TSTP Solution File: SYN503-1 by Gandalf---c-2.6

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Gandalf---c-2.6
% Problem  : SYN503-1 : TPTP v3.4.2. Released v2.1.0.
% Transfm  : add_equality:r
% Format   : otter:hypothesis:set(auto),clear(print_given)
% Command  : gandalf-wrapper -time %d %s

% Computer : art10.cs.miami.edu
% Model    : i686 unknown
% CPU      : Intel(R) Pentium(R) 4 CPU 2.80GHz @ 2793MHz
% Memory   : 1000MB
% OS       : Linux 2.4.22-21mdk-i686-up-4GB
% CPULimit : 600s

% Result   : Timeout 607.7s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 
% Gandalf c-2.6 r1 starting to prove: /home/graph/tptp/TSTP/PreparedTPTP/otter:hypothesis:set(auto),clear(print_given)---add_equality:r/SYN/SYN503-1+noeq.in
% Using automatic strategy selection.
% Time limit in seconds: 600
% 
% prove-all-passes started
% 
% detected problem class: nne
% detected subclass: big
% 
% strategies selected: 
% (hyper 30 #f 1 19)
% (binary-unit 30 #f 1 19)
% (binary-double 18 #f 1 19)
% (binary 90 #t 1 19)
% (binary-order 30 #f 1 19)
% (binary-posweight-order 54 #f)
% (binary-order-sos 30 #t)
% (binary-unit-uniteq 30 #f)
% (binary-weightorder 30 #f)
% (binary-weightorder-sos 30 #f)
% (binary-order 30 #f)
% (hyper-order 30 #f)
% (binary 168 #t)
% 
% 
% SOS clause 
% -c1_1(X) | -c2_1(X) | -c3_1(X) | -ndr1_0(0) | -c0_1(Y) | -c2_1(Y) | -c3_1(Y) | -c0_1(Z) | -c1_1(Z) | -c2_1(Z).
% was split for some strategies as: 
% -c0_1(Z) | -c1_1(Z) | -c2_1(Z).
% -c0_1(Y) | -c2_1(Y) | -c3_1(Y).
% -c1_1(X) | -c2_1(X) | -c3_1(X).
% -ndr1_0(0).
% 
% Starting a split proof attempt with 4 components.
% 
% Split component 1 started.
% 
% START OF PROOFPART
% Making new sos for split:
% Original clause to be split: 
% -c1_1(X) | -c2_1(X) | -c3_1(X) | -ndr1_0(0) | -c0_1(Y) | -c2_1(Y) | -c3_1(Y) | -c0_1(Z) | -c1_1(Z) | -c2_1(Z).
% Split part used next: -c0_1(Z) | -c1_1(Z) | -c2_1(Z).
% Wow, gandalf-wrapper got a signal XCPU
% END OF PROOFPARTXcpu signal caught by Gandalf: stopping
% 
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