TSTP Solution File: SYN925+1 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : SYN925+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n022.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 06:14:52 EDT 2022
% Result : Theorem 0.20s 0.38s
% Output : CNFRefutation 0.20s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 1
% Syntax : Number of formulae : 6 ( 3 unt; 0 def)
% Number of atoms : 9 ( 0 equ)
% Maximal formula atoms : 2 ( 1 avg)
% Number of connectives : 6 ( 3 ~; 0 |; 1 &)
% ( 0 <=>; 2 =>; 0 <=; 0 <~>)
% Maximal formula depth : 5 ( 3 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-1 aty)
% Number of functors : 1 ( 1 usr; 1 con; 0-0 aty)
% Number of variables : 6 ( 1 sgn 3 !; 2 ?)
% Comments :
%------------------------------------------------------------------------------
fof(prove_this,conjecture,
? [X1] :
( p(X1)
=> ! [X2] : p(X2) ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',prove_this) ).
fof(c_0_1,negated_conjecture,
~ ? [X1] :
( p(X1)
=> ! [X2] : p(X2) ),
inference(assume_negation,[status(cth)],[prove_this]) ).
fof(c_0_2,negated_conjecture,
! [X3] :
( p(X3)
& ~ p(esk1_0) ),
inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(shift_quantors,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_1])])])])]) ).
cnf(c_0_3,negated_conjecture,
~ p(esk1_0),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_4,negated_conjecture,
p(X1),
inference(split_conjunct,[status(thm)],[c_0_2]) ).
cnf(c_0_5,negated_conjecture,
$false,
inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_3,c_0_4])]),
[proof] ).
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.13 % Problem : SYN925+1 : TPTP v8.1.0. Released v3.1.0.
% 0.13/0.14 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.14/0.35 % Computer : n022.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 600
% 0.14/0.35 % DateTime : Mon Jul 11 19:17:25 EDT 2022
% 0.14/0.35 % CPUTime :
% 0.20/0.38 # No SInE strategy applied
% 0.20/0.38 # Auto-Mode selected heuristic G_E___107_C48_F1_PI_AE_Q4_CS_SP_PS_S0Y
% 0.20/0.38 # and selection function SelectMaxLComplexAvoidPosPred.
% 0.20/0.38 #
% 0.20/0.38 # Presaturation interreduction done
% 0.20/0.38
% 0.20/0.38 # Proof found!
% 0.20/0.38 # SZS status Theorem
% 0.20/0.38 # SZS output start CNFRefutation
% See solution above
% 0.20/0.38 # Training examples: 0 positive, 0 negative
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