TSTP Solution File: SYN920+1 by SPASS---3.9
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- Process Solution
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% File : SPASS---3.9
% Problem : SYN920+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n024.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:32:04 EDT 2022
% Result : Theorem 0.18s 0.42s
% Output : Refutation 0.18s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12 % Problem : SYN920+1 : TPTP v8.1.0. Released v3.1.0.
% 0.10/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n024.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Mon Jul 11 21:41:13 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.42
% 0.18/0.42 SPASS V 3.9
% 0.18/0.42 SPASS beiseite: Proof found.
% 0.18/0.42 % SZS status Theorem
% 0.18/0.42 Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.18/0.42 SPASS derived 10 clauses, backtracked 14 clauses, performed 3 splits and kept 29 clauses.
% 0.18/0.42 SPASS allocated 97569 KBytes.
% 0.18/0.42 SPASS spent 0:00:00.08 on the problem.
% 0.18/0.42 0:00:00.03 for the input.
% 0.18/0.42 0:00:00.02 for the FLOTTER CNF translation.
% 0.18/0.42 0:00:00.00 for inferences.
% 0.18/0.42 0:00:00.00 for the backtracking.
% 0.18/0.42 0:00:00.00 for the reduction.
% 0.18/0.42
% 0.18/0.42
% 0.18/0.42 Here is a proof with depth 2, length 30 :
% 0.18/0.42 % SZS output start Refutation
% 0.18/0.42 1[0:Inp] || -> f(skc3)*.
% 0.18/0.42 2[0:Inp] || -> f(skc2)*.
% 0.18/0.42 3[0:Inp] || -> SkC0 g(skc3)*.
% 0.18/0.42 4[0:Inp] || h(skc3)* -> SkC0.
% 0.18/0.42 5[0:Inp] || SkC0 g(skc2)* -> .
% 0.18/0.42 6[0:Inp] h(u) f(u) || -> g(u)*.
% 0.18/0.42 7[0:Inp] g(u) f(u) || -> h(u)*.
% 0.18/0.42 8[0:Inp] f(u) f(v) || -> h(u)* g(v)*.
% 0.18/0.42 16[1:Spt:8.1,8.3] f(u) || -> g(u)*.
% 0.18/0.42 17[1:MRR:7.0,16.1] f(u) || -> h(u)*.
% 0.18/0.42 18[2:Spt:3.0] || -> SkC0*.
% 0.18/0.42 19[2:MRR:5.0,18.0] || g(skc2)*+ -> .
% 0.18/0.42 20[2:Res:16.1,19.0] f(skc2) || -> .
% 0.18/0.42 21[2:SSi:20.0,2.0] || -> .
% 0.18/0.42 22[2:Spt:21.0,3.0,18.0] || SkC0*+ -> .
% 0.18/0.42 23[2:Spt:21.0,3.1] || -> g(skc3)*.
% 0.18/0.42 24[2:MRR:4.1,22.0] || h(skc3)*+ -> .
% 0.18/0.42 25[2:Res:17.1,24.0] f(skc3) || -> .
% 0.18/0.42 26[2:SSi:25.0,1.0,23.0] || -> .
% 0.18/0.42 27[1:Spt:26.0,8.0,8.2] f(u) || -> h(u)*.
% 0.18/0.42 28[1:MRR:6.0,27.1] f(u) || -> g(u)*.
% 0.18/0.42 29[2:Spt:3.0] || -> SkC0*.
% 0.18/0.42 30[2:MRR:5.0,29.0] || g(skc2)*+ -> .
% 0.18/0.42 31[2:Res:28.1,30.0] f(skc2) || -> .
% 0.18/0.42 32[2:SSi:31.0,2.0] || -> .
% 0.18/0.42 33[2:Spt:32.0,3.0,29.0] || SkC0*+ -> .
% 0.18/0.42 34[2:Spt:32.0,3.1] || -> g(skc3)*.
% 0.18/0.42 35[2:MRR:4.1,33.0] || h(skc3)*+ -> .
% 0.18/0.42 36[2:Res:27.1,35.0] f(skc3) || -> .
% 0.18/0.42 37[2:SSi:36.0,1.0,34.0] || -> .
% 0.18/0.42 % SZS output end Refutation
% 0.18/0.42 Formulae used in the proof : prove_this
% 0.18/0.42
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