TSTP Solution File: SYN415+1 by SPASS---3.9
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- Process Solution
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% File : SPASS---3.9
% Problem : SYN415+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n023.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:21:12 EDT 2022
% Result : Theorem 0.19s 0.43s
% Output : Refutation 0.19s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYN415+1 : TPTP v8.1.0. Released v2.0.0.
% 0.12/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n023.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Tue Jul 12 04:42:54 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.19/0.43
% 0.19/0.43 SPASS V 3.9
% 0.19/0.43 SPASS beiseite: Proof found.
% 0.19/0.43 % SZS status Theorem
% 0.19/0.43 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.43 SPASS derived 66 clauses, backtracked 29 clauses, performed 4 splits and kept 53 clauses.
% 0.19/0.43 SPASS allocated 103846 KBytes.
% 0.19/0.43 SPASS spent 0:00:00.08 on the problem.
% 0.19/0.43 0:00:00.04 for the input.
% 0.19/0.43 0:00:00.02 for the FLOTTER CNF translation.
% 0.19/0.43 0:00:00.00 for inferences.
% 0.19/0.43 0:00:00.00 for the backtracking.
% 0.19/0.43 0:00:00.00 for the reduction.
% 0.19/0.43
% 0.19/0.43
% 0.19/0.43 Here is a proof with depth 3, length 38 :
% 0.19/0.43 % SZS output start Refutation
% 0.19/0.43 1[0:Inp] || -> f(skc7)*.
% 0.19/0.43 2[0:Inp] || -> f(skc6)*.
% 0.19/0.43 3[0:Inp] || -> f(skc4)*.
% 0.19/0.43 4[0:Inp] || -> f(skf1(u))*.
% 0.19/0.43 6[0:Inp] f(u) || -> SkC0* equal(skc4,u)*.
% 0.19/0.43 7[0:Inp] f(u) || equal(skc7,skc6) -> SkC0*.
% 0.19/0.43 8[0:Inp] f(u) || SkC0 equal(skf1(u),u)** -> .
% 0.19/0.43 9[0:Inp] f(u) f(v) || SkC0*+ -> equal(v,u)*.
% 0.19/0.43 15[1:Spt:9.0,9.1,9.3] f(u) f(v) || -> equal(v,u)*.
% 0.19/0.43 16[2:Spt:6.0,6.2] f(u) || -> equal(skc4,u)*.
% 0.19/0.43 17[3:Spt:8.0,8.2] f(u) || equal(skf1(u),u)** -> .
% 0.19/0.43 19[1:EmS:15.0,3.0] f(u) || -> equal(u,skc4)*.
% 0.19/0.43 23[2:EmS:16.0,2.0] || -> equal(skc6,skc4)**.
% 0.19/0.43 30[2:EmS:16.0,1.0] || -> equal(skc7,skc4)**.
% 0.19/0.43 47[2:EmS:16.0,4.0] || -> equal(skf1(u),skc4)**.
% 0.19/0.43 50[3:Rew:47.0,17.1] f(u) || equal(skc4,u)* -> .
% 0.19/0.43 58[3:EmS:50.0,3.0] || equal(skc4,skc4)* -> .
% 0.19/0.43 59[3:Obv:58.0] || -> .
% 0.19/0.43 60[3:Spt:59.0,8.1] || SkC0* -> .
% 0.19/0.43 61[2:Rew:30.0,7.1,23.0,7.1] f(u) || equal(skc4,skc4) -> SkC0*.
% 0.19/0.43 62[2:Obv:61.1] f(u) || -> SkC0*.
% 0.19/0.43 63[3:MRR:62.1,60.0] f(u) || -> .
% 0.19/0.43 64[3:UnC:63.0,3.0] || -> .
% 0.19/0.43 65[2:Spt:64.0,6.1] || -> SkC0*.
% 0.19/0.43 67[2:MRR:8.1,65.0] f(u) || equal(skf1(u),u)** -> .
% 0.19/0.43 76[1:EmS:19.0,4.0] || -> equal(skf1(u),skc4)**.
% 0.19/0.43 88[2:Rew:76.0,67.1] f(u) || equal(skc4,u)* -> .
% 0.19/0.43 93[2:EmS:88.0,3.0] || equal(skc4,skc4)* -> .
% 0.19/0.43 94[2:Obv:93.0] || -> .
% 0.19/0.43 95[1:Spt:94.0,9.2] || SkC0* -> .
% 0.19/0.43 96[1:MRR:6.1,95.0] f(u) || -> equal(skc4,u)*.
% 0.19/0.43 97[1:MRR:7.2,95.0] f(u) || equal(skc7,skc6)** -> .
% 0.19/0.43 99[1:EmS:96.0,2.0] || -> equal(skc6,skc4)**.
% 0.19/0.43 100[1:EmS:96.0,1.0] || -> equal(skc7,skc4)**.
% 0.19/0.43 103[1:Rew:99.0,97.1] f(u) || equal(skc7,skc4)** -> .
% 0.19/0.43 106[1:Rew:100.0,103.1] f(u) || equal(skc4,skc4)* -> .
% 0.19/0.43 107[1:Obv:106.1] f(u) || -> .
% 0.19/0.43 108[1:UnC:107.0,3.0] || -> .
% 0.19/0.43 % SZS output end Refutation
% 0.19/0.43 Formulae used in the proof : kalish317
% 0.19/0.43
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