          0
% 0.68/1.05  literals s-matched: 0
% 0.68/1.05  literals matched:   0
% 0.68/1.05  full subsumption:   0
% 0.68/1.05  
% 0.68/1.05  checksum:           2147483397
% 0.68/1.05  
% 0.68/1.05  
% 0.68/1.05  Bliksem ended
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