TSTP Solution File: SYN562-1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN562-1 : TPTP v8.1.0. Released v2.5.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:22:53 EDT 2022

% Result   : Unsatisfiable 0.35s 0.51s
% Output   : Refutation 0.35s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   12 (   7 unt;   0 nHn;  12 RR)
%            Number of literals    :   21 (   0 equ;  11 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :   19 (   7 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-2 aty)
%            Number of functors    :   10 (  10 usr;   6 con; 0-1 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    p2(u,u),
    file('SYN562-1.p',unknown),
    [] ).

cnf(3,axiom,
    ~ p10(u,u),
    file('SYN562-1.p',unknown),
    [] ).

cnf(12,axiom,
    ( ~ p2(u,v)
    | ~ p2(u,w)
    | p2(w,v) ),
    file('SYN562-1.p',unknown),
    [] ).

cnf(14,axiom,
    ( ~ p10(u,v)
    | ~ p2(v,w)
    | ~ p2(u,x)
    | p10(x,w) ),
    file('SYN562-1.p',unknown),
    [] ).

cnf(15,axiom,
    p2(f7(c11),f3(f4(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(c12))))))))))))))))))),
    file('SYN562-1.p',unknown),
    [] ).

cnf(16,axiom,
    p10(f7(c11),f3(f4(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(c12))))))))))))))))))),
    file('SYN562-1.p',unknown),
    [] ).

cnf(19,plain,
    ( ~ p2(u,v)
    | p2(v,u) ),
    inference(res,[status(thm),theory(equality)],[1,12]),
    [iquote('0:Res:1.0,12.0')] ).

cnf(44,plain,
    ( ~ p2(f3(f4(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(c12)))))))))))))))))),u)
    | ~ p2(f7(c11),v)
    | p10(v,u) ),
    inference(res,[status(thm),theory(equality)],[16,14]),
    [iquote('0:Res:16.0,14.0')] ).

cnf(58,plain,
    p2(f3(f4(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(f5(c12)))))))))))))))))),f7(c11)),
    inference(res,[status(thm),theory(equality)],[15,19]),
    [iquote('0:Res:15.0,19.0')] ).

cnf(640,plain,
    ( ~ p2(f7(c11),u)
    | p10(u,f7(c11)) ),
    inference(res,[status(thm),theory(equality)],[58,44]),
    [iquote('0:Res:58.0,44.0')] ).

cnf(643,plain,
    ~ p2(f7(c11),f7(c11)),
    inference(res,[status(thm),theory(equality)],[640,3]),
    [iquote('0:Res:640.1,3.0')] ).

cnf(645,plain,
    $false,
    inference(mrr,[status(thm)],[643,1]),
    [iquote('0:MRR:643.0,1.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SYN562-1 : TPTP v8.1.0. Released v2.5.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.13/0.34  % Computer : n014.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Mon Jul 11 15:39:34 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.35/0.51  
% 0.35/0.51  SPASS V 3.9 
% 0.35/0.51  SPASS beiseite: Proof found.
% 0.35/0.51  % SZS status Theorem
% 0.35/0.51  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.35/0.51  SPASS derived 622 clauses, backtracked 0 clauses, performed 0 splits and kept 461 clauses.
% 0.35/0.51  SPASS allocated 63571 KBytes.
% 0.35/0.51  SPASS spent	0:00:00.15 on the problem.
% 0.35/0.51  		0:00:00.04 for the input.
% 0.35/0.51  		0:00:00.00 for the FLOTTER CNF translation.
% 0.35/0.51  		0:00:00.01 for inferences.
% 0.35/0.51  		0:00:00.00 for the backtracking.
% 0.35/0.51  		0:00:00.08 for the reduction.
% 0.35/0.51  
% 0.35/0.51  
% 0.35/0.51  Here is a proof with depth 4, length 12 :
% 0.35/0.51  % SZS output start Refutation
% See solution above
% 0.35/0.51  Formulae used in the proof : p2_1 not_p10_3 p2_12 p10_14 p2_15 p10_16
% 0.35/0.51  
%------------------------------------------------------------------------------