TSTP Solution File: SYN722+1 by Bliksem---1.12
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Bliksem---1.12
% Problem : SYN722+1 : TPTP v8.1.0. Released v2.5.0.
% Transfm : none
% Format : tptp:raw
% Command : bliksem %s
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Thu Jul 21 02:54:12 EDT 2022
% Result : Theorem 0.42s 1.06s
% Output : Refutation 0.42s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : SYN722+1 : TPTP v8.1.0. Released v2.5.0.
% 0.03/0.12 % Command : bliksem %s
% 0.12/0.31 % Computer : n003.cluster.edu
% 0.12/0.31 % Model : x86_64 x86_64
% 0.12/0.31 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.31 % Memory : 8042.1875MB
% 0.12/0.31 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.31 % CPULimit : 300
% 0.12/0.31 % DateTime : Mon Jul 11 14:23:15 EDT 2022
% 0.12/0.32 % CPUTime :
% 0.42/1.06 *** allocated 10000 integers for termspace/termends
% 0.42/1.06 *** allocated 10000 integers for clauses
% 0.42/1.06 *** allocated 10000 integers for justifications
% 0.42/1.06 Bliksem 1.12
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 Automatic Strategy Selection
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 Clauses:
% 0.42/1.06
% 0.42/1.06 { p( X ), r( X ) }.
% 0.42/1.06 { q( X ) }.
% 0.42/1.06 { p( X ), ! q( X ), ! q( skol1 ), ! q( c ), ! q( d ) }.
% 0.42/1.06 { ! p( a ), ! p( b ) }.
% 0.42/1.06
% 0.42/1.06 percentage equality = 0.000000, percentage horn = 0.750000
% 0.42/1.06 This a non-horn, non-equality problem
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 Options Used:
% 0.42/1.06
% 0.42/1.06 useres = 1
% 0.42/1.06 useparamod = 0
% 0.42/1.06 useeqrefl = 0
% 0.42/1.06 useeqfact = 0
% 0.42/1.06 usefactor = 1
% 0.42/1.06 usesimpsplitting = 0
% 0.42/1.06 usesimpdemod = 0
% 0.42/1.06 usesimpres = 3
% 0.42/1.06
% 0.42/1.06 resimpinuse = 1000
% 0.42/1.06 resimpclauses = 20000
% 0.42/1.06 substype = standard
% 0.42/1.06 backwardsubs = 1
% 0.42/1.06 selectoldest = 5
% 0.42/1.06
% 0.42/1.06 litorderings [0] = split
% 0.42/1.06 litorderings [1] = liftord
% 0.42/1.06
% 0.42/1.06 termordering = none
% 0.42/1.06
% 0.42/1.06 litapriori = 1
% 0.42/1.06 termapriori = 0
% 0.42/1.06 litaposteriori = 0
% 0.42/1.06 termaposteriori = 0
% 0.42/1.06 demodaposteriori = 0
% 0.42/1.06 ordereqreflfact = 0
% 0.42/1.06
% 0.42/1.06 litselect = none
% 0.42/1.06
% 0.42/1.06 maxweight = 15
% 0.42/1.06 maxdepth = 30000
% 0.42/1.06 maxlength = 115
% 0.42/1.06 maxnrvars = 195
% 0.42/1.06 excuselevel = 1
% 0.42/1.06 increasemaxweight = 1
% 0.42/1.06
% 0.42/1.06 maxselected = 10000000
% 0.42/1.06 maxnrclauses = 10000000
% 0.42/1.06
% 0.42/1.06 showgenerated = 0
% 0.42/1.06 showkept = 0
% 0.42/1.06 showselected = 0
% 0.42/1.06 showdeleted = 0
% 0.42/1.06 showresimp = 1
% 0.42/1.06 showstatus = 2000
% 0.42/1.06
% 0.42/1.06 prologoutput = 0
% 0.42/1.06 nrgoals = 5000000
% 0.42/1.06 totalproof = 1
% 0.42/1.06
% 0.42/1.06 Symbols occurring in the translation:
% 0.42/1.06
% 0.42/1.06 {} [0, 0] (w:1, o:2, a:1, s:1, b:0),
% 0.42/1.06 . [1, 2] (w:1, o:22, a:1, s:1, b:0),
% 0.42/1.06 ! [4, 1] (w:0, o:14, a:1, s:1, b:0),
% 0.42/1.06 = [13, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.42/1.06 ==> [14, 2] (w:1, o:0, a:0, s:1, b:0),
% 0.42/1.06 p [36, 1] (w:1, o:19, a:1, s:1, b:0),
% 0.42/1.06 r [37, 1] (w:1, o:21, a:1, s:1, b:0),
% 0.42/1.06 q [38, 1] (w:1, o:20, a:1, s:1, b:0),
% 0.42/1.06 c [41, 0] (w:1, o:10, a:1, s:1, b:0),
% 0.42/1.06 d [42, 0] (w:1, o:11, a:1, s:1, b:0),
% 0.42/1.06 a [43, 0] (w:1, o:12, a:1, s:1, b:0),
% 0.42/1.06 b [44, 0] (w:1, o:9, a:1, s:1, b:0),
% 0.42/1.06 skol1 [45, 0] (w:1, o:13, a:1, s:1, b:0).
