TSTP Solution File: SYN401+1 by ePrincess---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : ePrincess---1.0
% Problem  : SYN401+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : ePrincess-casc -timeout=%d %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 05:02:09 EDT 2022

% Result   : Theorem 1.45s 0.99s
% Output   : Proof 2.05s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : SYN401+1 : TPTP v8.1.0. Released v2.0.0.
% 0.10/0.12  % Command  : ePrincess-casc -timeout=%d %s
% 0.12/0.33  % Computer : n012.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Mon Jul 11 23:59:27 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.18/0.57          ____       _                          
% 0.18/0.57    ___  / __ \_____(_)___  ________  __________
% 0.18/0.57   / _ \/ /_/ / ___/ / __ \/ ___/ _ \/ ___/ ___/
% 0.18/0.57  /  __/ ____/ /  / / / / / /__/  __(__  |__  ) 
% 0.18/0.57  \___/_/   /_/  /_/_/ /_/\___/\___/____/____/  
% 0.18/0.57  
% 0.18/0.57  A Theorem Prover for First-Order Logic
% 0.18/0.58  (ePrincess v.1.0)
% 0.18/0.58  
% 0.18/0.58  (c) Philipp Rümmer, 2009-2015
% 0.18/0.58  (c) Peter Backeman, 2014-2015
% 0.18/0.58  (contributions by Angelo Brillout, Peter Baumgartner)
% 0.18/0.58  Free software under GNU Lesser General Public License (LGPL).
% 0.18/0.58  Bug reports to peter@backeman.se
% 0.18/0.58  
% 0.18/0.58  For more information, visit http://user.uu.se/~petba168/breu/
% 0.18/0.58  
% 0.18/0.58  Loading /export/starexec/sandbox/benchmark/theBenchmark.p ...
% 0.65/0.62  Prover 0: Options:  -triggersInConjecture -genTotalityAxioms -tightFunctionScopes -clausifier=simple -reverseFunctionalityPropagation +boolFunsAsPreds -triggerStrategy=allMaximal -resolutionMethod=nonUnifying +ignoreQuantifiers -generateTriggers=all
% 1.16/0.81  Prover 0: Preprocessing ...
% 1.16/0.84  Prover 0: Warning: ignoring some quantifiers
% 1.16/0.86  Prover 0: Constructing countermodel ...
% 1.37/0.93  Prover 0: gave up
% 1.37/0.93  Prover 1: Options:  +triggersInConjecture -genTotalityAxioms -tightFunctionScopes -clausifier=simple +reverseFunctionalityPropagation -boolFunsAsPreds -triggerStrategy=maximal -resolutionMethod=normal +ignoreQuantifiers -generateTriggers=all
% 1.45/0.94  Prover 1: Preprocessing ...
% 1.45/0.97  Prover 1: Constructing countermodel ...
% 1.45/0.99  Prover 1: proved (63ms)
% 1.45/0.99  
% 1.45/0.99  No countermodel exists, formula is valid
% 1.45/0.99  % SZS status Theorem for theBenchmark
% 1.45/0.99  
% 1.45/0.99  Generating proof ... found it (size 5)
% 1.86/1.07  
% 1.86/1.07  % SZS output start Proof for theBenchmark
% 1.86/1.08  Assumed formulas after preprocessing and simplification: 
% 1.86/1.08  | (0)  ? [v0] :  ? [v1] : ( ~ (v1 = 0) & f(v0) = v1 &  ! [v2] :  ! [v3] :  ! [v4] : (v3 = v2 |  ~ (f(v4) = v3) |  ~ (f(v4) = v2)) &  ! [v2] :  ! [v3] : (v3 = 0 |  ~ (f(v2) = v3)))
% 2.05/1.13  | Instantiating (0) with all_0_0_0, all_0_1_1 yields:
% 2.05/1.13  | (1)  ~ (all_0_0_0 = 0) & f(all_0_1_1) = all_0_0_0 &  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (f(v2) = v1) |  ~ (f(v2) = v0)) &  ! [v0] :  ! [v1] : (v1 = 0 |  ~ (f(v0) = v1))
% 2.05/1.13  |
% 2.05/1.13  | Applying alpha-rule on (1) yields:
% 2.05/1.13  | (2)  ~ (all_0_0_0 = 0)
% 2.05/1.13  | (3) f(all_0_1_1) = all_0_0_0
% 2.05/1.13  | (4)  ! [v0] :  ! [v1] :  ! [v2] : (v1 = v0 |  ~ (f(v2) = v1) |  ~ (f(v2) = v0))
% 2.05/1.13  | (5)  ! [v0] :  ! [v1] : (v1 = 0 |  ~ (f(v0) = v1))
% 2.05/1.13  |
% 2.05/1.13  | Instantiating formula (5) with all_0_0_0, all_0_1_1 and discharging atoms f(all_0_1_1) = all_0_0_0, yields:
% 2.05/1.13  | (6) all_0_0_0 = 0
% 2.05/1.13  |
% 2.05/1.13  | Equations (6) can reduce 2 to:
% 2.05/1.13  | (7) $false
% 2.05/1.13  |
% 2.05/1.13  |-The branch is then unsatisfiable
% 2.05/1.13  % SZS output end Proof for theBenchmark
% 2.05/1.13  
% 2.05/1.13  546ms
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