TSTP Solution File: SYN413+1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYN413+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n025.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:11:41 EDT 2023
% Result : Theorem 3.38s 3.66s
% Output : Proof 3.38s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYN413+1 : TPTP v8.1.2. Released v2.0.0.
% 0.13/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n025.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 20:00:53 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.38/3.66 SZS status Theorem for theBenchmark.p
% 3.38/3.66 SZS output start Proof for theBenchmark.p
% 3.38/3.66 Clause #0 (by assumption #[]): Eq
% 3.38/3.66 (Not
% 3.38/3.66 ((∀ (Z : Iota), Exists fun Y => ∀ (X : Iota), Iff (f X Y) (And (f X Z) (Not (f X X)))) →
% 3.38/3.66 Not (Exists fun V => ∀ (U : Iota), f U V)))
% 3.38/3.66 True
% 3.38/3.66 Clause #1 (by clausification #[0]): Eq
% 3.38/3.66 ((∀ (Z : Iota), Exists fun Y => ∀ (X : Iota), Iff (f X Y) (And (f X Z) (Not (f X X)))) →
% 3.38/3.66 Not (Exists fun V => ∀ (U : Iota), f U V))
% 3.38/3.66 False
% 3.38/3.66 Clause #2 (by clausification #[1]): Eq (∀ (Z : Iota), Exists fun Y => ∀ (X : Iota), Iff (f X Y) (And (f X Z) (Not (f X X)))) True
% 3.38/3.66 Clause #3 (by clausification #[1]): Eq (Not (Exists fun V => ∀ (U : Iota), f U V)) False
% 3.38/3.66 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (Exists fun Y => ∀ (X : Iota), Iff (f X Y) (And (f X a) (Not (f X X)))) True
% 3.38/3.66 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (∀ (X : Iota), Iff (f X (skS.0 0 a a_1)) (And (f X a) (Not (f X X)))) True
% 3.38/3.66 Clause #6 (by clausification #[5]): ∀ (a a_1 a_2 : Iota), Eq (Iff (f a (skS.0 0 a_1 a_2)) (And (f a a_1) (Not (f a a)))) True
% 3.38/3.66 Clause #7 (by clausification #[6]): ∀ (a a_1 a_2 : Iota), Or (Eq (f a (skS.0 0 a_1 a_2)) True) (Eq (And (f a a_1) (Not (f a a))) False)
% 3.38/3.66 Clause #8 (by clausification #[6]): ∀ (a a_1 a_2 : Iota), Or (Eq (f a (skS.0 0 a_1 a_2)) False) (Eq (And (f a a_1) (Not (f a a))) True)
% 3.38/3.66 Clause #9 (by clausification #[7]): ∀ (a a_1 a_2 : Iota), Or (Eq (f a (skS.0 0 a_1 a_2)) True) (Or (Eq (f a a_1) False) (Eq (Not (f a a)) False))
% 3.38/3.66 Clause #10 (by clausification #[9]): ∀ (a a_1 a_2 : Iota), Or (Eq (f a (skS.0 0 a_1 a_2)) True) (Or (Eq (f a a_1) False) (Eq (f a a) True))
% 3.38/3.66 Clause #11 (by clausification #[3]): Eq (Exists fun V => ∀ (U : Iota), f U V) True
% 3.38/3.66 Clause #12 (by clausification #[11]): ∀ (a : Iota), Eq (∀ (U : Iota), f U (skS.0 1 a)) True
% 3.38/3.66 Clause #13 (by clausification #[12]): ∀ (a a_1 : Iota), Eq (f a (skS.0 1 a_1)) True
% 3.38/3.66 Clause #14 (by superposition #[13, 10]): ∀ (a a_1 a_2 : Iota), Or (Eq (f a (skS.0 0 (skS.0 1 a_1) a_2)) True) (Or (Eq True False) (Eq (f a a) True))
% 3.38/3.66 Clause #15 (by clausification #[8]): ∀ (a a_1 a_2 : Iota), Or (Eq (f a (skS.0 0 a_1 a_2)) False) (Eq (Not (f a a)) True)
% 3.38/3.66 Clause #17 (by clausification #[15]): ∀ (a a_1 a_2 : Iota), Or (Eq (f a (skS.0 0 a_1 a_2)) False) (Eq (f a a) False)
% 3.38/3.66 Clause #18 (by clausification #[14]): ∀ (a a_1 a_2 : Iota), Or (Eq (f a (skS.0 0 (skS.0 1 a_1) a_2)) True) (Eq (f a a) True)
% 3.38/3.66 Clause #22 (by superposition #[18, 17]): ∀ (a a_1 a_2 a_3 : Iota),
% 3.38/3.66 Or (Eq (f (skS.0 0 a a_1) (skS.0 0 (skS.0 1 a_2) a_3)) True) (Or (Eq True False) (Eq True False))
% 3.38/3.66 Clause #27 (by clausification #[22]): ∀ (a a_1 a_2 a_3 : Iota), Or (Eq (f (skS.0 0 a a_1) (skS.0 0 (skS.0 1 a_2) a_3)) True) (Eq True False)
% 3.38/3.66 Clause #28 (by clausification #[27]): ∀ (a a_1 a_2 a_3 : Iota), Eq (f (skS.0 0 a a_1) (skS.0 0 (skS.0 1 a_2) a_3)) True
% 3.38/3.66 Clause #29 (by superposition #[28, 17]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (f (skS.0 0 a a_1) (skS.0 0 a a_1)) False)
% 3.38/3.66 Clause #33 (by clausification #[29]): ∀ (a a_1 : Iota), Eq (f (skS.0 0 a a_1) (skS.0 0 a a_1)) False
% 3.38/3.66 Clause #34 (by superposition #[33, 28]): Eq False True
% 3.38/3.66 Clause #36 (by clausification #[34]): False
% 3.38/3.66 SZS output end Proof for theBenchmark.p
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