TSTP Solution File: SYN403+1 by Etableau---0.67

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : SYN403+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 06:10:43 EDT 2022

% Result   : Theorem 0.19s 0.37s
% Output   : CNFRefutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    1
% Syntax   : Number of formulae    :    9 (   4 unt;   0 def)
%            Number of atoms       :   26 (   0 equ)
%            Maximal formula atoms :    6 (   2 avg)
%            Number of connectives :   24 (   7   ~;   4   |;   5   &)
%                                         (   0 <=>;   8  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    6 (   3 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-1 aty)
%            Number of functors    :    1 (   1 usr;   1 con; 0-0 aty)
%            Number of variables   :    2 (   0 sgn   2   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(kalish234,conjecture,
    ! [X1] :
      ( ( ( f(X1)
         => g(X1) )
        & ( g(X1)
         => h(X1) ) )
     => ( f(X1)
       => h(X1) ) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',kalish234) ).

fof(c_0_1,negated_conjecture,
    ~ ! [X1] :
        ( ( ( f(X1)
           => g(X1) )
          & ( g(X1)
           => h(X1) ) )
       => ( f(X1)
         => h(X1) ) ),
    inference(assume_negation,[status(cth)],[kalish234]) ).

fof(c_0_2,negated_conjecture,
    ( ( ~ f(esk1_0)
      | g(esk1_0) )
    & ( ~ g(esk1_0)
      | h(esk1_0) )
    & f(esk1_0)
    & ~ h(esk1_0) ),
    inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_1])])]) ).

cnf(c_0_3,negated_conjecture,
    ( g(esk1_0)
    | ~ f(esk1_0) ),
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_4,negated_conjecture,
    f(esk1_0),
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_5,negated_conjecture,
    ( h(esk1_0)
    | ~ g(esk1_0) ),
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_6,negated_conjecture,
    g(esk1_0),
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_3,c_0_4])]) ).

cnf(c_0_7,negated_conjecture,
    ~ h(esk1_0),
    inference(split_conjunct,[status(thm)],[c_0_2]) ).

cnf(c_0_8,negated_conjecture,
    $false,
    inference(sr,[status(thm)],[inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_5,c_0_6])]),c_0_7]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SYN403+1 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.13  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.12/0.34  % Computer : n008.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Tue Jul 12 04:40:38 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.19/0.37  # No SInE strategy applied
% 0.19/0.37  # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.19/0.37  # and selection function SelectComplexExceptUniqMaxHorn.
% 0.19/0.37  #
% 0.19/0.37  # Presaturation interreduction done
% 0.19/0.37  
% 0.19/0.37  # Proof found!
% 0.19/0.37  # SZS status Theorem
% 0.19/0.37  # SZS output start CNFRefutation
% See solution above
% 0.19/0.37  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------