%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN406+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:11:40 EDT 2023

% Result   : Theorem 3.56s 3.73s
% Output   : Proof 3.56s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYN406+1 : TPTP v8.1.2. Released v2.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.16/0.34  % Computer : n020.cluster.edu
% 0.16/0.34  % Model    : x86_64 x86_64
% 0.16/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.34  % Memory   : 8042.1875MB
% 0.16/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.16/0.34  % CPULimit   : 300
% 0.16/0.34  % WCLimit    : 300
% 0.16/0.34  % DateTime   : Sat Aug 26 17:50:29 EDT 2023
% 0.16/0.34  % CPUTime    : 
% 3.56/3.73  SZS status Theorem for theBenchmark.p
% 3.56/3.73  SZS output start Proof for theBenchmark.p
% 3.56/3.73  Clause #0 (by assumption #[]): Eq (Not (And (∀ (X : Iota), f X → g X) (Exists fun Y => And (f Y) (h Y)) → Exists fun Z => And (g Z) (h Z))) True
% 3.56/3.73  Clause #1 (by clausification #[0]): Eq (And (∀ (X : Iota), f X → g X) (Exists fun Y => And (f Y) (h Y)) → Exists fun Z => And (g Z) (h Z)) False
% 3.56/3.73  Clause #2 (by clausification #[1]): Eq (And (∀ (X : Iota), f X → g X) (Exists fun Y => And (f Y) (h Y))) True
% 3.56/3.73  Clause #3 (by clausification #[1]): Eq (Exists fun Z => And (g Z) (h Z)) False
% 3.56/3.73  Clause #4 (by clausification #[2]): Eq (Exists fun Y => And (f Y) (h Y)) True
% 3.56/3.73  Clause #5 (by clausification #[2]): Eq (∀ (X : Iota), f X → g X) True
% 3.56/3.73  Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (And (f (skS.0 0 a)) (h (skS.0 0 a))) True
% 3.56/3.73  Clause #7 (by clausification #[6]): ∀ (a : Iota), Eq (h (skS.0 0 a)) True
% 3.56/3.73  Clause #8 (by clausification #[6]): ∀ (a : Iota), Eq (f (skS.0 0 a)) True
% 3.56/3.73  Clause #9 (by clausification #[5]): ∀ (a : Iota), Eq (f a → g a) True
% 3.56/3.73  Clause #10 (by clausification #[9]): ∀ (a : Iota), Or (Eq (f a) False) (Eq (g a) True)
% 3.56/3.73  Clause #11 (by superposition #[8, 10]): ∀ (a : Iota), Or (Eq (g (skS.0 0 a)) True) (Eq False True)
% 3.56/3.73  Clause #12 (by clausification #[3]): ∀ (a : Iota), Eq (And (g a) (h a)) False
% 3.56/3.73  Clause #13 (by clausification #[12]): ∀ (a : Iota), Or (Eq (g a) False) (Eq (h a) False)
% 3.56/3.73  Clause #14 (by clausification #[11]): ∀ (a : Iota), Eq (g (skS.0 0 a)) True
% 3.56/3.73  Clause #15 (by superposition #[14, 13]): ∀ (a : Iota), Or (Eq True False) (Eq (h (skS.0 0 a)) False)
% 3.56/3.73  Clause #16 (by clausification #[15]): ∀ (a : Iota), Eq (h (skS.0 0 a)) False
% 3.56/3.73  Clause #17 (by superposition #[16, 7]): Eq False True
% 3.56/3.73  Clause #18 (by clausification #[17]): False
% 3.56/3.73  SZS output end Proof for theBenchmark.p
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