TSTP Solution File: SYN931+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYN931+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:13:19 EDT 2023

% Result   : Theorem 3.75s 3.89s
% Output   : Proof 3.75s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem    : SYN931+1 : TPTP v8.1.2. Released v3.1.0.
% 0.10/0.13  % Command    : duper %s
% 0.14/0.34  % Computer : n023.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit   : 300
% 0.14/0.34  % WCLimit    : 300
% 0.14/0.34  % DateTime   : Sat Aug 26 18:09:56 EDT 2023
% 0.14/0.34  % CPUTime    : 
% 3.75/3.89  SZS status Theorem for theBenchmark.p
% 3.75/3.89  SZS output start Proof for theBenchmark.p
% 3.75/3.89  Clause #0 (by assumption #[]): Eq (Not (Iff (Exists fun X => And (p X) c) (And (Exists fun X => p X) c))) True
% 3.75/3.89  Clause #1 (by betaEtaReduce #[0]): Eq (Not (Iff (Exists fun X => And (p X) c) (And (Exists p) c))) True
% 3.75/3.89  Clause #2 (by clausification #[1]): Eq (Iff (Exists fun X => And (p X) c) (And (Exists p) c)) False
% 3.75/3.89  Clause #3 (by clausification #[2]): Or (Eq (Exists fun X => And (p X) c) False) (Eq (And (Exists p) c) False)
% 3.75/3.89  Clause #4 (by clausification #[2]): Or (Eq (Exists fun X => And (p X) c) True) (Eq (And (Exists p) c) True)
% 3.75/3.89  Clause #5 (by clausification #[3]): ∀ (a : Iota), Or (Eq (And (Exists p) c) False) (Eq (And (p a) c) False)
% 3.75/3.89  Clause #6 (by clausification #[5]): ∀ (a : Iota), Or (Eq (And (p a) c) False) (Or (Eq (Exists p) False) (Eq c False))
% 3.75/3.89  Clause #7 (by clausification #[6]): ∀ (a : Iota), Or (Eq (Exists p) False) (Or (Eq c False) (Or (Eq (p a) False) (Eq c False)))
% 3.75/3.89  Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq c False) (Or (Eq (p a) False) (Or (Eq c False) (Eq (p a_1) False)))
% 3.75/3.89  Clause #9 (by eliminate duplicate literals #[8]): ∀ (a a_1 : Iota), Or (Eq c False) (Or (Eq (p a) False) (Eq (p a_1) False))
% 3.75/3.89  Clause #10 (by clausification #[4]): ∀ (a : Iota), Or (Eq (And (Exists p) c) True) (Eq (And (p (skS.0 0 a)) c) True)
% 3.75/3.89  Clause #11 (by clausification #[10]): ∀ (a : Iota), Or (Eq (And (p (skS.0 0 a)) c) True) (Eq c True)
% 3.75/3.89  Clause #12 (by clausification #[10]): ∀ (a : Iota), Or (Eq (And (p (skS.0 0 a)) c) True) (Eq (Exists p) True)
% 3.75/3.89  Clause #13 (by clausification #[11]): Or (Eq c True) (Eq c True)
% 3.75/3.89  Clause #15 (by eliminate duplicate literals #[13]): Eq c True
% 3.75/3.89  Clause #16 (by backward demodulation #[15, 9]): ∀ (a a_1 : Iota), Or (Eq True False) (Or (Eq (p a) False) (Eq (p a_1) False))
% 3.75/3.89  Clause #17 (by clausification #[16]): ∀ (a a_1 : Iota), Or (Eq (p a) False) (Eq (p a_1) False)
% 3.75/3.89  Clause #20 (by clausification #[12]): ∀ (a : Iota), Or (Eq (Exists p) True) (Eq (p (skS.0 0 a)) True)
% 3.75/3.89  Clause #23 (by clausification #[20]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 0 a)) True) (Eq (p (skS.0 2 a_1)) True)
% 3.75/3.89  Clause #24 (by superposition #[23, 17]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 2 a)) True) (Or (Eq True False) (Eq (p a_1) False))
% 3.75/3.89  Clause #29 (by clausification #[24]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 2 a)) True) (Eq (p a_1) False)
% 3.75/3.89  Clause #30 (by superposition #[29, 23]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 2 a)) True) (Or (Eq False True) (Eq (p (skS.0 2 a_1)) True))
% 3.75/3.89  Clause #33 (by clausification #[30]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 2 a)) True) (Eq (p (skS.0 2 a_1)) True)
% 3.75/3.89  Clause #36 (by equality factoring #[33]): ∀ (a : Iota), Or (Ne True True) (Eq (p (skS.0 2 a)) True)
% 3.75/3.89  Clause #37 (by clausification #[36]): ∀ (a : Iota), Or (Eq (p (skS.0 2 a)) True) (Or (Eq True False) (Eq True False))
% 3.75/3.89  Clause #39 (by clausification #[37]): ∀ (a : Iota), Or (Eq (p (skS.0 2 a)) True) (Eq True False)
% 3.75/3.89  Clause #40 (by clausification #[39]): ∀ (a : Iota), Eq (p (skS.0 2 a)) True
% 3.75/3.89  Clause #41 (by superposition #[40, 17]): ∀ (a : Iota), Or (Eq True False) (Eq (p a) False)
% 3.75/3.89  Clause #43 (by clausification #[41]): ∀ (a : Iota), Eq (p a) False
% 3.75/3.89  Clause #44 (by superposition #[43, 40]): Eq False True
% 3.75/3.89  Clause #45 (by clausification #[44]): False
% 3.75/3.89  SZS output end Proof for theBenchmark.p
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