TSTP Solution File: SYN668-1 by SPASS---3.9

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%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN668-1 : TPTP v8.1.0. Released v2.5.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:23:33 EDT 2022

% Result   : Unsatisfiable 2.14s 2.38s
% Output   : Refutation 2.14s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   13 (   7 unt;   0 nHn;  13 RR)
%            Number of literals    :   22 (   0 equ;  12 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    4 (   2 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :   13 (  13 usr;   8 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(7,axiom,
    p2(u,u),
    file('SYN668-1.p',unknown),
    [] ).

cnf(12,axiom,
    p25(c33,c36),
    file('SYN668-1.p',unknown),
    [] ).

cnf(14,axiom,
    p25(c32,c33),
    file('SYN668-1.p',unknown),
    [] ).

cnf(18,axiom,
    ~ p2(u,f18(u,f9(f17(c31)))),
    file('SYN668-1.p',unknown),
    [] ).

cnf(30,axiom,
    ( ~ p2(u,v)
    | ~ p2(u,w)
    | p2(w,v) ),
    file('SYN668-1.p',unknown),
    [] ).

cnf(38,axiom,
    p2(f11(f4(c32),c34),f18(f11(f4(c33),c34),f9(f17(c31)))),
    file('SYN668-1.p',unknown),
    [] ).

cnf(50,axiom,
    ( ~ p25(u,c36)
    | ~ p25(c32,u)
    | p2(f11(f4(u),c34),f11(f4(c32),c34)) ),
    file('SYN668-1.p',unknown),
    [] ).

cnf(104,plain,
    ( ~ p2(u,v)
    | p2(v,u) ),
    inference(res,[status(thm),theory(equality)],[7,30]),
    [iquote('0:Res:7.0,30.0')] ).

cnf(131,plain,
    ( ~ p2(f11(f4(c32),c34),u)
    | p2(u,f18(f11(f4(c33),c34),f9(f17(c31)))) ),
    inference(res,[status(thm),theory(equality)],[38,30]),
    [iquote('0:Res:38.0,30.0')] ).

cnf(446,plain,
    ( ~ p25(u,c36)
    | ~ p25(c32,u)
    | p2(f11(f4(c32),c34),f11(f4(u),c34)) ),
    inference(res,[status(thm),theory(equality)],[50,104]),
    [iquote('0:Res:50.2,104.0')] ).

cnf(750,plain,
    ~ p2(f11(f4(c32),c34),f11(f4(c33),c34)),
    inference(res,[status(thm),theory(equality)],[131,18]),
    [iquote('0:Res:131.1,18.0')] ).

cnf(4274,plain,
    ( ~ p25(c33,c36)
    | ~ p25(c32,c33) ),
    inference(res,[status(thm),theory(equality)],[446,750]),
    [iquote('0:Res:446.2,750.0')] ).

cnf(4276,plain,
    $false,
    inference(mrr,[status(thm)],[4274,12,14]),
    [iquote('0:MRR:4274.0,4274.1,12.0,14.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : SYN668-1 : TPTP v8.1.0. Released v2.5.0.
% 0.11/0.12  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n013.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Tue Jul 12 01:43:15 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 2.14/2.38  
% 2.14/2.38  SPASS V 3.9 
% 2.14/2.38  SPASS beiseite: Proof found.
% 2.14/2.38  % SZS status Theorem
% 2.14/2.38  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 2.14/2.38  SPASS derived 4204 clauses, backtracked 0 clauses, performed 0 splits and kept 2044 clauses.
% 2.14/2.38  SPASS allocated 78968 KBytes.
% 2.14/2.38  SPASS spent	0:00:02.01 on the problem.
% 2.14/2.38  		0:00:00.04 for the input.
% 2.14/2.38  		0:00:00.00 for the FLOTTER CNF translation.
% 2.14/2.38  		0:00:00.05 for inferences.
% 2.14/2.38  		0:00:00.00 for the backtracking.
% 2.14/2.38  		0:00:01.88 for the reduction.
% 2.14/2.38  
% 2.14/2.38  
% 2.14/2.38  Here is a proof with depth 3, length 13 :
% 2.14/2.38  % SZS output start Refutation
% See solution above
% 2.14/2.38  Formulae used in the proof : p2_7 p25_12 p25_14 not_p2_18 p2_30 p2_38 p2_50
% 2.14/2.38  
%------------------------------------------------------------------------------