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 Starting Search:
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 Bliksems!, er is een bewijs:
% 0.42/1.06 % SZS status Theorem
% 0.42/1.06 % SZS output start Refutation
% 0.42/1.06
% 0.42/1.06 (1) {G0,W2,D2,L1,V1,M1} I { q( X ) }.
% 0.42/1.06 (2) {G1,W8,D2,L4,V1,M1} I;r(1) { p( X ), ! q( c ), ! q( d ), ! q( skol1 )
% 0.42/1.06 }.
% 0.42/1.06 (3) {G0,W4,D2,L2,V0,M1} I { ! p( b ), ! p( a ) }.
% 0.42/1.06 (4) {G2,W2,D2,L1,V1,M1} S(2);r(1);r(1);r(1) { p( X ) }.
% 0.42/1.06 (5) {G3,W0,D0,L0,V0,M0} R(4,3);r(4) { }.
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 % SZS output end Refutation
% 0.42/1.06 found a proof!
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 Unprocessed initial clauses:
% 0.42/1.06
% 0.42/1.06 (7) {G0,W4,D2,L2,V1,M2} { p( X ), r( X ) }.
% 0.42/1.06 (8) {G0,W2,D2,L1,V1,M1} { q( X ) }.
% 0.42/1.06 (9) {G0,W10,D2,L5,V1,M5} { p( X ), ! q( X ), ! q( skol1 ), ! q( c ), ! q(
% 0.42/1.06 d ) }.
% 0.42/1.06 (10) {G0,W4,D2,L2,V0,M2} { ! p( a ), ! p( b ) }.
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 Total Proof:
% 0.42/1.06
% 0.42/1.06 subsumption: (1) {G0,W2,D2,L1,V1,M1} I { q( X ) }.
% 0.42/1.06 parent0: (8) {G0,W2,D2,L1,V1,M1} { q( X ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 X := X
% 0.42/1.06 end
% 0.42/1.06 permutation0:
% 0.42/1.06 0 ==> 0
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 resolution: (23) {G1,W8,D2,L4,V1,M4} { p( X ), ! q( skol1 ), ! q( c ), ! q
% 0.42/1.06 ( d ) }.
% 0.42/1.06 parent0[1]: (9) {G0,W10,D2,L5,V1,M5} { p( X ), ! q( X ), ! q( skol1 ), ! q
% 0.42/1.06 ( c ), ! q( d ) }.
% 0.42/1.06 parent1[0]: (1) {G0,W2,D2,L1,V1,M1} I { q( X ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 X := X
% 0.42/1.06 end
% 0.42/1.06 substitution1:
% 0.42/1.06 X := X
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 subsumption: (2) {G1,W8,D2,L4,V1,M1} I;r(1) { p( X ), ! q( c ), ! q( d ), !
% 0.42/1.06 q( skol1 ) }.
% 0.42/1.06 parent0: (23) {G1,W8,D2,L4,V1,M4} { p( X ), ! q( skol1 ), ! q( c ), ! q( d
% 0.42/1.06 ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 X := X
% 0.42/1.06 end
% 0.42/1.06 permutation0:
% 0.42/1.06 0 ==> 0
% 0.42/1.06 1 ==> 3
% 0.42/1.06 2 ==> 1
% 0.42/1.06 3 ==> 2
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 subsumption: (3) {G0,W4,D2,L2,V0,M1} I { ! p( b ), ! p( a ) }.
