TSTP Solution File: SYN940+1 by Otter---3.3
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%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : SYN940+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n011.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:25:31 EDT 2022
% Result : Theorem 1.89s 2.06s
% Output : Refutation 1.89s
% Verified :
% SZS Type : Refutation
% Derivation depth : 3
% Number of leaves : 4
% Syntax : Number of clauses : 7 ( 4 unt; 0 nHn; 2 RR)
% Number of literals : 13 ( 0 equ; 7 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 4 ( 3 usr; 1 prp; 0-1 aty)
% Number of functors : 3 ( 3 usr; 2 con; 0-1 aty)
% Number of variables : 8 ( 6 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
( p(f(A))
| ~ q(B) ),
file('SYN940+1.p',unknown),
[] ).
cnf(2,axiom,
( ~ p(A)
| r(B)
| ~ q(A) ),
file('SYN940+1.p',unknown),
[] ).
cnf(3,axiom,
( ~ p(A)
| ~ r(dollar_c2)
| ~ r(dollar_c1)
| ~ q(A) ),
file('SYN940+1.p',unknown),
[] ).
cnf(4,axiom,
q(f(A)),
file('SYN940+1.p',unknown),
[] ).
cnf(5,plain,
p(f(A)),
inference(hyper,[status(thm)],[4,1]),
[iquote('hyper,4,1')] ).
cnf(6,plain,
r(A),
inference(hyper,[status(thm)],[5,2,4]),
[iquote('hyper,5,2,4')] ).
cnf(7,plain,
$false,
inference(hyper,[status(thm)],[6,3,5,6,4]),
[iquote('hyper,6,3,5,6,4')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11 % Problem : SYN940+1 : TPTP v8.1.0. Released v3.1.0.
% 0.11/0.12 % Command : otter-tptp-script %s
% 0.12/0.33 % Computer : n011.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Wed Jul 27 11:20:25 EDT 2022
% 0.12/0.33 % CPUTime :
% 1.89/2.06 ----- Otter 3.3f, August 2004 -----
% 1.89/2.06 The process was started by sandbox on n011.cluster.edu,
% 1.89/2.06 Wed Jul 27 11:20:25 2022
% 1.89/2.06 The command was "./otter". The process ID is 14391.
% 1.89/2.06
% 1.89/2.06 set(prolog_style_variables).
% 1.89/2.06 set(auto).
% 1.89/2.06 dependent: set(auto1).
% 1.89/2.06 dependent: set(process_input).
% 1.89/2.06 dependent: clear(print_kept).
% 1.89/2.06 dependent: clear(print_new_demod).
% 1.89/2.06 dependent: clear(print_back_demod).
% 1.89/2.06 dependent: clear(print_back_sub).
% 1.89/2.06 dependent: set(control_memory).
% 1.89/2.06 dependent: assign(max_mem, 12000).
% 1.89/2.06 dependent: assign(pick_given_ratio, 4).
% 1.89/2.06 dependent: assign(stats_level, 1).
% 1.89/2.06 dependent: assign(max_seconds, 10800).
% 1.89/2.06 clear(print_given).
% 1.89/2.06
% 1.89/2.06 formula_list(usable).
% 1.89/2.06 -(all B C ((all Z q(f(Z)))-> (exists X Y ((p(f(Y))->p(X)& (r(Y)->r(B)&r(C)))&q(X))))).
% 1.89/2.06 end_of_list.
% 1.89/2.06
% 1.89/2.06 -------> usable clausifies to:
% 1.89/2.06
% 1.89/2.06 list(usable).
% 1.89/2.06 0 [] q(f(Z)).
% 1.89/2.06 0 [] p(f(Y))| -q(X).
% 1.89/2.06 0 [] -p(X)|r(Y)| -q(X).
% 1.89/2.06 0 [] -p(X)| -r($c2)| -r($c1)| -q(X).
% 1.89/2.06 end_of_list.
% 1.89/2.06
% 1.89/2.06 SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=4.
% 1.89/2.06
% 1.89/2.06 This is a Horn set without equality. The strategy will
% 1.89/2.06 be hyperresolution, with satellites in sos and nuclei
% 1.89/2.06 in usable.
% 1.89/2.06
% 1.89/2.06 dependent: set(hyper_res).
% 1.89/2.06 dependent: clear(order_hyper).
% 1.89/2.06
% 1.89/2.06 ------------> process usable:
% 1.89/2.06 ** KEPT (pick-wt=5): 1 [] p(f(A))| -q(B).
% 1.89/2.06 ** KEPT (pick-wt=6): 2 [] -p(A)|r(B)| -q(A).
% 1.89/2.06 ** KEPT (pick-wt=8): 3 [] -p(A)| -r($c2)| -r($c1)| -q(A).
% 1.89/2.06
% 1.89/2.06 ------------> process sos:
% 1.89/2.06 ** KEPT (pick-wt=3): 4 [] q(f(A)).
% 1.89/2.06
% 1.89/2.06 ======= end of input processing =======
% 1.89/2.06
% 1.89/2.06 =========== start of search ===========
% 1.89/2.06
% 1.89/2.06 -------- PROOF --------
% 1.89/2.06
% 1.89/2.06 -----> EMPTY CLAUSE at 0.00 sec ----> 7 [hyper,6,3,5,6,4] $F.
% 1.89/2.06
% 1.89/2.06 Length of proof is 2. Level of proof is 2.
% 1.89/2.06
% 1.89/2.06 ---------------- PROOF ----------------
% 1.89/2.06 % SZS status Theorem
% 1.89/2.06 % SZS output start Refutation
% See solution above
% 1.89/2.06 ------------ end of proof -------------
% 1.89/2.06
% 1.89/2.06
% 1.89/2.06 Search stopped by max_proofs option.
% 1.89/2.06
% 1.89/2.06
% 1.89/2.06 Search stopped by max_proofs option.
% 1.89/2.06
% 1.89/2.06 ============ end of search ============
% 1.89/2.06
% 1.89/2.06 -------------- statistics -------------
% 1.89/2.06 clauses given 3
% 1.89/2.06 clauses generated 3
% 1.89/2.06 clauses kept 6
% 1.89/2.06 clauses forward subsumed 0
% 1.89/2.06 clauses back subsumed 2
% 1.89/2.06 Kbytes malloced 976
% 1.89/2.06
% 1.89/2.06 ----------- times (seconds) -----------
% 1.89/2.06 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.89/2.06 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.89/2.06 wall-clock time 2 (0 hr, 0 min, 2 sec)
% 1.89/2.06
% 1.89/2.06 That finishes the proof of the theorem.
% 1.89/2.06
% 1.89/2.06 Process 14391 finished Wed Jul 27 11:20:27 2022
% 1.89/2.06 Otter interrupted
% 1.89/2.06 PROOF FOUND
%------------------------------------------------------------------------------