TSTP Solution File: SYN540+1 by DarwinFM---1.4.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : DarwinFM---1.4.5
% Problem  : SYN540+1 : TPTP v8.1.0. Released v2.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Thu Jul 21 03:59:18 EDT 2022

% Result   : CounterSatisfiable 0.47s 0.67s
% Output   : FiniteModel 0.47s
% Verified : 
% SZS Type : FiniteModel
%            Domain size           :    2

% Comments : 
%------------------------------------------------------------------------------
fof(interpretation_domain,fi_domain,
    ! [X] :
      ( X = e1
      | X = e2 ) ).

fof(interpretation_domain_distinct,fi_domain,
    e1 != e2 ).

fof(interpretation_terms,fi_functors,
    ( a681 = e1
    & a682 = e1
    & a683 = e1
    & a684 = e1
    & a685 = e1
    & a686 = e1
    & a687 = e1
    & a688 = e1
    & a689 = e1
    & a690 = e2
    & a691 = e1
    & a692 = e2
    & a693 = e1
    & a694 = e2
    & a695 = e1
    & a696 = e1
    & a697 = e1
    & a698 = e1
    & a699 = e1
    & a700 = e1
    & a701 = e1
    & a702 = e2
    & a703 = e1
    & a704 = e1
    & a705 = e1
    & a706 = e1
    & a707 = e1
    & a708 = e1
    & a709 = e1
    & a710 = e1
    & a711 = e1
    & a712 = e1
    & a713 = e1
    & a714 = e1
    & a715 = e1
    & a716 = e1
    & a717 = e1
    & a718 = e1
    & a719 = e1
    & a720 = e1
    & a721 = e1
    & a722 = e1
    & a723 = e2
    & a724 = e1 ) ).

fof(interpretation_atoms,fi_predicates,
    ( ( c1_0
    <=> $false )
    & ! [X0] :
        ( c1_1(X0)
      <=> X0 = e1 )
    & ! [X0,X1] :
        ( c1_2(X0,X1)
      <=> ( X0 = e2
          | X1 = e1 ) )
    & c2_0
    & ! [X0] :
        ( c2_1(X0)
      <=> $false )
    & ! [X0,X1] :
        ( c2_2(X0,X1)
      <=> ( X0 = e2
          | ( X0 = e1
            & X1 = e2 ) ) )
    & ( c3_0
    <=> $false )
    & ! [X0] :
        ( c3_1(X0)
      <=> X0 = e1 )
    & ! [X0,X1] :
        ( c3_2(X0,X1)
      <=> ( X0 = e1
          & X1 = e2 ) )
    & ( c4_0
    <=> $false )
    & ! [X0] :
        ( c4_1(X0)
      <=> X0 = e1 )
    & ! [X0,X1] :
        ( c4_2(X0,X1)
      <=> X0 = e2 )
    & c5_0
    & ! [X0] : c5_1(X0)
    & ! [X0,X1] :
        ( c5_2(X0,X1)
      <=> ( X0 = e1
          & X1 = e1 ) )
    & ndr1_0
    & ! [X0] : ndr1_1(X0) ) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.11  % Problem  : SYN540+1 : TPTP v8.1.0. Released v2.1.0.
% 0.10/0.12  % Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s
% 0.13/0.33  % Computer : n017.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % DateTime : Tue Jul 12 06:40:34 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.13/0.33  Defaulting to tptp format.
% 0.47/0.67  SZS status CounterSatisfiable for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.47/0.67  
% 0.47/0.67  MODEL (TPTP):
% 0.47/0.67  SZS output start FiniteModel for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
%------------------------------------------------------------------------------