% 0.42/1.06 parent0: (10) {G0,W4,D2,L2,V0,M2} { ! p( a ), ! p( b ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 end
% 0.42/1.06 permutation0:
% 0.42/1.06 0 ==> 1
% 0.42/1.06 1 ==> 0
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 resolution: (36) {G1,W6,D2,L3,V1,M3} { p( X ), ! q( d ), ! q( skol1 ) }.
% 0.42/1.06 parent0[1]: (2) {G1,W8,D2,L4,V1,M1} I;r(1) { p( X ), ! q( c ), ! q( d ), !
% 0.42/1.06 q( skol1 ) }.
% 0.42/1.06 parent1[0]: (1) {G0,W2,D2,L1,V1,M1} I { q( X ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 X := X
% 0.42/1.06 end
% 0.42/1.06 substitution1:
% 0.42/1.06 X := c
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 resolution: (39) {G1,W4,D2,L2,V1,M2} { p( X ), ! q( skol1 ) }.
% 0.42/1.06 parent0[1]: (36) {G1,W6,D2,L3,V1,M3} { p( X ), ! q( d ), ! q( skol1 ) }.
% 0.42/1.06 parent1[0]: (1) {G0,W2,D2,L1,V1,M1} I { q( X ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 X := X
% 0.42/1.06 end
% 0.42/1.06 substitution1:
% 0.42/1.06 X := d
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 resolution: (41) {G1,W2,D2,L1,V1,M1} { p( X ) }.
% 0.42/1.06 parent0[1]: (39) {G1,W4,D2,L2,V1,M2} { p( X ), ! q( skol1 ) }.
% 0.42/1.06 parent1[0]: (1) {G0,W2,D2,L1,V1,M1} I { q( X ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 X := X
% 0.42/1.06 end
% 0.42/1.06 substitution1:
% 0.42/1.06 X := skol1
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 subsumption: (4) {G2,W2,D2,L1,V1,M1} S(2);r(1);r(1);r(1) { p( X ) }.
% 0.42/1.06 parent0: (41) {G1,W2,D2,L1,V1,M1} { p( X ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 X := X
% 0.42/1.06 end
% 0.42/1.06 permutation0:
% 0.42/1.06 0 ==> 0
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 resolution: (42) {G1,W2,D2,L1,V0,M1} { ! p( a ) }.
% 0.42/1.06 parent0[0]: (3) {G0,W4,D2,L2,V0,M1} I { ! p( b ), ! p( a ) }.
% 0.42/1.06 parent1[0]: (4) {G2,W2,D2,L1,V1,M1} S(2);r(1);r(1);r(1) { p( X ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 end
% 0.42/1.06 substitution1:
% 0.42/1.06 X := b
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 resolution: (44) {G2,W0,D0,L0,V0,M0} { }.
% 0.42/1.06 parent0[0]: (42) {G1,W2,D2,L1,V0,M1} { ! p( a ) }.
% 0.42/1.06 parent1[0]: (4) {G2,W2,D2,L1,V1,M1} S(2);r(1);r(1);r(1) { p( X ) }.
% 0.42/1.06 substitution0:
% 0.42/1.06 end
% 0.42/1.06 substitution1:
% 0.42/1.06 X := a
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 subsumption: (5) {G3,W0,D0,L0,V0,M0} R(4,3);r(4) { }.
% 0.42/1.06 parent0: (44) {G2,W0,D0,L0,V0,M0} { }.
% 0.42/1.06 substitution0:
% 0.42/1.06 end
% 0.42/1.06 permutation0:
% 0.42/1.06 end
% 0.42/1.06
% 0.42/1.06 Proof check complete!
% 0.42/1.06
% 0.42/1.06 Memory use:
% 0.42/1.06
% 0.42/1.06 space for terms: 122
% 0.42/1.06 space for clauses: 277
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 clauses generated: 6
% 0.42/1.06 clauses kept: 6
% 0.42/1.06 clauses selected: 4
% 0.42/1.06 clauses deleted: 1
% 0.42/1.06 clauses inuse deleted: 0
% 0.42/1.06
% 0.42/1.06 subsentry: 41
% 0.42/1.06 literals s-matched: 0
% 0.42/1.06 literals matched: 0
% 0.42/1.06 full subsumption: 0
% 0.42/1.06
% 0.42/1.06 checksum: 1573959
% 0.42/1.06
% 0.42/1.06
% 0.42/1.06 Bliksem ended
%------------------------------------------------------------------------------